Áp dụng tính chất của dãy tỷ số bằng nhau

\(\frac{3x-1}{40-5x}=\frac{25-3x}{4x-34}=\frac{\left(3x-1\right)+\left(25x-3x\right)}{\left(40-5x\right)+\left(5x-34\right)}=4\)

\(\Rightarrow\frac{3x-1}{40-5x}=4\)

\(\Rightarrow3x-1=3\left(40-5x\right)\)

\(\Rightarrow3x-1=160-20x\)

\(\Rightarrow23x=161\)

\(\Rightarrow x=161:23\)

\(\Rightarrow x=7\)

60 x 3 + 3 x 40

= 3 x ( 60 + 40 )

= 3 x 100

= 300

34 x 5 + 34 x 95

= 34 x ( 5 + 95 ) 

= 34 x 100

= 3400

60 x 3 + 3 x 40

= 3 x (60 + 40)

= 3 x 100

=300

34 x 5 + 34 x 95

= 34 x (5+95)

=34 x 100

= 3400

60 x 3 + 3 x 40 

= ( 60 + 40 ) x 3

=       100     x 3

=           300

34 x 5 + 34 x 95

= 34 x  ( 5 + 95 )

=  34 x      100

=       3400

Cấp độ 1 : \(5+3=8\)

Cấp độ 2 : \(34-12=22\)

Cấp độ 3 : \(34\times6=204\)

Cấp độ 4 : \(38\times26=988\)

Cấp độ 5 : \(34,5\times73,732=2543,54\)

\(\left(3-x\right)\left(3+x\right)+\left(x-5\right)^2\\ =9-x^2+x^2-10x+25\\ =34-10x\)

$#Shả$

`A)=5/17xx(15/34+19/34)`

`=5/17xx1=5/17`

`B)=(13/12+7/12)+1/3`

`=5/3+1/3=2`

\(\sqrt{x+3}=\sqrt{5-x}\)

\(\Leftrightarrow x+3=5-x\)

\(\Leftrightarrow2x=2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

17/5 : x  = 51/10

           x = 17/5 : 51/10

           x = 2/3

17/5 : x = 34/5 : 4/3

17/5 : x = 51/10

x = 17/5 : 51/10

x = 2/3

Vậy x = ...

\(\frac{17}{5}:x=\frac{34}{5}:\frac{4}{3}\)

\(\frac{17}{5}:x=\frac{34}{5}\cdot\frac{3}{4}\)

\(\frac{17}{5}:x=\frac{51}{10}\)

\(x=\frac{17}{5}:\frac{51}{10}\)

\(x=\frac{17}{5}\cdot\frac{10}{51}\)

\(x=\frac{2}{3}\)

Vậy x=\(\frac{2}{3}\)

a) 2017 x 34 + 2017 x 65 + 2017

= 2017 x ( 34+65+1)

= 2017 x 100

= 201700

b) 3/5 x 7/9 - 3/5 x 2/9

= 3/5 x ( 7/9- 2/9)

= 3/5 x 5/9

= 1/3

a) 2017 x 34 + 2017 x 65 + 2017

= 2017 x (34 + 65 + 1)

= 2017 x 100

= 201700

b) \(\dfrac{3}{5}\) x \(\dfrac{7}{9}\) - \(\dfrac{3}{5}\) x \(\dfrac{2}{9}\)

= \(\dfrac{3}{5}\) x \(\left(\dfrac{7}{9}-\dfrac{2}{9}\right)\)

= \(\dfrac{3}{5}\) x \(\dfrac{5}{9}\)

= \(\dfrac{1}{3}\)

\(a,=2017\times\left(34+65+1\right)=2017\times100=201700\)

\(b,\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{15}{45}=\dfrac{1}{3}\)