Làm giúp mình với ạ

Em ghi đề lại cho chính xác nhé

Đáp án : C

a) 5/3 : 0,5 = 4/3 : 0,1 . x

10/3 = 40/3.x

x = 1/4

b) 18¹⁶ = 2x.3³²

2¹⁶.(3²)¹⁶ = 2x .3³²

2¹⁶.3³² = 2x.3³²

=> 2¹⁶ = 2.x

=> x = 2¹⁶ : 2 = 2¹⁵

\(a.\frac{5}{3}:0,5=\frac{4}{3}:0,1\times x\)

\(\Leftrightarrow\frac{4}{3}:0,1\times x=\frac{10}{3}\)

\(\frac{4}{3}:0,1=\frac{10}{3}:x\)

\(\frac{40}{3}=\frac{10}{3}:x\)

\(\Rightarrow x=\frac{10}{3}:\frac{40}{3}\)

\(x=\frac{1}{4}\)

\(b.18^{16}=2x.3^{32}\)

\(2^{16}.\left(3^{16}\right)^2=2x.3^{32}\)

\(2^{16}.\left(3^{32}\right)=2x.3^{32}\)

\(2^{16}=2x\)

\(\Rightarrow x=2^{16}:2\)

\(x=2^{15}\)

\(\)

A = \(x\) - 2\(x\) + 3

A = - \(x\) + 3

|\(x\)| = 0,5

\(\left[{}\begin{matrix}x=0,5\\x=-0,5\end{matrix}\right.\)

Thay \(x=0,5\) vào A ta có: A = -0,5 + 3 = 2,5

Thay \(x\) = -,05 vào A ta có: A  = -(-0,5) + 3 = 3,5 

a. 7(2x - 0,5) - 3(x + 4) = 4 - 5(x - 0,7)

⇔ 14x - 4,5 - 3x - 12 = 4 - 5x + 3,5

⇔ 14x -3x + 5x = 4 + 4,5 + 3,5

⇔ 16x = 12

⇔ x = \(\dfrac{12}{16}=\dfrac{3}{4}\)

a. 7(2x - 0,5) - 3(x + 4) = 4 - 5(x - 0,7)

⇔ 14x - 3,5 - 3x - 12 = 4 - 5x + 3,5

⇔ 14x - 3x + 5x = 4 + 3,5 + 3,5

⇔ 16x = 11

⇔ x = \(\dfrac{11}{16}\)

a. \(7\left(2x-0,5\right)-3\left(x+4\right)=4-5\left(x-0,7\right)\)

\(\Rightarrow14x-3,5-3x-12=4-5x+3,5\)

\(\Rightarrow14x-3x+5x=4+3,5+3,5+12\)

\(\Rightarrow16x=23\)

\(\Rightarrow x=\dfrac{23}{16}\)

Vậy \(S=\left\{\dfrac{23}{16}\right\}\)

b. \(5x^3-2x^2-7x=0\)

\(\Rightarrow x\left(5x^2-2x-7\right)=0\)

\(\Rightarrow x\left(x-\dfrac{7}{5}\right)\left(x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x-\dfrac{7}{5}=0\\x+1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{7}{5}\\x=-1\end{matrix}\right.\)

Vậy \(S=\left\{0;\dfrac{7}{5};-1\right\}\)

\(7\left(2x+0,5\right)-3\left(x+4\right)=4-5\left(x-0,7\right)\\ \Rightarrow14x+3,5-3x-12=4-5x+3,5\\ \Rightarrow14x+3,5-3x-12-4+5x-3,5=0\)

\(\Rightarrow16x-16=0\\ \Rightarrow16x=16\\ \Rightarrow x=1\)

Vậy pt có tập nghiệm \(S=\left\{1\right\}\)

$7\left(2x+0,5\right)-3\left(x+4\right)=4-5\left(x-0,7\right)$$\Rightarrow 16x-16=0\Rightarrow 16x=16\Rightarrow x=1$

Vậy pt có tập nghiệm $S=\left\{1\right\}$

a.

3x - 2 = 2x - 3

<=> 3x -2x = -3+2

<=> x = -1

Vậy.............

b.

\(5-\left(x-6\right)=4\left(3-2x\right)\)

\(\Leftrightarrow5-x+6=12-8x\)

\(\Leftrightarrow7x=1\)

\(\Leftrightarrow x=\dfrac{1}{7}\)

Vậy..........

c.

\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)

\(\Leftrightarrow5\left(7x-1\right)+2x.30=6\left(16-x\right)\)

\(\Leftrightarrow35x-5+60x=96-6x\)

\(\Leftrightarrow101x=101\)

\(\Leftrightarrow x=1\)

Vậy ......

e tách ra nhé.☘

;))

a/ \(\orbr{\begin{cases}x-2=0\\2x-5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=\frac{5}{2}\end{cases}}\)

\(a,\left(x-2\right)\left(2x-5\right)=0.\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\2x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\2x=5\Leftrightarrow x=\frac{5}{2}\end{cases}}}\)

Vậy .... 

\(b,\left(0,2x-3\right)\left(0,5x-8\right)=0\left(\text{Mạo muội sửa đề nha 0,5 thành 0,5x}\right)\)

\(\Leftrightarrow\orbr{\begin{cases}0,2x-3=0\\0,5x-8=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}0,2x=3\\0,5x=8\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=15\\x=16\end{cases}}\)

Vậy ... ( có j sai thì bỏ qua cho)

\(c,2x\left(x-6\right)+3\left(x-6\right)=0\)

\(\Leftrightarrow\left(x-6\right)\left(2x+3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-6=0\\2x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=6\\2x=-3\Leftrightarrow x=-\frac{3}{2}\end{cases}}}\)

Vậy ... 

\(d,\left(x-1\right)\left(2x-4\right)\left(3x-9\right)=0\)

\(\Leftrightarrow2.3\left(x-1\right)\left(x-2\right)\left(x-3\right)=0\)

( ko có ngoặc vuông 3 cái nên mk trình bày kiểu này) 

+ TH1: 

x-1=0 <=> x= 1

+ TH2: 

x-2=0  <=> x=2 

+TH3: 

x-3 = 0 <=> x = 3 

b/ vế sau ko co x ak bạn

c/\(\Leftrightarrow\left(x-6\right)\left(2x+3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-6=0\\2x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=6\\x=-\frac{3}{2}\end{cases}}}\)