2x-9/240=39/80
2x-9/240=39/80
39/80=117/240
=>2x-9/240=117/240
=>2x-9=117
=>2x=126
=>x=63
39/80 = 117/240
\(\Rightarrow\) 2x - 9/240 = 117/240
2x = 117/240 + 9/240
2x = 21/40
x = 21/40 : 2
x = 21/80
Đáp án là 63. Cách giải giống bạn Huy.
2x-9 /240
=39/80
2x-9=117
2x=117+9
2x=126
x=126:2
x=26
co j thick nhe
tìm số nguyên x biết \(\dfrac{2x-9}{240}\) -\(\dfrac{39}{80}\)
nó phải có = bao nhiêu thì mới ra kết quả bạn ạ
\(\dfrac{2x-9}{240}\) \(=\) \(\dfrac{39}{80}\) \(\Leftrightarrow\) \(\left(2x-9\right)\) \(.80\) \(=\) \(240.39\)
\(2x\) \(-\) \(9\) \(=\) ( \(240\) \(.\) \(39\) ) \(:\) \(80\)
\(2x\) \(-\) \(9\) \(=\) \(117\)
\(2x\) \(=\) \(126\)
\(x\) \(=\) \(63\)
Tìm số nguyên x biết rằng:2x-9 / 240=39/80
\(\frac{2x-9}{240}=\frac{39}{80}\Leftrightarrow\left(2x-9\right).80=240.39\)
\(2x-9=\left(240.39\right):80\)
\(2x-9=117\)
\(2x=126\)
\(x=63\)
2x-9/240=39/80
hay 39.3/240=2x-9/240
nên 117=2x-9
x=63
2x-9/240=39/80
=>2x-9/240=117/240
=>2x-9=117
=>2x=117+9
=>2x=126
=>x=126:2
=>x=63
Tìm số nguyên x , biết rằng 2x-9 / 240 = 39 / 80
2x-9 / 240 = 39 / 80
2x-9 / 240 = 117 / 240
2x - 9 = 117
2x = 117 + 9
2x = 126
x = 126 : 2
x = 63
Vậy x = 63
\(\frac{2x-9}{240}=\frac{39}{80}\)
\(\Rightarrow\frac{2x-9}{240}=\frac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(\Rightarrow2x=117+9\)
\(\Rightarrow2x=126\)
\(\Rightarrow x=126:2\)
\(\Rightarrow x=63\)
Vậy \(x=63\)
Chúc bạn học tốt !!!
2x - 9 / 240 = 39/ 80
=> ( 2x - 9 ) ,. 80 = 240 . 39
=> ( 2x - 9 ) . 80 = 9360
=> ( 2x - 9 ) = 9360 : 80
=> ( 2x - 9 ) = 117
=> 2x = 117 + 9
=> 2x = 126
=> x= 126 : 2
=> x = 63
tìm số nguyên x,biết
2x-9/240=39/80
Ta có: \(\frac{2x-9}{240}=\frac{39}{80}\)
=> \(\frac{2x-9}{240}=\frac{117}{240}\)
=> 2x-9 = 117
=> 2x = 117+9
=> 2x = 126
=> x = 126:2
=> x = 63
Ta có: \(\frac{2x-9}{240}=\frac{39}{80}\)
=> \(\frac{2x-9}{240}=\frac{156}{240}\)
=> 2x-9 = 156
=> 2x = 156+9
=> 2x = 165
=> x = 82,5
Tim số nguyên x biết:
2x-9/240=39/80
\(2x=\frac{39}{80}+\frac{9}{240}=\frac{21}{40}\)
\(x=\frac{21}{40}\div2=\frac{21}{40}\times\frac{1}{2}=\frac{21}{80}\)
\(\dfrac{2x-9}{240}=\dfrac{39}{80}\)
\(\dfrac{2x-9}{240}=\dfrac{117}{240}\)
=> 2x -9=117
2x=117+9
2x=126
x=126/2
x=63
\(\dfrac{2x-9}{240}\)=\(\dfrac{117}{240}\)
►2x-9=117
2x=117+9
2x=126
x=126:2
x=63
Vậy:x=63
\(\dfrac{2x-9}{240}=\dfrac{39}{80}=\dfrac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(2x=117-9\)
\(2x=108\)
\(x=108:2\)
\(x=54\)
Vậy: \(x=54\)
a)2x-9/240 = 39/80
b) GTTD (x-8)+12=25
\(\frac{2x-9}{240}=\frac{39}{80}\)
<=> \(\left(2x-9\right)\cdot80=240\cdot39\)
<=> \(160x-720=9360\)
<=> \(160x=10080\)
<=> \(x=63\)
\(\left|x-8\right|+12=25\)
<=> \(\left|x-8\right|=13\)
<=> x - 8 = 13 hoặc x - 8 = -13
<=> x = 21 hoặc x = -5
(2x-9):3/240:3 =39/80
2x:3-3/80=39/80
=>2x:3 =39
2x = 39:3
2x =13
x = 13 :2
x = 13/2
b)x - 8 =25 -12
x - 8 = 13
x = 13 +8
x = 21