7(x-3)-5(3-x)=11x-5

<=>7(x-3)+5(x-3)-11x+5=0

<=>12(x-3)-11x+5=0

<=>12x-36-11x+5=0

<=>x-31=0

<=>x=31

a, => 7x-63-30+5x=11x-6

=> 12x-93=11x-6

=> 12x=11x-6+93 = 11x+87

=> 12x-11x=87

=> x=87

b, => 7x-21-15+5x=11x-5

=> 12x-36=11x-5

=> 12x=11x-5+36 = 11x+31

=> 12x-11x=31

=> x=31

Tk mk nha

\(7.\left(x-3\right)-5.\left(3-x\right)=11x-5\)

        \(7x-21-15+5x=11x-5\)

                           \(12x-36=11x-5\)

                         \(12x-11x=-5+36\)

                                            \(x=31\)

Vậy \(x=31\)

\(7.\left(x-3\right)-5.\left(3-x\right)=11x-5\)

\(7x-7.3-5.3+5x=11x-5\)

\(7x-21-15+5x=11x-5\)

\(7x-\left(21+15\right)+5x=11x-5\)

\(7x-36+5x=11x-5\)

\(7x+5x-36=11x-5\)

\(12x-11x=\left(-5\right)+36\)

\(x=31\)

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\(7\left(x-3\right)-5\left(3-x\right)=11x-5\)

\(\Leftrightarrow7x-21-15+5x=11x-5\)

\(\Leftrightarrow7x+5x-11x=-5+15+21\)

\(\Leftrightarrow x=31\)

Vậy...

\(7\left(x-3\right)-5\left(3-x\right)=11x-5.\)

\(\left(7x-21\right)-\left(15-5x\right)=11x-5\)

\(7x-21-15+5x=11x-5\)

\(12x-36=11x-5\)

\(12x-11x=36-5\)

\(x=31\)

7 (x - 3) - 5 (3 - x) = 11x - 5

7x - 7.3 - 5.3 - 5x = 11x - 5

7x - 5x - 21 -15 = 11x - 5

2x - (21 + 15) = 11x - 5

2x - 36 = 11x - 5

2x - 11x = 36 - 5

-9x = 31

x = 31:(-9)

x = \(\frac{-31}{9}\)

Mik làm sai rồi, như bn Ahwi mới đúng

X là nhân à?

6/11X 3/7 + 3/7 X 5/11

=\(\dfrac{6x3}{11x7}+\dfrac{3x5}{7x11}=\dfrac{18}{77}+\dfrac{15}{77}=\dfrac{33}{77}\)

Kết quả là 33/77 em nhé! :)

\(\dfrac{6}{11}\) . \(\dfrac{3}{7}\) + \(\dfrac{3}{7}\) . \(\dfrac{5}{11}\)

= ( \(\dfrac{6}{11}\) + \(\dfrac{5}{11}\) ) \(\dfrac{3}{7}\)

= 1 . \(\dfrac{3}{7}\) = \(\dfrac{3}{7}\)