Điền các từ sau vào chỗ trống:

play, dance, be, use, have, go, ride, collect, spend, jump

1. She used to __play___ with dolls when she was a child.

2. They didn't use to _play___ any sports.

3. He didn't use to __have___ a scrapbook.

4. When they were younger, they used to _go__ to the beach, ride a bike and collect comics.

5. I used to _be___ very shy, but I am not anymore.

6. After school, my friend and I used to __play__ chess and hide - and - seek.

7. I used to __spend__ my vacation in a summer camp with my friends.

8. I used to _have___ a pet when I was 5 years old. Now I don't have it anymore.

Điền các từ sau vào chỗ trống:

play, dance, be, use, have, go, ride, collect, spend, jump

1. She used to _play____ with dolls when she was a child.

2. They didn't use to ___play_ any sports.

3. He didn't use to _use__ a scrapbook.

4. When they were younger, they used to __go_ to the beach, ride a bike and collect comics.

5. I used to __be__ very shy, but I am not anymore.

6. After school, my friend and I used to __play__ chess and hide - and - seek.

7. I used to ___spend_ my vacation in a summer camp with my friends.

8. I used to __have_ a pet when I was 5 years old. Now I don't have it anymore.

hard hard

A = (2x-1)/(2x+1)

=>A=4x²-1

để A bé hơn 2

=>4x²-1<2

=>4x²<3

=>2x<\(\sqrt{3}\)

=>x<\(\frac{\sqrt{3}}{2}\)

làm ơn giúp em với

Bài 2: 

a: \(\Leftrightarrow12x-8x^2+8x^2-12x-8+12x=4\)

\(\Leftrightarrow12x=12\)

hay x=1

b: \(\Leftrightarrow\left(x-4\right)\left(x-3\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=3\\x=-3\end{matrix}\right.\)

a)2x( 2x-1) -(2x-1)

=(2x-1)(2x-1)

=(2x-1)²

b)2x( 4x + 2x + 1) - ( 4x + 2x +1)

=(2x-1)(4x+2x+1)

=(2x-1)(6x+1)

a) \(2x\left(2x-1\right)-\left(2x-1\right)=\left(2x-1\right)\left(2x-1\right)\)

b) \(2x\left(4x+2x+4\right)-\left(4x+2x+4\right)=\left(2x-1\right)\left(4x+2x+4\right)\)

Mik làm cho vui thôi chứ chẳng ai T mik đâu

Naruto lục đạo:làm thiếu chả ko T :D

1:

a: 5x(x^2-2x+1)

=5x*x^2-5x*2x+5x*1

=5x^3-10x^2+5x

b: \(M\left(x\right)+N\left(x\right)\)

=8x^2-2x+7+x^2+2x-9

=9x^2-2

c: C(x)=0

=>-3x+9=0

=>-3x=-9

=>x=3

2:

a: Xét ΔAMN và ΔAEP có

AM=AE

góc MAN=góc EAP

AN=AP

=>ΔAMN=ΔAEP

b: ΔAMN=ΔAEP

=>góc AMN=góc AEP

=>MN//EP

mà MN vuông góc MP

nên EP vuông góc MP

c: ΔMPN vuông tại M có MA là trung tuyến

nên MA=1/2NP

a: Sửa đề: (5-2x)(5+2x)+2x(x+3)=4-2x^2

=>25-4x^2+2x^2+6x=4-2x^2

=>6x+25=4

=>6x=-21

=>x=-7/2

b: (3x-2)(-2x)+5x^2=-x(x-3)

=>-6x^2+4x+5x^2=-x^2+3x

=>4x=3x

=>x=0

c: =>7-(4x^2-9)=x^2+8x+16

=>7-4x^2+9-x^2-8x-16=0

=>-5x^2-8x=0

=>5x^2+8x=0

=>x(5x+8)=0

=>x=0 hoặc x=-8/5