Tính A = 1 + 2 + 22 + 23 + ... + 230
A = 1 - 2 + 22 - 23 + 24 - 25 +...+ 228 - 229 + 230
\(2A=2-2^2+2^3-...-2^{30}+2^{31}\\ \Leftrightarrow2A+A=2-2^2+2^3-...-2^{30}+2^{31}+1-2+2^2-...-2^{29}+2^{30}\\ \Leftrightarrow3A=2^{31}+1\\ \Leftrightarrow A=\dfrac{2^{31}+1}{2}\)
Tính nhanh :
a) 23 . 55 - 45 . 23 + 230
b) 71 . 66 - 41 . 71 - 71
c) 11 . 50 + 50 . 22 - 100
d) 54 . 27 - 27 . 50 + 50
a. = 23 . (55-45) + 230
= 23 . 10 +230
= 230 + 230
= 460
b. = 71 . (66 - 41 - 1)
= 71 . 24
= 1704
c. = 50 . (11 + 22) - 100
= 50 . 33 - 100
= 1650 - 100
= 1550
d. = 27. (54 - 50) + 50
= 27 . 4 + 50
= 108 + 50
= 158
a) 23.55-45.23+230
=23.(55-45)+230
=23.10+230
=230+230
=460
b) 71.66-41.71-71
=71.(66-41-1)
=71.24
=1704
c) 11.50+50.22-100
=50.(11+22)-100
=50.33-100
=1550
d) 54.27-27.50+50
=27.(54-50)+50
=27.4+50
=108+50
=158
# Bé_Bông #
a, 23 . 55 -45 . 23 + 230
23 . ( 55 - 45) + 230
23 . 10 + 230
230 + 230
4600
b, 71 . 66 - 41 . 71 - 71
71 . ( 66 - 71 - 1)
71 . ( -4)
-248
c, 11 . 50 + 50 . 22 - 100
11 . ( 50 + 50 ) - 100
11 . 100 - 100
1100 - 100
1000
d, 54 . 27 - 27 . 50 + 50
27 . ( 54 - 50 ) + 50
27 . 4 + 50
108 + 50
158
tck mk nhé
thank you
Câu 1: Với a = 4; b = -5 thì tích a2b bằng:
A. 80 B. –80 C. 11 D. 100
Câu 2: Cách tính đúng là:
A. 22 . 23 = 25 B. 22 . 23 = 26 C. 22 . 23 = 46 D. 22 . 23 = 45
Câu 3: Cách tính đúng:
A. 43 . 44 = 412 B. 43 . 44 = 1612 C. 43 . 44 = 47 D. 43 . 44 = 87
#Hạo_Hạo
Tính tổng
A = 1 + 2 + 22 + 23 +.....+ 262 + 263
A=1+2+22+23+...+262+263
2A=2+22+23+24+...+263+264
2A-A=2+22+23+24+...+263+264-1+2+22+23+...+262+263
A=264-1
\(A=1+2+2^2+2^3+..+2^{62}+2^{63}\)
\(2A=2+2^2+2^3+...+2^{63}+2^{64}\)
\(2A-A=2^{64}-1\)
\(A=2^{64}-1\)
A=1+2+22+23+...+262+263
2A=2(1+2+22+23+...+262+263)
2A=2+23+24+25...+263+264
2A-A=(2+23+24+25...+263+264)-(1+2+22+23+...+262+263)
A=264-1
Nha bạn. Chúc bn ht
Tính tổng
A = 1 + 2 + 22 + 23 + ... + 262 + 263
2A = 2 + 22 + 23 + 24 + ... + 263 + 264
A = 264 - 1
Câu 1 (5 điểm). Thực hiện phép tính
a) 7/22+ -15/23 +2022/2023+ -8/23 +15/22
b) -2/11+ 5 và 5/6(14 và 1/5 – 11 và 1/5): 5 và 1/2
,c) 2000+{20-[4.2022°-(3²+5):2]}
a, \(\dfrac{7}{22}\) - \(\dfrac{15}{23}\) + \(\dfrac{2022}{2023}\) - \(\dfrac{8}{23}\) + \(\dfrac{15}{22}\)
= ( \(\dfrac{7}{22}\) + \(\dfrac{15}{22}\)) - ( \(\dfrac{15}{23}+\dfrac{18}{23}\)) + \(\dfrac{2022}{2023}\)
= \(\dfrac{22}{22}\) - \(\dfrac{23}{23}\) + \(\dfrac{2022}{2023}\)
= 1 - 1 + \(\dfrac{2022}{2023}\)
= \(\dfrac{2022}{2023}\)
b, - \(\dfrac{2}{11}\) + 5\(\dfrac{5}{6}\) ( 14\(\dfrac{1}{5}\) - 11\(\dfrac{1}{5}\)): 5\(\dfrac{1}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) ( \(\dfrac{71}{5}\) - \(\dfrac{56}{5}\)) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) . \(\dfrac{15}{5}\) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{2}\) \(\times\) \(\dfrac{2}{11}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{11}\)
= \(\dfrac{33}{11}\)
= 3
c, 2000 + { 20 - [ 4.20220 - (32 + 5):2] }
= 2000 + { 20 - [ 4.1 - (9+5):2]}
= 2000 + { 20 - [ 4 - 14 : 2 ]}
= 2000 + { 20 - [ 4 -7]}
= 2000 + { 20 - (-3)}
= 2000 + 23
= 2023
Bài 6. Tính
a) A=1+3+32+33+...+32000
b) B = 250- 249- 248 -...- 22- 2
c) C = 2000.(20019+20018+...+2001)+1
d) D = 1-2+22-23+...+22020
a, A = 1 + 3 + 32 + 33 + ... + 32000
3.A = 3 + 32 + 33+ 33+... + 32001
3A - A = 3 + 32 + 33 + ... + 32001 - (1 + 3 + 32 + 33 + ... + 32000)
2A = 3 + 32 + 33 + ... + 32001 - 1 - 3 - 32 - 33 - ... - 32000
2A = 32001 - 1
A = \(\dfrac{3^{2001}-1}{2}\)
Câu 1 (5 điểm). Thực hiện phép tính 2624
a) 7/22+ -15/23 +2022/2023+ -8/23 +15/22
b) -2/11+ 5 và 5/6(14 và 1/5 – 11 và 1/5): 5 và 1/2
,c) 2000+(20-[4.2022°-(3²+5):2]}
Đặt tính và tính
a) 40 230 : 6
b) 9240 : 30
c) 8008 : 22
d) 1682 : 58
a) 40 230 : 6 = 6705
b) 9240 : 30 = 308
c) 8008 : 22 = 364
d) 1682 : 58 = 29
3. Thực hiện phép tính: A, 61• 45 + 61 • 23 - 68 • 51 B, 3 • 52 - ( 75 - 4 • 23 ) C,36 : { 22 • 5 - [ 30 - ( 5 - 1 ]2 } D,(12•49 -3 • 22•72):(2020• 2021)
a: \(61\cdot45+61\cdot23-68\cdot51\)
\(=61\left(45+23\right)-68\cdot51\)
\(=68\cdot61-68\cdot51\)
\(=68\left(61-51\right)=68\cdot10=680\)
b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)
\(=75-75+4\cdot8\)
\(=4\cdot8=32\)
c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)
\(=\dfrac{36}{20-30+4^2}\)
\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)
d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)
\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)