6^2:43+2.5^2
Tính:
6\(^2\) : 43 + 2.5\(^2\)
\(\frac{6^2}{43}=\frac{36}{43}\)
\(2.5^2=2.25=50\)
Vậy biểu thức có kết quả là:\(\frac{36}{43}+50\)
76-{2.[2.5^2-(31-2.3)]}
6^2.10:{780:[10^3-(2.5^3+35.14)]}
Mn ra đáp án nhanh hộ mình ạ
\(76-\left\{2\cdot\left[2\cdot5^2-\left(31-2\cdot3\right)\right]\right\}\)
\(=76-\left\{2\cdot\left[2\cdot25-\left(31-6\right)\right]\right\}\)
\(=75-\left[2\cdot\left(50-25\right)\right]\)
\(=76-\left(2\cdot25\right)\)
\(=76-50\)
\(=26\)
____________________
\(6^2\cdot10:\left\{780:\left[10^3-\left(2\cdot5^3+35\cdot14\right)\right]\right\}\)
\(=36\cdot10:\left\{780:\left[1000-\left(2\cdot125+490\right)\right]\right\}\)
\(=360:\left\{780:\left[1000-\left(250+490\right)\right]\right\}\)
\(=360:\left[780:\left(1000-740\right)\right]\)
\(=360:\left(780:260\right)\)
\(=360:3\)
\(=120\)
a: =76-{2*[2*25-31+6]}
=76-{2*[50-31+6]}
=76-2*25
=76-50=26
b: \(=360:\left\{\dfrac{780}{1000-2\cdot125-490}\right\}\)
\(=360:\dfrac{780}{260}\)
=360/3=120
62:4.3+2.52=?
62:4.3+2.52
=36:4.3+2.25
=9.3+50
=27+50
=77
Vậy GTBT=77
số đó là
77
ai k mình mình k
lại cho
mình ko nói dối nửa lời
(94,5)^2.(-2.5)^6\(-3.45)^5=?
tinh
62:4.3+2.52
62:4.3+2.52
= 36 : 4 . 3 + 2.25
= 9.3 + 50
= 27 + 50
= 77
Tìm x biết:
6^2.2^2.5:[3.12-(2x-6)]=2^3.5
\(6^2.2^2.5:\left[3.12-\left(2x-6\right)\right]=2^3.5\)
\(\Rightarrow36.4.5:\left[36-\left(2x-6\right)\right]=8.5\)
\(\Rightarrow720:\left[36-\left(2x-6\right)\right]=40\)
\(\Rightarrow36-\left(2x-6\right)=720:40=18\)
\(\Rightarrow2x-6=36-18=18\)
\(\Rightarrow2x=18+6=24\)
\(\Rightarrow x=24:2=12\)
\(\dfrac{6}{2.5}+\dfrac{2}{5.7}+\dfrac{6}{8.11}+...+\dfrac{6}{59.62}+\dfrac{6}{62.65}\)
giúp mình từng bước một nhé
Sửa đề: \(\dfrac{6}{2\cdot5}+\dfrac{6}{5\cdot8}+...+\dfrac{6}{62\cdot65}\)
\(=2\left(\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+...+\dfrac{3}{62\cdot65}\right)\)
=3(1/2-1/5+1/5-1/8+...+1/62-1/65)
=3*63/130=189/130
A=(1+2/1.4)x (1+2.5)x(1+3/6)x...x(1+2/100/103)
A=(1+2/1.4)x (1+2.5)x(1+3/6)x...x(1+2/100/103)
Ta có : (12+13+14+....+110)×x=19+28+....+82+91(12+13+14+....+110)×x=19+28+....+82+91
Đặt A=19+28+....+82+91A=19+28+....+82+91
=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)
=1+102+103+...+109=102+103+....+109+1010=1+102+103+...+109=102+103+....+109+1010
=(12+13+14+....+110)×10=(12+13+14+....+110)×10 (1)
Từ (1), suy ra:
(12+13+14+...+110)×x=(12+13+14+....+110)×10(12+13+14+...+110)×x=(12+13+14+....+110)×10
⇒x=10⇒x=10
Vậy x=10x=10
~ Học tốt ~
Ta có : (12+13+14+....+110)×x=19+28+....+82+91(12+13+14+....+110)×x=19+28+....+82+91
Đặt A=19+28+....+82+91A=19+28+....+82+91
=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)
=1+102+103+...+109=102+103+....+109+1010=1+102+103+...+109=102+103+....+109+1010
=(12+13+14+....+110)×10=(12+13+14+....+110)×10 (1)
Từ (1), suy ra:
(12+13+14+...+110)×x=(12+13+14+....+110)×10(12+13+14+...+110)×x=(12+13+14+....+110)×10
⇒x=10⇒x=10
Vậy x=10x=10
~ Học tốt ~