XIV.

1. Her sister is more beautiful than her

2. English exercises is more difficult than Literature exercises

3. My new class is bigger tham my old class

4. Phi is more handsome than anybody in the class

5. Loan is taller than anyone in the family

IV.

3. French is not as difficult as English

4. That house is bigger than this house

5. A new house is more expensive than an old house

6. Yesterday is not as hot as today

7. My sister is taller than me

8. Girls are not as strong as boys

X.

1. Lesson 1 is not as long as Lesson 2

2. Ha Noi is smaller than HCM City

3. Old English is not as difficult as new French

4. Quang is not as thin as Quan

5. Your computer is more expensive than my computer

XI.

3. Minh is thinner than Hoang

4. Driving a motorbike is not as difficult as driving a car

XII.

1. Boys are stronger than girls

2. I am more intelligent than my sister

3. A new house is more expensive than an old house

4. English is more difficult than French

5. That river is longer than this river
6. New films are more interesting than old films 

XIII.

3. Quan is the most intelligent student in my school

4. HCM City is the biggest city in VN

Đề bài đây ạ 

`2x-2/3=1/2`

`2x=1/2+2/3`

`2x=7/6`

`x=7/6:2=7/12`

\(2x-\dfrac{2}{3}=\dfrac{1}{2}\Leftrightarrow2x=\dfrac{2}{3}+\dfrac{1}{2}=\dfrac{7}{6}\Leftrightarrow x=\dfrac{7}{6}:2=\dfrac{7}{12}\)

2x - 2/3 = 1/2

2x = 1/2 + 2/3 = 7/6

x = 7/6 : 2 = 7/12

vậy x = 7/12

lỗi

lỗi

Lỗi rồi bạn ơi

\(\dfrac{4}{7}+\dfrac{2}{9}+\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{7}{9}+\dfrac{75}{100}\\ =\dfrac{4}{7}+\dfrac{2}{9}+\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{7}{9}+\dfrac{3}{4}\\ =\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\\ =\dfrac{7}{7}+\dfrac{9}{9}+\dfrac{4}{4}\\ =1+1+1\\ =3\)

Ta có: \(\dfrac{7}{11}=\dfrac{7\times3}{11\times3}=\dfrac{21}{33};\dfrac{8}{11}=\dfrac{8\times3}{11\times3}=\dfrac{24}{33}\)

2 phân số giữa là: \(\dfrac{22}{33};\dfrac{23}{33}\)

\(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)=1+1+1=3\)

(\(\dfrac{4}{7}\)+\(\dfrac{3}{7}\))+(\(\dfrac{2}{9}\)+\(\dfrac{7}{9}\))+(\(\dfrac{1}{4}\)+\(\dfrac{75}{100}\))

=1+1+1

=3

Bài 8:

1: =>x+1+3 chia hết cho x+1

=>\(x+1\in\left\{1;-1;3;-3\right\}\)

=>\(x\in\left\{0;-2;2;-4\right\}\)

2: =>2x+2-5 chia hết cho x+1

=>\(x+1\in\left\{1;-1;5;-5\right\}\)

=>\(x\in\left\{0;-2;4;-6\right\}\)

3: =>2x-2+3 chia hết cho x-1

=>\(x-1\in\left\{1;-1;3;-3\right\}\)

=>\(x\in\left\{2;0;4;-2\right\}\)

4: =>4x+1 chia hết cho 2x-3

=>4x-6+7 chia hết cho 2x-3

=>\(2x-3\in\left\{1;-1;7;-7\right\}\)

=>\(x\in\left\{2;1;5;-2\right\}\)

a: Xét tứ giác AOBM có

góc OAM+góc OBM=180 độ

=>AOBM nội tiếp

b: \(cosAOM=\dfrac{OA}{OM}=\dfrac{1}{3}\)

nên \(\widehat{AOM}\simeq71^0\)

=>\(\widehat{AOB}\simeq142^0\)

=>sđ cung nhỏ AB là 142 độ; sđ cung lơn AB=360-142=218 độ

c:

Xét (O) có

ΔBAC nội tiếp

BC là đường kính

=>ΔBAC vuông tại A

=>BA vuông góc AC

Xét(O) có

MA,MB là tiêp tuyến

nên MA=MB

mà OA=OB

nên OM là trung trực của AB

=>OM//AC

góc ACB=góc OAC

góc OAC=góc AOM

=>góc ACB=góc AOM=góc BOM

d: góc DOM+góc BOM=90 độ

góc DMO+góc AOM=90 độ

mà góc BOM=góc AOM

nên góc DOM=góc DMO

=>DO=DM

\(Ba\left(NO_3\right)_2+H_2SO_4\rightarrow2HNO_3+BaSO_4\downarrow\)

\(CaCO_3+HNO_3\rightarrow Ca\left(NO_3\right)_2+CO_2\uparrow+H_2O\)

\(3AgNO_3+H_3PO_4\rightarrow AgPO_4\downarrow+HNO_3\)

Anh thấy PTHH đầu 2 chất kết tủa không hợp lí nhá. Em coi lại đề có phải 1 kết tủa 1 bay hơi không nha