Bài 7: Thực hiện phép tính:
a) \(\frac{5}{3}+\left(7+\frac{-5}{3}\right)\) b) A= -\(\frac{3}{5}\)+ (-\(\frac{2}{5}\)+2) c) \(\frac{-17}{13}+\){ \(\frac{25}{101}+\frac{4}{13}\)}
Những câu hỏi liên quan
Thực hiện phép tính:
a,\(16\frac{2}{7}:\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
b,\(\left(2^2:\frac{4}{3}-\frac{1}{2}\right)\cdot\frac{6}{5}-17\)
c,\(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
Ta có : \(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
=\(=\left(4.\frac{3}{4}-\frac{1}{2}\right).\frac{6}{5}-17\)
\(=\frac{5}{2}.\frac{6}{5}-17\)
\(=3-17=-14\)
Tụi quá mới lớp 5 thui
B1: Thực hiện phép tính :a, 11frac{3}{4}-(6frac{5}{6}-4frac{1}{2})+1frac{2}{3}b, 2frac{17}{20}-1frac{11}{5}+6frac{9}{20}:3c, 4frac{3}{7}:left(frac{7}{5}.4frac{3}{7}right)d, left(3frac{2}{9}.frac{15}{23}.1frac{7}{29}right):frac{5}{23}B2: Thực hiện phép tính:a,11frac{3}{4}-(6frac{5}{6}4frac{1}{2}+1frac{2}{3})
b,left(5frac{7}{8}-2frac{1}{4}-0,5right):frac{23}{26}c,left(17frac{13}{15}-3frac{3}{7}right)-left(2frac{12}{15}-4right)
d,2frac{2}{3}.frac{-4}{5}.0,375-left(-10right).frac{-15}{24}
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B1: Thực hiện phép tính :
a, \(11\frac{3}{4}-(6\frac{5}{6}-4\frac{1}{2})+1\frac{2}{3}\)
b, \(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)
c, \(4\frac{3}{7}:\left(\frac{7}{5}.4\frac{3}{7}\right)\)
d, \(\left(3\frac{2}{9}.\frac{15}{23}.1\frac{7}{29}\right):\frac{5}{23}\)
B2: Thực hiện phép tính:
\(a,11\frac{3}{4}-(6\frac{5}{6}4\frac{1}{2}+1\frac{2}{3})\\ b,\left(5\frac{7}{8}-2\frac{1}{4}-0,5\right):\frac{23}{26}\)
\(c,\left(17\frac{13}{15}-3\frac{3}{7}\right)-\left(2\frac{12}{15}-4\right)\\ d,2\frac{2}{3}.\frac{-4}{5}.0,375-\left(-10\right).\frac{-15}{24}\)
Bài 2: (3 đ) Thực hiện phép tính:
a)\(\left[4\frac{1}{9}+3\frac{1}{4}\right].2\frac{1}{4}+2\frac{3}{4}\)
b)\(1+\left[\frac{9}{4}+\frac{4}{5}\right]:3\frac{1}{6}\)
c)(-7+|13|)-(13-|-7|-25)-(25+|-10|-9)
2 Thực hiện phép tínhfrac{17}{9}-frac{17}{9}:left(frac{7}{3}+frac{1}{2}right)frac{4}{3}.frac{2}{5}-frac{3}{4}.frac{2}{5}-frac{3}{4}.5frac{3}{13}-0.75.frac{36}{13}3.left(-frac{4}{3}right)^2-frac{7}{3}-frac{5}{7}.frac{3}{11}+frac{-5}{7}.frac{8}{11}+3frac{5}{7}32frac{1}{7}:left(frac{-5}{4}right)-47frac{1}{7}:left(frac{-5}{4}right)left(frac{2}{3}+frac{1}{2}right)^2-frac{1}{12} frac{1}{4}-frac{5}{12}:frac{1}{6}+frac{-6}{5} frac{17}{21}+frac{5}{23}-frac{1}{2}+frac{4}{21}-1frac{5}{23}left(-3right)^2+sq...
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2 Thực hiện phép tính
\(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)
\(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)
\(-\frac{3}{4}.5\frac{3}{13}-0.75.\frac{36}{13}\)
\(3.\left(-\frac{4}{3}\right)^2-\frac{7}{3}\)
\(-\frac{5}{7}.\frac{3}{11}+\frac{-5}{7}.\frac{8}{11}+3\frac{5}{7}\)
\(32\frac{1}{7}:\left(\frac{-5}{4}\right)-47\frac{1}{7}:\left(\frac{-5}{4}\right)\)
\(\left(\frac{2}{3}+\frac{1}{2}\right)^2-\frac{1}{12}\\ \frac{1}{4}-\frac{5}{12}:\frac{1}{6}+\frac{-6}{5}\\ \frac{17}{21}+\frac{5}{23}-\frac{1}{2}+\frac{4}{21}-1\frac{5}{23}\)
\(\left(-3\right)^2+\sqrt{\frac{16}{25}}-\sqrt{9}+\frac{\sqrt{81}}{3}\)
a) \(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)
= \(\frac{17}{9}-\frac{17}{9}:\frac{17}{6}\)
= \(\frac{17}{9}-\frac{2}{3}\)
= \(\frac{11}{9}\)
b) \(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)
= \(\frac{2}{5}.\left(\frac{4}{3}-\frac{3}{4}\right)\)
= \(\frac{2}{5}.\frac{7}{12}\)
= \(\frac{7}{30}\)
Mình lười làm quá, hay mình nói kết quả cho bn thôi nha
c) -6
d) 3
e) 3
g) 12
h) \(\frac{23}{18}\)
i) \(\frac{-69}{20}\)
k) \(\frac{-1}{2}\)
l) \(\frac{49}{5}\)
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Tính:
a)\(A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right);\) b) \(B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\)
a)
\(\begin{array}{l}A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right)\\A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\frac{{ - 23}}{5}\\A = \frac{{5.\left( { - 3} \right).11.\left( { - 23} \right)}}{{11.23.5.5}}\\A = \frac{3}{5}\end{array}\)
b)
\(\begin{array}{l}B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\\B = \frac{{13}}{{25}}.\left( {\frac{{ - 7}}{9} - \frac{2}{9}} \right)\\B = \frac{{13}}{{25}}.(-1)\\B = \frac{{-13}}{{25}}.\end{array}\)
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Thực hiện phép tính:
\(M=\frac{-1,2:\left(1\frac{3}{5}.1.25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-\frac{9}{4}.\frac{36}{17}\right)}+0,6.0,5:\frac{2}{5}\)
Thực hiện phép tính:
A=\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
B=1\(\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right):\frac{7}{5}\)
A=3/4
B=29/35
mình nghĩ thế
Sai thôi nhé!
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\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)
\(A=1+\frac{1}{2}\)
\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)
\(A=\frac{3}{2}\)
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Bài 2: Thực hiện phép tính:
a)\((4\frac{1}{9}+3\frac{1}{4}).2\frac{1}{4}+2\frac{3}{4}\)
b) \(1+(\frac{9}{10}-\frac{4}{5})\div3\frac{1}{6}\)
c) \((-7+|13|)-\left(13-|-7|-25\right)-\left(25-|-10|-9\right)\)
a) \(\left(4\frac{1}{9}+3\frac{1}{4}\right)\cdot2\frac{1}{4}+2\frac{3}{4}\)
\(=7\frac{13}{36}\cdot2\frac{1}{4}+2\frac{3}{4}\)
\(=16\frac{9}{16}+2\frac{3}{4}\)
\(=19\frac{5}{16}\)
b)\(1+\left(\frac{9}{10}-\frac{4}{5}\right)\div3\frac{1}{6}\)
\(=1+\frac{1}{10}\div\frac{19}{6}\)
\(=1+\frac{3}{95}=1\frac{3}{95}\)
MK LÀM CHO BẠN 2 Ý THÔI NHA.
K MK NHA. CHÚC BN HỌC TỐT. ^_^
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c) \(\left(-7+|13|\right)-\left(13-|-7|-25\right)-\left(25-|-10|-9\right)\)
\(=-7+13-13+7+25-25+10+9\)
\(=\left(-7+7\right)+\left(13-13\right)+\left(25-25\right)+10+9\)
\(=0+0+0+10+9=10+9=19\)
MK LÀM XONG RỒI. K MK NHA. KB
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Bài 1:Thực hiện các phép tínha)A1-frac{1}{1+frac{2}{1-frac{3}{1-4}}}b)B-frac{1}{10}-frac{1}{100}-frac{1}{1000}-frac{1}{10000}-frac{1}{100000}-frac{1}{1000000}Bài 2:Thực hiện các phép tính sau 1 cách hợp lýa)Afrac{frac{3}{7}-frac{3}{17}+frac{3}{37}}{frac{5}{7}-frac{5}{17}+frac{5}{37}}+frac{frac{1}{2}-frac{1}{3}+frac{1}{4}-frac{1}{5}}{frac{7}{5}-frac{7}{4}+frac{7}{3}-frac{7}{2}}b)Bfrac{frac{2}{39}-frac{1}{15}-frac{2}{153}}{frac{1}{34}+frac{3}{20}-frac{3}{26}}:frac{1+frac{2}{71}-frac{5}{121}}{frac{...
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Bài 1:Thực hiện các phép tính
a)A=\(1-\frac{1}{1+\frac{2}{1-\frac{3}{1-4}}}\)
b)B=\(-\frac{1}{10}-\frac{1}{100}-\frac{1}{1000}-\frac{1}{10000}-\frac{1}{100000}-\frac{1}{1000000}\)
Bài 2:Thực hiện các phép tính sau 1 cách hợp lý
a)A=\(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\)
b)B=\(\frac{\frac{2}{39}-\frac{1}{15}-\frac{2}{153}}{\frac{1}{34}+\frac{3}{20}-\frac{3}{26}}:\frac{1+\frac{2}{71}-\frac{5}{121}}{\frac{65}{121}-\frac{26}{71}-13}\)
c)C=\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
d)D=\(\frac{2.2016}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2016}}\)
e)E=\(-1-\frac{1}{3}-\frac{1}{6}-\frac{1}{10}-\frac{1}{15}-...-\frac{1}{1225}\)
Thực hiện phép tính (hợp lí nếu có thể):1,frac{-1}{3}-frac{-3}{5}-frac{1}{6}+frac{1}{43}-frac{-3}{7}+frac{-1}{2}-frac{1}{35}
2,left(-frac{1}{3}+frac{7}{13}right)-left(frac{-16}{24}+frac{6}{26}+frac{9}{13}right)3,frac{-7}{3}-left[frac{2}{5}-left(frac{1}{3}+frac{-5}{25}right)right]
4,left(2frac{1}{4}-3frac{1}{5}right)-left[frac{-3}{4}+left(frac{4}{5}-2019right)right]
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Thực hiện phép tính (hợp lí nếu có thể):
\(1,\frac{-1}{3}-\frac{-3}{5}-\frac{1}{6}+\frac{1}{43}-\frac{-3}{7}+\frac{-1}{2}-\frac{1}{35}\\ \\ 2,\left(-\frac{1}{3}+\frac{7}{13}\right)-\left(\frac{-16}{24}+\frac{6}{26}+\frac{9}{13}\right)\)\(3,\frac{-7}{3}-\left[\frac{2}{5}-\left(\frac{1}{3}+\frac{-5}{25}\right)\right]\\ 4,\left(2\frac{1}{4}-3\frac{1}{5}\right)-\left[\frac{-3}{4}+\left(\frac{4}{5}-2019\right)\right]\)