Tìm x, biết
\(\frac{-512}{343}=\left(\frac{-8}{7}\right)^x\)
Giúp mk nha, mk đag cần gấp ạ !! ♥
1) Tính:
a) \(\frac{6^3-3.6^2+3^2}{-13}\)
b) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
2) Tìm n \(\in\)Z:
a) 27n : 3n = 9
b) \(\frac{25}{5^n}=5\)
c) \(\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
d) \(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
tính
\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{3}{2}\right)^3:\left(\frac{3}{8}\right)3}{2^{7.}5^2+512}\)
\(\frac{\left(\frac{2}{7}\right)^7.\left(\frac{5}{7}\right)^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^3+512}\)
\(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{3}\right)^6:\left(\frac{343}{625}\right)^{-2}\)
\frac{\left(\frac{2}{5}\right)^7\times 5^{7\:}+\left(\frac{9}{4}\right)^3\div \left(\frac{3}{16}\right)^3}{2^7\times 5^2+512}
Bài 1: Tìm x:
[0,5x-2] - [x+\(\frac{2}{3}\)]=0
Bài 2: tìm các số nguyên m, n biết:
a) (\(\frac{1}{3}\))\(^3\)= \(\frac{1}{81}\)
B) \(\frac{-512}{343}\)=(\(\frac{-8}{7}\))
c) \(\frac{-32}{\left(-2\right)^n}\)= 4
d) (\(\frac{1}{2}\))\(^{2n-1}\)=\(\frac{1}{8}\)
Thực hiện phép tính \(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\frac{\left(\frac{9}{4}\right)^3}{\left(\frac{3}{16}\right)^3}}{2^7\cdot5^2+512}\)
tính:
\(\frac{1-\frac{1}{\sqrt{49}}+\frac{1}{49}-\frac{1}{\left(\sqrt[7]{7}\right)^2}}{\frac{\sqrt{64}}{2}-\frac{4}{7}+\left(\frac{2}{7}\right)^2-\frac{4}{343}}\)