4Al+3O₂----t^o--->2Al₂O₃

Al₂O₃ +3H₂SO₄----->Al₂(SO₄)₃+3H₂O

Al₂(SO₄)₃+3BaCl₂------>2AlCl₃+3BaSO₄

2AlCl₃+3Ca(OH)₂---->2Al(OH)₃+3CaCl₂

Al(OH)₃+3HNO₃---->Al(NO₃)₃+3H₂O

2Al(NO₃)₃+3Mg----->3Mg(NO₃)₂+2Al

2Al+3H₂SO₄------->Al₂(SO₄)₃+3H₂

Al₂(SO₄)₃+3Ca(OH)₂------>2Al(OH)₃+3CaSO₄

2Al(OH)₃-----t^o----->Al₂O₃+3H₂O

2Al₂O₃----\(\dfrac{t^o}{criolit}\)---->4Al+3O₂

2Al+2H₂O+2NaOH------>2NaAlO₂+3H₂

4Al+3O₂\(\underrightarrow{t^o}\) 2Al₂O₃

Al₂O₃+H₂SO₄ —> Al₂(SO₄)₃+3H₂O

Al₂(SO₄)₃+3BaCl₂–>3BaSO₄\(\downarrow\)+2AlCl₃

AlCl₃+3NaOH—>Al(OH)₃\(\downarrow\)+3NaCl

Al(OH)₃+HNO₃ —>Al(NO₃)₃+NO₂\(\uparrow\)+H₂O

2Al(NO₃)₃+3Mg—>3Mg(NO₃)₂+2Al\(\downarrow\)

2Al+3H₂SO₄–>Al₂(SO₄)₃+3H₂\(\uparrow\)

Al₂(SO₄)₃+6NaOH—>2Al(OH)₃+3Na₂SO₄

2Al(OH)₃\(\underrightarrow{t^o}\)Al₂O₃+3H₂O

2Al₂O₃\(\xrightarrow[criolit]{đien.phan.nong.chay}\)

4Al+3O₂

2Al+2NaOH+2H₂O—>2NaAlO₂+3H₂

\(\begin{array}{l} 4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\uparrow\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{\text{đpnc, Criolit}} 4Al+3O_2\uparrow\\ 2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2\uparrow\end{array}\)

Câu hỏi là jz bạn? 

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)

\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)

\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)

\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)

1.2FeO  +     \(\dfrac{1}{2}\)O₂  →  Fe₂O₃

2.2Fe_xO­_y   +   \(\dfrac{3x-2y}{2}\)   O₂  →  xFe₂O₃

3.2Al +     6HCl  → 2AlCl₃ +       3H₂

4.Al₂O₃  +  3H₂SO₄  →  Al₂(SO₄)₃  +  3H₂O

5.Al(OH)₃   +     3HNO₃  →  Al(NO₃)₃   +       3H₂O

6. 2Al +             3H₂SO₄  →  Al₂(SO₄)₃ +         3H₂

7.2C4H10 + 13O2 → 8CO2 + 10H2O

8. 2KMnO₄  →  K₂MnO₄ +      MnO₂  +     O₂

9.2Cu(NO3)2 → 2CuO + 4NO2 + O2

10.M₂O_x    +        2xHNO₃  →  2M(NO₃)_x   +      xH₂O

11.Mg(OH)₂ +       2HNO₃  →  Mg(NO₃)₂ +     2H₂O

12.KClO₃  →  KCl   +   \(\dfrac{3}{2}\)O₂ 

13.CH4 + 2O2 → CO2 + 2H2O

14.xFe2O3 + (3x-2y)H2 → 2FexOy + (3x-2y)H2O

15.Fe₃O₄   +         8HCl  →  FeCl₂   +       2FeCl₃   +        4H₂O

D. Al₂(SO₄)₃

\(Al+2HCl->AlCl_2+H_2\)

\(AlCl_2+3NaOH->Al\left(OH\right)_3+3NaCl\)

Làm gì có \(AlCl_2\)?