So sánh : \(A=\frac{2013}{a^n}\)+ \(\frac{2011}{a^m}\) và \(B=\frac{2012}{a^m}\)+ \(\frac{2012}{a^n}\)
Biết rằng : a>0, m>0, n>0
1.Cho phân số \(\frac{a}{b}\)(a, b \(\in\)N, b\(\ne\)0)
Giả sử \(\frac{a}{b}\)> 1 và m\(\in\)N, m\(\ne\)0. Chứng minh rằng:
\(\frac{a}{b}\)> \(\frac{a+m}{b+m}\)
2.So sánh: A=\(\frac{2011}{2012}\)+\(\frac{2012}{2013}\)và B=\(\frac{2011+2012}{2012+2013}\)
a. Ta có
\(B=\frac{2011+2012}{2012+2013}=\frac{2011}{2012+2013}+\frac{2012}{2012+2013}.\)
Vì\(\frac{2011}{2012+2013}< \frac{2011}{2012}.\)(1)
\(\frac{2012}{2012+2013}< \frac{2012}{2013}.\)(2)
Cộng vế với vế của 1;2 ta được
\(B=\frac{2011}{2012+2013}+\frac{2012}{2012+2013}< A=\frac{2011}{2012}+\frac{2012}{2013}\)
hay A>B
Làm ơn giúp mk, mk đang cần gấp!!!
a.Ta có
\(1-\frac{a}{b}=\frac{b-a}{b}.\)
\(1-\frac{a+m}{b+m}=\frac{a-b}{b+m}\)
Do \(m\in N;m\ne0\)nên \(\frac{b-a}{b}>\frac{b-a}{b+m}\Rightarrow\frac{a}{b}< \frac{a+m}{b+m}\)
hay: \(\frac{a}{b}< \frac{a+m}{b+m}\)
Cho ba số a,m,n\(\in\)N,hãy so sánh
A=\(\frac{2012}{a^m}\)+\(\frac{2012}{a^n}\)và B=\(\frac{2013}{a^m}\)+\(\frac{2011}{a^n}\)
~.~
M lớn hơn hay nhỏ hơn N vậy bạn ơi??
Nếu m > n thì A > B; m < n thì A < B nhé!!
So sánh A và B , biết rằng :
A = \(-\frac{1}{2010.2011}-\frac{1}{2012.2013}\)và B = \(\frac{2010}{2011}-\frac{2011}{2012}+\frac{2012}{2013}-\frac{2013}{2014}\)
a) So sánh P và Q
Biết\(P=\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}\) và\(\frac{2010+2011+2012}{2011+2012+2013}\)
b) Tìm hai số tự nhiên a và b, biết: BCNN(a,b)=420;ƯCLN(a,b)=21 và a+21=b
Áp dụng BĐT \(\frac{a}{b}+\frac{b}{c}+\frac{c}{d}>\frac{a+b+c}{a+b+c}=1>\frac{a+b+c}{b+c+d}\).
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2010+2011+2012}>\frac{2010+2011+2012}{2011+2012+2013}\)mà 2010 + 2011 + 2012 < 2011+2012+2013 ,suy ra \(\frac{2010+2011+2012}{2011+2012+2013}< 1\))
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\)hay P > Q
Vậy P > Q
b) Áp dụng công thức BCNN (a, b) . UCLN (a,b) = a.b
\(\Rightarrow a.b=420.21=8820\)
Ta có:
\(ab=8820\)
\(a+21=b\Rightarrow b-a=21\)
Hai số cách nhau 21 mà có tích là 8820 là 84 , 105
Mà a + 21 = b suy ra a < b
Vậy a = 84 ; b = 105
a,-Cách khác:
-Ta có: \(\frac{2010+2011+2012}{2011+2012+2013}=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
-Mà: \(\frac{2010}{2011}>\frac{2010}{2011+2012+2013}\left(1\right)\)
\(\frac{2011}{2012}>\frac{2011}{2011+2012+2013}\left(2\right)\)
\(\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\left(3\right)\)
\(\Rightarrow P>Q\)
CHO : \(A=\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}\)
VÀ : \(B=\frac{2010+2011+2012}{2011+2012+2013}\)
SO SÁNH A VÀ B
TA CÓ :
\(B=\frac{2010+2011+2012}{2011+2012+2013}\)
\(B=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
VÌ : \(\frac{2010}{2011}>\frac{2010}{2011+2012+2013}\)
\(\frac{2011}{2012}>\frac{2011}{2011+2012+2013}\)
\(\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\)
=> A > B
VẬY , A > B
Mình tự hỏi. sao banh biết rồi còn đăng lên làm gì??????????
So sánh
M= \(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}\)
N= \(\frac{2010+2011+2012}{2011+2012+2013}\)
N =\(\frac{2010+2011+2012}{2011+2012+2013}\)
\(\Rightarrow N=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
Do: \(\frac{2010}{2011}>\frac{2010}{2011+2012+2013};\frac{2011}{2012}>\frac{2011}{2011+2012+2013};\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\)
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\Leftrightarrow N>M\)
cho \(A=\frac{2011}{2012}+\frac{2012}{2013};B=\frac{2011+2013}{2012+2013}\)So sánh A và B
Gọi 2011 là a
2012 là b;2013 là c
=>\(A=\frac{2011}{2012}+\frac{2012}{2013}=\frac{a}{b}+\frac{b}{c}\);\(B=\frac{2011+2013}{2012+2013}=\frac{a+c}{b+c}\)
=>\(A=\frac{a}{b}+\frac{b}{c}=\frac{ac+b^2}{bc}\)\(=\frac{\left(ac+b^2\right).\left(b+c\right)}{bc.\left(b+c\right)}\);\(B=\frac{a+c}{b+c}=\frac{\left(a+c\right).bc}{bc.\left(b+c\right)}\)
b+c>a+c;b2+ac>bc
Vậy A>B
\(\frac{A^{2011+2012}}{A^{2012+2013}}\)VÀ\(\frac{A^{2011}}{A^{2012}}+\frac{A^{2012}}{A^{2013}}\)
So sánh
Ta có
\(\frac{A^{2011}}{A^{2012}}=\frac{A^{2012}}{A^{2103}}=\frac{A}{A^2}\)
=> \(\frac{A^{2011}}{A^{2012}}+\frac{A^{2012}}{A^{2013}}=\frac{2A}{A^2}\)
\(\frac{A^{2011+2012}}{A^{2012+2013}}=\frac{A^{4023}}{A^{4025}}=\frac{1}{A^2}\)
=> \(\frac{A^{2011+2012}}{A^{2012+2013}}< \frac{A^{2011}}{A^{2012}}+\frac{A^{2012}}{A^{2013}}\)
So sánh 2 số sau: M=\(\frac{2013^{2012}+2012}{2013^{2011}+1}\)và \(N=\frac{2013^{2011}+2012}{2013^{2010}+1}\)
Ta có :
\(\frac{1}{2013}M=\frac{2013^{2012}+2012}{2013^{2012}+2013}=\frac{2013^{2012}+2013}{2013^{2012}+2013}-\frac{1}{2013^{2012}+2013}=1-\frac{1}{2013^{2012}+2013}\)
Lại có :
\(\frac{1}{2013}N=\frac{2013^{2011}+2012}{2013^{2011}+2013}=\frac{2013^{2011}+2013}{2013^{2011}+2013}-\frac{1}{2013^{2011}+2013}=1-\frac{1}{2013^{2011}+2013}\)
Vì \(\frac{1}{2013^{2012}+2013}< \frac{1}{2013^{2011}+2013}\) nên \(M=1-\frac{1}{2013^{2012}}>N=1-\frac{1}{2013^{2011}+2013}\)
Vậy \(M>N\)
Chúc bạn học tốt ~