A = \(\dfrac{254\times399-145}{254+399\times253}\)

A = \(\dfrac{\left(253+1\right)\times399-145}{254+399\times253}\)

A = \(\dfrac{253\times399+399-145}{254+399\times253}\)

A = \(\dfrac{253\times399+254}{254+399\times253}\)

A = 1 

a) \(254x399-145=\left(250+4\right)\left(400-1\right)-145\)

\(=100000+1600-250-145-4=101600-\left(250+145+4\right)\)

\(=101600-399=101201\)

b) \(254+399x253=254+\left(400-1\right)x\left(250+3\right)\)

\(=254+100000+1200-250-3\)

\(=101454-250-3=101201\)

\(\dfrac{a}{b}=1\)

254 × 399 - 145 / 254 + 399 × 253

= (253 + 1) × 399 - 145 / 254 + 399 × 253

= 253 × 399 + (399 - 145) / 254 + 399 × 253

= 253 × 399 + 254 / 254 + 399 × 253

= 1

\(\frac{254x399-145}{254+399x253}\)

\(=\frac{253x399+399-145}{254+399x253}\)

\(=\frac{253x399+254}{254+399x253}=1\)

\(\frac{254.399-145}{254+399.253}=\frac{254.399-145}{\left(254-1\right).399+254}\)\(=\frac{254.399-145}{254.399-399+254}=\frac{254.399-145}{254.399-145}=1\)

DẤU . LÀ DẤU NHÂN NHA

\(\frac{254.399-145}{254+399.253}\)

\(=\frac{253.399+399-145}{254+399.253}\)

\(=\frac{253.399+254}{254+399.253}=1\)

Trả lời

254.399-145/254+399.253

=253.399+399-145/254+399.253

=253.399+254/254+399.253

=1.

= 202292,42913385826771653543307087.............

=202292,4291338582677165353307087

a) \(\frac{254.399-145}{254+399.253}\)

\(=\frac{253.399+399-145}{254+399.253}\)

\(=\frac{253.399+254}{254+399.253}\)

\(=1\)

b) tự làm

A)\(\frac{254\cdot399-145}{254+399\cdot253}\)

\(=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+1\cdot399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+254}{254+399\cdot253}\Rightarrow=1\)

B) X x X - 1/6 = 5/18

x² = 5/18 + 1/6

x² = 8/18 = 4/9

x= \(\sqrt{\frac{4}{9}}\) \(=\frac{2}{3}\)

\(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}=\frac{253.399+\left(399-145\right)}{254+399.253}\)

                                                                               \(=\frac{253.399+254}{254+399.253}=1\)

\(\frac{254\times399-145}{254+399\times253}\)

\(=\frac{253\times399+399-145}{254+399\times253}\)

\(=\frac{253\times399+254}{254+399\times253}\)

\(=1\)

uh là nhân

a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)

\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)

b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)

\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)

c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)