\(x^2-6x+9=x^2-2.3x+3^2=\left(x-3\right)^2\)

\(\frac{1}{4}a^2+2ab^2+4b^4=\left(\frac{1}{2}a\right)^2+2.\frac{1}{2}a.2b^2+\left(2b\right)^2=\left(\frac{1}{2}a+2b\right)^2\)

\(25+10x+x^2=5^2+2.5x+x^2=\left(5+x\right)^2\)

\(\frac{1}{9}-\frac{2}{3}y^4+y^8=\left(\frac{1}{3}\right)^2-2.\frac{1}{3}y^4+\left(y^4\right)^2=\left(\frac{1}{3}-y^4\right)^2\)

a,(x-3)^2

b,(1/4x+2b^2)^2

c,(5+x)^2

d,(1/3-y^4)^2

sorry ,phần b fải là (1/2a+2b^2)^2

\(x^2-6x+9=\left(x-3\right)^2\)

\(\frac{1}{4}a^2+2ab+4b^2=\left(\frac{1}{2}a+b\right)^2\)

\(25+10x+x^2=\left(x+5\right)^2\)

\(\frac{1}{9}-\frac{2}{3}y^4+y^8=\left(y^4-\frac{1}{3}\right)^2\)

a) \(x^2-6x+9\)

\(=x^2-2.3x+3^2\)

\(=\left(x-3\right)^2\)

b) \(25+10x+x^2\)

\(=5^2+2.5x+x^2\)

\(=\left(5+x\right)^2\)

c) \(\frac{1}{9}-\frac{2}{3}y^4+y^8\)

\(=\left(\frac{1}{3}\right)^2-2.\frac{1}{3}x^4+\left(y^4\right)^2\)

\(=\left(\frac{1}{3}-x^4\right)^2\)

a) x² - 6x + 9

= x² - 2.3x + 3² 

= (x - 3)² 

a) 6xy^3+x^2y^6+9

= (xy^3 + 3)^2

b) x^4-2x^2y+y^2

= (x^2 - y)^2

c) x^6+25-10x^3

= (x^3 - 5)^2

a/ 6xy³+x²y⁶+9

= (xy³+3)² bình phương của 1 tổng;cttq: (A+B)²

b/ x⁴-2x²y+y²

= (x²-y)² bình phương của 1 hiệu; cttq (A-B)²

c/ x⁶+25-10x³

=(x³-5)²

Khó nhỉ

a) 25x² - 10xy + y²

= (5x)² - 2.5x.y + y²

= (5x - y)²

b) 4/9 x² + 20/3 xy + + 25y²

= (2/3 x)² + 2.2/3 x.5y + (5y)²

= (2/3 x + 5y)²

c) 9x² - 12x + 4

= (3x)² - 2.3x.2 + 2²

= (3x - 2)²

d) Sửa đề: 16u²v⁴ - 8uv² + 1

= (4uv²)² - 2.4uv².1 + 1²

= (4uv² - 1)²

chỉ cần giải mỗi c và d thui

giúp với sos

\(25x^2-10xy+y^2=\left(5x\right)^2-2.5x.y+y^2=\left(5x-y\right)^2\)

\(\dfrac{4}{9}x^2+\dfrac{20}{3}xy+25y^2=\left(\dfrac{2}{3}x\right)^2+2.\dfrac{2}{3}x.5y+\left(5y\right)^2=\left(\dfrac{2}{3}x+5y\right)^2\)

a) \(9x^2+6x+1=\left(3x+1\right)^2\)

b)\(x^2-x+\frac{1}{4}=\left(x-\frac{1}{2}\right)^2\)

c)\(x^2y^4-2xy^2+1=\left(xy^2-1\right)^2\)

d) \(x^2+\frac{2}{3}x+\frac{1}{9}=\left(x+\frac{1}{3}\right)^2\)

a) 9x² + 6x + 1 = ( 3x + 1 )²

b) x² - x + 1/4 = ( x - 1/2)²

c) x² . y⁴ - 2xy² + 1 = ( xy² - 1 ) ²

d) x² + 2/3x + 1/9 = (x+1/3)²

a) \(9x^2+6x+1\)

\(=\left(3x\right)^2+6x+1\)

\(=\left(3x+1\right)^2\)

b) \(x^2-x+\frac{1}{4}\)

\(=x^2-2x\frac{1}{2}+\frac{1}{2}-\frac{1}{2}+\frac{1}{4}\)

\(=\left(x-\frac{1}{2}\right)^2\)

c)  \(x^2y^4-2xy^2+1\)

.... Rút gọn lũy thừa cao

d ) Tương tự câu b . Làm theo cách thêm bớt

a) \(9x^2+6x+1=\left(3x\right)^2+2.3x.1+1^2=\left(3x+1\right)^2\)

b) \(x^2-x+\dfrac{1}{4}=x^2-2.\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)^2=\left(x-0,5\right)^2\)

c) \(x^2y^4-2xy^2+1=\left(xy^2\right)^2-2.xy^2.1+1^2=\left(xy^2-1\right)^2\)

d) \(x^2+\dfrac{2}{3}x+\dfrac{1}{9}=x^2+2.x.\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2=\left(x+\dfrac{1}{3}\right)^2\)

a) \(9x^2+6x+1\)

\(=\left(3x\right)^2+2.3x.1+1^2\)

\(=\left(3x+1\right)^2\)

b) \(x^2-x+\dfrac{1}{4}\)

\(=x^2-2.x.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2\)

\(=\left(x-\dfrac{1}{2}\right)^2\)