1084 +(942 -2x) :36 x44 =1434

=>(942 -2x) :36 x44 =1434 -1084

=>(942 -2x) :36 x44 = 350

=>(942 -2x) :36 =350 :44

=>(942 -2x) :36 =175 /22

=>(942 -2x)=175 /22x 36

=>(942 -2x)= 3150 /11

=>2x = 3150 /11-942

=>2x =-7212 /11

kết quả nè còn lại bn tự nghĩ nhé! -655,6363636

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\(1084+\left(942-2x\right)\div36\cdot44=1434\)

\(\left(942-2x\right)\div36\cdot44=1434-1084\)

\(\left(942-2x\right)\div36\cdot44=350\)

\(\left(942-2x\right)\div36=350\div44\)

\(\left(942-2x\right)\div36=\frac{175}{22}\)

\(942-2x=\frac{175}{22}\cdot36\)

\(942-2x=\frac{3150}{11}\)

\(2x=942-\frac{3150}{11}\)

\(2x=\frac{7212}{11}\)

\(\Rightarrow x=\frac{3606}{11}\)

b) 1084+(942-2x):16.14=1434

=>(942-2x):36.14=1434-1084

=>(942-2x):36.14=350

=>(942-2x):36=350:14

=>(942-2x):36=25

=>942-2x=25.36

=>942-2x=900

=>2x=942-900

=>2x=42

=>x=42:2

=>x=21

a) 14x+27x+13x=3888

=>(14+27+13)x=3888

=>54x=3888

=>x=3888:54

=>x=72

a)14x+27x+13x=3888

=(14+27+13)x=3888

=54x=3888

x=3888:54

x=72

b)1084+(942-2x):36.14=1434

=(942-2x):36.14=1434-1084

=(942-2x):36.14=350

=(942-2x):36=350:14

=(942-2x):36=25

=942-2x=25.36

=942-2x=900

=2x=942-900

=2x=42

x=42:2

x=21

$36 - 2x + 50 = x + 14$

$-3x = -72$

$x = 24$.

\(942\times112-942\times11-942\)

\(=942\times\left(112-11-1\right)\)

\(=942\times100\)

\(=94200\)

\(\dfrac{1}{3}\times\dfrac{14}{15}+\dfrac{14}{15}\times\dfrac{2}{3}\)

\(=\dfrac{14}{15}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)

\(=\dfrac{14}{15}\times\left(\dfrac{1+2}{3}\right)\)

\(=\dfrac{14}{15}\times\dfrac{3}{3}\)

\(=\dfrac{14}{15}\times1\)

\(=\dfrac{14}{15}\)

    942 \(\times\) 112 - 942 \(\times\) 11 - 942

= 942 \(\times\) 112 - 942 \(\times\) 11 - 942 \(\times\) 1

= 942 \(\times\) ( 112 - 11 - 1)

= 942 \(\times\) 100

= 94200

Tính ra thừa số nguyên tố

=373248.2916:1084

=1088391168:1084

=1004050,893

1) \(2x\left(x-3\right)+5x-15=0\)

\(2x\left(x-3\right)+5\left(x-3\right)=0\)

\(\left(x-3\right)\left(2x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-3=0\\2x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{-5}{2}\end{matrix}\right.\)

2) \(x\left(2x-7\right)-4x+14=0\)

\(x\left(2x-7\right)-2\left(2x-7\right)=0\)

\(\left(2x-7\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2x-7=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=2\end{matrix}\right.\)

3) \(x^2-12x+36=0\)

\(\left(x-6\right)^2=0\)

\(x-6=0\)

\(x=6\)

4) \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)-27=0\)

\(\left(x^3+3^3\right)-x\left(x^2-1\right)-27=0\)

\(x^3+27-x^3+x-27=0\)

\(x=0\)

a) 5 + 45(2x - 1) = 10

45(2x - 1) = 10 - 5

45(2x - 1) = 5

2x - 1 = 5 : 45

2x - 1 = 1/9

2x = 1/9 + 1

2x = 10/9

x = 10/9 : 2

x = 5/9

b) 54 : (2ˣ⁻³ + 1) + 3 = 9

54 : (2ˣ⁻³ + 1) = 9 - 3

54 : (2ˣ⁻³ + 1) = 6

2ˣ⁻³ + 1 = 54 : 6

2ˣ⁻³ + 1 = 9

2ˣ⁻³ = 9 - 1

2ˣ⁻³ = 8

2ˣ⁻³ = 2³

x - 3 = 3

x = 3 + 3

x = 6

c) 14 + 36 : 3ˣ⁻⁵ = 18

36 : 3ˣ⁻⁵ = 18 - 14

36 : 3ˣ⁻⁵ = 4

3ˣ⁻⁵ = 36 : 4

3ˣ⁻⁵ = 9

3ˣ⁻⁵ = 3²

x - 5 = 2

x = 2 + 5

x = 7

a: =>45(2x-1)=5

=>2x-1=1/9

=>2x=10/9

=>x=5/9

b: =>\(\dfrac{54}{2^{x-3}+1}=6\)

=>\(2^{x-3}+1=9\)

=>\(2^{x-3}=8\)

=>x-3=3

=>x=6

c: \(14+36:3^{x-5}=18\)

=>\(\dfrac{36}{3^{x-5}}=18-14=4\)

=>\(3^{x-5}=9\)

=>x-5=2

=>x=7