i) 5. 2\(^{x-2}\) +3.2x = 2\(^{2016}\) .17
k) (\(\frac{1}{2}\) -\(\frac{1}{6}\) ) . 3\(^{x+4}\) - 4.3x = 3\(^{16}\) - 4. 3\(^{13}\)
B. Tự luận
I: Đại số:
Bài 1: Thực hiện phép tính
1) 11/24 - 5/41 + 13/24 + 0,5 - 36/41
2) -12 : (3/4 - 5/6)^2
3) 7/23. [(-8/6) - 45/18]
4) \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5) (\(1+\frac{2}{3}-\frac{1}{4}\) ) (\(0,8\:-\frac{3}{4}\) )^2
6) 16\(\frac{2}{7}:\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
7) \((2^2:\frac{4}{3}-\frac{1}{2}\) ) . 6/5 - 17
8) (1/3)^50 .(-9)^25 -2/3:4
9) 3/5: ( -1/15 - 1/6 )+3/5:( -1/3 - 1\(\frac{1}{15}\) )
10) (-6,5).5,7+5,7.(-3,5)
11) 10.√0,01.√16/9+3√49-1/6√4
12) \(\frac{2⁴.2⁶}{\left(2⁵\right)^2}-\frac{2⁵.15^3}{6^3.10^2}\)
Bài 2. Tìm x, biết
1) x/12 - 5/6 = 1/12
2) 2/3 - 1\(\frac{4}{15}x=\frac{-3}{5}\)
3) -2^3 + 0,5x =1,5
Nhiêu đó thôi mik còn thiếu nhiều lắm
Bài 2:
1) \(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\)
\(\Rightarrow\frac{x}{12}=\frac{1}{12}+\frac{5}{6}\)
\(\Rightarrow\frac{x}{12}=\frac{11}{12}\)
\(\Rightarrow x.12=11.12\)
\(\Rightarrow x.12=132\)
\(\Rightarrow x=132:12\)
\(\Rightarrow x=11\)
Vậy \(x=11.\)
2) \(\frac{2}{3}-1\frac{4}{15}x=\frac{-3}{5}\)
\(\Rightarrow\frac{2}{3}-\frac{19}{15}x=\frac{-3}{5}\)
\(\Rightarrow\frac{19}{15}x=\frac{2}{3}+\frac{3}{5}\)
\(\Rightarrow\frac{19}{15}x=\frac{19}{15}\)
\(\Rightarrow x=\frac{19}{15}:\frac{19}{15}\)
\(\Rightarrow x=1\)
Vậy \(x=1.\)
3) \(\left(-2\right)^3+0,5x=1,5\)
\(\Rightarrow-8+0,5x=1,5\)
\(\Rightarrow0,5x=1,5+8\)
\(\Rightarrow0,5x=9,5\)
\(\Rightarrow x=9,5:0,5\)
\(\Rightarrow x=19\)
Vậy \(x=19.\)
Chúc bạn học tốt!
Tìm số nguyên x, nếu biết
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(\left(\frac{1}{3}+\frac{1}{6}\right)2^{x+4}-2^x=2^{13}-2^{10}\)
\(\left(\frac{1}{2}-\frac{1}{6}\right)3^{x+4}-4.3^x=3^{16}-4.3^{13}\)
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(5^{x+3}\left(5-3\right)=2.5^{11}\)
\(5^{x+3}.2=2.5^{11}\)
\(5^{x+3}=5^{11}\)
\(x+3=11\)
\(x=8\)
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(4^{x+1}\left(4^2-3\right)=13.4^{11}\)
\(4^{x+1}.13=13.4^{11}\)
\(4^{x+1}=4^{11}\)
\(x+1=11\)
\(x=10\)
1 . \(\frac{x-1}{12}-\frac{2x-12}{14}=\frac{3x-14}{25}-\frac{4x-25}{27}\)
2 . \(\frac{3}{x-1}+\frac{4}{x-2}=\frac{5}{x-3}+\frac{6}{x-4}\)
3 . \(\frac{2x-1}{2}+\frac{2x+1}{3}=\frac{2x+7}{6}+\frac{2x+9}{7}\)
4 . \(\frac{x^2+x+4}{2}+\frac{x^2+x+7}{3}=\frac{x^2+x+13}{5}+\frac{x^2+x+16}{6}\)
BÀI 1:Tính bằng cách hợp lý nhất: | BÀI 2:Tìm x biết:
a) 1\(\frac{4}{23}\)+\(\frac{5}{21}\)-\(\frac{4}{23}\)+0,5+\(\frac{16}{21}\) ; | a) |x+5|-6=9
b) \(23\frac{1}{4}\).\(\frac{7}{5}\)-13\(\frac{1}{4}\):\(\frac{5}{7}\) ; | b) \(\left(x-1\right)^2=25\)
c) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\) |
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BÀI 3:Tìm x biết:
a) \(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\) e) \(1\frac{1}{2}.x-4=0,5\)
b) \(\frac{2}{3}-1\frac{4}{15}x=\frac{-3}{5}\) f) 2x-1 =16
c) -23 +0.5x=1.5 g) (x-1)2 =25
d) \(\frac{\left(-3\right)^x}{81}=27\) h) |2x-1|=5
Tìm x biết :
a) \(\frac{1}{4}\) - \(\frac{1}{3}\)x = \(\frac{2}{5}\) - \(\frac{3}{2}\)x
b) 5 . \(2^{x-2}\) + 3 . \(2^x\) = \(2^{2016}\) . 17
c) ( \(\frac{1}{2}\) - \(\frac{1}{6}\) ) . \(3^{x+4}\) - 4 . \(3^x\) = \(3^{16}\) - 4 . \(3^{13}\)
Các bn ơi giúp mình với mình cảm trước nha
a)\(\frac{1}{4}-\frac{1}{3}x=\frac{2}{5}-\frac{3}{2}x\)
\(\Leftrightarrow\)\(\frac{15-20x}{60}=\frac{24-90x}{60}\)
\(\Leftrightarrow15-20x=24-90x\)
\(\Leftrightarrow-20x+90x=24-15\)
\(\Leftrightarrow70x=9\)
\(\Leftrightarrow x=\frac{9}{70}\)
c) (1/2-1/6)*3^x+4-4*3^x=3^16-4*3^13
=1/3*3^x*3^4-4*3^x=3^13*3^3-4*3^13
=27*3^x-4*3^x=3^13*(27-4)
=3^x*(27-4)=3^13*(27-4)
=>x=13
c, \(\frac{1}{3}\)x\(3^x\)x\(3^4\)-4x\(3^x\)=\(3^{16}\)-4x\(3^{13}\)
\(\Leftrightarrow\) \(3^3\)x\(3^x\)-4x\(3^x\)=\(3^3\)x\(3^{13}\)-4x\(3^{13}\)
\(\Leftrightarrow\) \(3^x\)x(\(3^3\)-4)=\(3^{13}\)x(\(3^3\)-4)
\(\Leftrightarrow\) \(3^x\)=\(3^{13}\)
\(\Leftrightarrow\) \(\chi\)=13
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}{5.\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}\right)}\)
\(=\frac{3}{5}+\frac{1}{\frac{5}{2}}\)
\(=\frac{3}{5}+\frac{2}{5}=1\)
b) B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6.8^4.3^5}-\frac{5^{10}.7^3:25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
\(=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{5^{10}.7^3-\left(5^2\right)^5.7^2}{\left(5^3\right)^3.7^3+5^9.\left(7.2\right)^3}\)
\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}-7^2}{5^9.7^3+5^9.7^3.2^3}\)
\(=\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5\left(3+1\right)}-\frac{5^{10}.7^2.\left(7-1\right)}{5^9.7^3\left(1+2^3\right)}\)
\(=\frac{1}{3.2}-\frac{5.2}{7.3}\)
\(=\frac{7}{3.2.7}-\frac{5.2.2}{7.3.2}\)
\(=\frac{7}{42}-\frac{20}{42}\)
\(=-\frac{13}{42}\)
cs ng làm đung r
đag định lm
BT2: Tim x
\(1.\left(3x+1\right)^2=25\)
\(2.\left[x-\frac{1}{2}\right]+\frac{1}{2}=\frac{5}{8}\)
\(3.\left[x+\frac{3}{4}\right]-\frac{1}{3}=0\)
\(4.\frac{1}{9}.3^4.3x=3^7\)
\(5.\frac{x}{5}=\frac{4}{21}\)
\(\left(3x+1\right)^2=25\)
\(\Rightarrow\left(3x+1\right)^2=5^2=\left(-5\right)^2\)
\(\Rightarrow\orbr{\begin{cases}3x+1=5\\3x+1=-5\end{cases}\Rightarrow\orbr{\begin{cases}3x=5-1=4\\3x=-5-1=-6\end{cases}}}\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-2\end{cases}}\)
\(\left[x-\frac{1}{2}\right]+\frac{1}{2}=\frac{5}{8}\)
\(\Rightarrow x-0=\frac{5}{8}\)
\(x=\frac{5}{8}\)
\(\left[x+\frac{3}{4}\right]-\frac{1}{3}=0\)
\(x+\frac{3}{4}=0+\frac{1}{3}=\frac{1}{3}\)
\(x=\frac{1}{3}-\frac{3}{4}\)
\(x=\frac{-5}{12}\)
\(\frac{1}{9}.3^4.3x=3^7\)
\(\Rightarrow\frac{1}{9}.3^5x=3^7\)
\(x=3^7:\frac{1}{9}:3^5\)
\(x=3^2.9\)
\(x=81\)
\(\frac{x}{5}=\frac{4}{21}\)
\(\Rightarrow21x=4.5\)
\(\Rightarrow x=\frac{4.5}{21}\)
\(x=\frac{20}{21}\)
bài 1:
a)\(\frac{1}{4}\)-\(\frac{1}{3}\)x =\(\frac{2}{5}\)-\(\frac{3}{2}\)x
b)5.x\(^{^{x-2}}\)+3.2\(^{^x}\)=2\(^{^{2016}}\).17
c) (\(\frac{1}{2}\)-\(\frac{1}{6}\)).3\(^{^{x+4}}\)-4.3\(^{^x}\)=3\(^{^{16}}\)-4.3\(^{^{13}}\)
Câu 1Tính giá trị biểu thức A biết
A=\(\frac{4+\frac{5}{6}-\frac{1}{9}}{10-\frac{7}{12}+\frac{1}{16}}-\frac{3-\frac{1}{5}+\frac{1}{3}-\frac{1}{9}}{9-\frac{3}{5}+1-\frac{1}{3}}\)
Câu 3 : Tìm x biết : 2016.x+x.\(\frac{1}{2016}\)-2016=\(\frac{1}{2016}\)
Câu 4 : Tìm tất cả các cặp số nguyên x,y biết rằng : (x-y).(y+3)2=9