\(\frac{-512}{343}=\left(-\frac{8}{7}\right)^n\)
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Tìm số nguyên N biết:
\(a,\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
\(b,\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
\(c,\left(\frac{-3}{4}\right)^n=\frac{81}{256}\)
\(d,\left(2x+3\right)^2=\frac{9}{121}^n\)
a) \(\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
\(\Rightarrow\left(\frac{1}{3}\right)^n=\frac{1^4}{3^4}\)
\(\Rightarrow\left(\frac{1}{3}\right)^n=\left(\frac{1}{3}\right)^4\)
\(\Rightarrow n=4\)
Vậy n = 4
b) \(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
\(\Rightarrow\frac{-8^3}{7^3}=\left(\frac{-8}{7}\right)^n\)
\(\Rightarrow\left(\frac{-8}{7}\right)^3=\left(\frac{-8}{7}\right)^n\)
\(\Rightarrow n=3\)
Vậy n = 3
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Tìm x, biết
\(\frac{-512}{343}=\left(\frac{-8}{7}\right)^x\)
Giúp mk nha, mk đag cần gấp ạ !! ♥
\(\frac{-512}{343}=\left(\frac{-8}{7}\right)^3\)
\(\Rightarrow x=3\)
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\(-\frac{512}{343}=\left(-\frac{8}{7}\right)^x\)
Vì \(-\frac{512}{343}=\left(-\frac{8}{7}\right)^3\)
\(\Rightarrow x=3\)
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tìm các số nguyên n biết
a. \(\left(\frac{1}{3}\right)^n=\frac{1}{18}\)
b. \(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
c. \(\left(\frac{-3}{4}\right)^n=\frac{81}{256}\)
d. 27n : 3n=9
e. \(\frac{1}{2}.2^n+4.2^n=9.2^5\)
a)\(27^x:3^x=9\)
b)\(\frac{125}{5^x}=25\)
c)\(\frac{-243}{\left(-3\right)}x=-245\)
d)\(\left(\frac{1}{3}\right)x=\frac{1}{81}\)
e)\(\frac{-512}{343}=\left(\frac{-8}{7}\right)^x\)
g)\(\left(\frac{-3}{4}\right)^x=\frac{81}{256}\)
a) x=1
b) x=1
c) x= -(245/81)
d) x= 1/27
e) x=3
g) x=4
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1) Tính:
a) \(\frac{6^3-3.6^2+3^2}{-13}\)
b) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
2) Tìm n \(\in\)Z:
a) 27n : 3n = 9
b) \(\frac{25}{5^n}=5\)
c) \(\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
d) \(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
ko bt làm thì xuống lớp 6 hocj đi
Bạn 12345678901 xuống lớp 1 học đạo đức làm người nhé bạn. Lịch sự tí đi
tính
\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{3}{2}\right)^3:\left(\frac{3}{8}\right)3}{2^{7.}5^2+512}\)
Tìm n∈Z biết :
a,27n/3n
b,frac{25}{5^n}5
c,frac{81}{left(-3right)^n}-243
d,frac{1}{2}cdot2^n+4cdot2^n9cdot2^5
e,(frac{1}{3})nfrac{1}{81}
f,left(frac{-3}{4}right)^nfrac{81}{256}
g,frac{-512}{343}left(frac{-8}{7}right)^n
h,5-1*25n125
k,3-1*3n+6*3n-17*36
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Tìm n∈Z biết :
a,27n/3n
b,\(\frac{25}{5^n}\)=5
c,\(\frac{81}{\left(-3\right)^n}=-243\)
d,\(\frac{1}{2}\cdot2^n+4\cdot2^n=9\cdot2^5\)
e,(\(\frac{1}{3}\))n=\(\frac{1}{81}\)
f,\(\left(\frac{-3}{4}\right)^n=\frac{81}{256}\)
g,\(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
h,5-1*25n=125
k,3-1*3n+6*3n-1=7*36
a) Câu này thiếu đề nhé bạn.
b) \(\frac{25}{5^n}=5\)
\(\Rightarrow5^n=25:5\)
\(\Rightarrow5^n=5\)
\(\Rightarrow5^n=5^1\)
\(\Rightarrow n=1\)
Vậy \(n=1.\)
c) \(\frac{81}{\left(-3\right)^n}=-243\)
\(\Rightarrow\left(-3\right)^n=81:\left(-243\right)\)
\(\Rightarrow\left(-3\right)^n=-\frac{1}{3}\)
\(\Rightarrow\left(-3\right)^n=\left(-3\right)^{-1}\)
\(\Rightarrow n=-1\)
Vậy \(n=-1.\)
e) \(\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
\(\Rightarrow\left(\frac{1}{3}\right)^n=\left(\frac{1}{3}\right)^4\)
\(\Rightarrow n=4\)
Vậy \(n=4.\)
f) \(\left(-\frac{3}{4}\right)^n=\frac{81}{256}\)
\(\Rightarrow\left(-\frac{3}{4}\right)^n=\left(-\frac{3}{4}\right)^4\)
\(\Rightarrow n=4\)
Vậy \(n=4.\)
Chúc bạn học tốt!
d) \(\frac{1}{2}.2^n+4.2^n=9.2^5\)
\(\Rightarrow2^n.\left(\frac{1}{2}+4\right)=288\)
\(\Rightarrow2^n.\frac{9}{2}=288\)
\(\Rightarrow2^n=288:\frac{9}{2}\)
\(\Rightarrow2^n=64\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
Vậy \(n=6.\)
g) \(-\frac{512}{343}=\left(-\frac{8}{7}\right)^n\)
\(\Rightarrow\left(-\frac{8}{7}\right)^n=\left(-\frac{8}{7}\right)^3\)
\(\Rightarrow n=3\)
Vậy \(n=3.\)
h) \(5^{-1}.25^n=125\)
\(\Rightarrow5^{-1}.5^{2n}=5^3\)
\(\Rightarrow5^{-1+2n}=5^3\)
\(\Rightarrow-1+2n=3\)
\(\Rightarrow2n=3+1\)
\(\Rightarrow2n=4\)
\(\Rightarrow n=4:2\)
\(\Rightarrow n=2\)
Vậy \(n=2.\)
k) \(3^{-1}.3^n+6.3^{n-1}=7.3^6\)
\(\Rightarrow3^{n-1}+6.3^{n-1}=7.3^6\)
\(\Rightarrow3^{n-1}.\left(1+6\right)=7.3^6\)
\(\Rightarrow3^{n-1}.7=7.3^6\)
\(\Rightarrow n-1=6\)
\(\Rightarrow n=6+1\)
\(\Rightarrow n=7\)
Vậy \(n=7.\)
Chúc bạn học tốt!
b)\(\frac{25}{5^n}\)=5
\(5^n\)=25/5
\(5^n\)=\(5^1\)
⇒ n = 1
c) \(\frac{81}{\left(-3\right)^n}\)=-243
\(\left(-3\right)^n\)=81/-243
\(\left(-3\right)^n\)=\(\frac{-1}{3}\)
\(\left(-3\right)^n\)=\(\left(-3\right)^{-1}\)
⇒n=-1
\(\frac{\left(\frac{2}{7}\right)^7.\left(\frac{5}{7}\right)^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^3+512}\)
\(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{3}\right)^6:\left(\frac{343}{625}\right)^{-2}\)