bài 1 tìm x biết
128-3(x+4)=23
[(14x+26)-3+55]/5=35
(x+12)^2.(x-1)=0
720/[41-(2x-5)]=22.5
b) 1500.(x – 7) = 0
c) (2.x – 4).(48 – 12.x) = 0
d) (x + 12).(x – 1) =0
Bài 2: Tìm x biết:
a) 128- 3(x+ 4) = 23
b) [(14x+ 26). 3+ 55]: 5= 35
d) 720: [41- (2x- 5)]= 23. 5
b. 1500(x-7)=0
x-7=0
x=7
c. (2x-4)(48-12x)=0
2x-4=0 hoặc 48-12x=0
x=2 hoặc x=4
d. (x+12)(x-1)=0
x+12=0 hoặc x-1=0
x=-12 hoặc x=1
bài 2 :
a . 128-3(x+4)=23
3(x+4)=105
x+4=35
x=31
b. [(14X+26).3+55]:5=35
(14x+26).3+55=175
(14x+26).3=120
14x+26=40
14x=14
x=1
d. 720:[41-(2X-5)]=23.5
41-(2x-5)=720:(23.5)
41-(2x-5)=144/23
2x-5=799/23
2x=914/23
x=457/23
b, 1500.(x – 7) = 0
<=>1500x-10500=0
<=>1500x=10500
<=>x=7
Vậy x=7
c,(2.x – 4).(48 – 12.x) = 0
\(\Leftrightarrow\)\(\left\{{}\begin{matrix}2x-4=0\\48-12x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\12x=48\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
Vậy x=2 hoặc x=4
d, (x + 12).(x – 1) =0
\(\Leftrightarrow\left\{{}\begin{matrix}x+12=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-12\\x=1\end{matrix}\right.\)
Vậy x=-12 hoặc x=1
Bài 2:
a) 128- 3(x+ 4) = 23
\(\Leftrightarrow\)128-(3x+12)=23
\(\Leftrightarrow\)128-3x-12=23
\(\Leftrightarrow\)116-3x=23
\(\Leftrightarrow\)3x=116-23
\(\Leftrightarrow\)3x=93
\(\Leftrightarrow\)x=31
Vậy x=31
b) [(14x+ 26). 3+ 55]: 5= 35
\(\Leftrightarrow\)(14x+ 26). 3+ 55=175
\(\Leftrightarrow\)42x+78+55=175
\(\Leftrightarrow\)42x+133=175
\(\Leftrightarrow\)42x=175-133
\(\Leftrightarrow\)42x=42
\(\Leftrightarrow\)x=1
Vậy x=1
d, 720: [41- (2x- 5)]= 23. 5
\(\Leftrightarrow\)720: 41- (2x- 5)=115
\(\Leftrightarrow\)41-(2x- 5)=720:115
\(\Leftrightarrow\)41-(2x- 5)=\(\dfrac{144}{23}\)
\(\Leftrightarrow\)2x-5=\(\dfrac{799}{23}\)
\(\Leftrightarrow\)2x=\(\dfrac{914}{23}\)
\(\Leftrightarrow\)x=\(\dfrac{457}{23}\)
Vậy x=\(\dfrac{457}{23}\)
Bài 2. Tìm x biết:
a, 128 - 3(x + 4) = 23 d, 720 : [41 - (2x - 5)] = 2 3 .5
b, [(4x + 28).3 + 55] : 5 = 35 e, 123 – 5.( x + 4 ) = 38
c, (12x - 4 3 ).8 3 = 4.8 4 g, ( 3x – 2 4 ) .7 3 = 2.7 4
a,
128-3x-12=23
3x=128-12-23
3x=93
x=93:3
= 31
b,
(12x+84+55):5=35
12x+84+55=35.5
12x+84+55=175
12x=175-55-84
12x=36
x=36:12
x=3
1.tìm x
a,128-3.(x=4)=23 b,[(4x =28).3=55]:5=35
c,(12x-4^3).8^3=4.8^4 d,720 :[41-(2x-5)]=263.5
\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)
c) \(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-64=4.8^4:8^3\)
\(12x-64=32\)
\(12x=32+64\)
\(12x=96\)
\(x=\dfrac{96}{12}\)
\(x=8\)
d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)
\(720:\left(41-2x+5\right):5=35\)
\(720:\left(46-2x\right)=35.5\)
\(720:\left(46-2x\right)=175\)
\(46-2x=720:175\)
\(46-2x=\dfrac{144}{35}\)
\(2x=46-\dfrac{144}{35}\)
\(2x=\dfrac{1466}{35}\)
\(x=\dfrac{1466}{35}:2\)
\(x=\dfrac{733}{35}\)
bài 2 tìm x biết
a)128-3(x+4)=23 d)720:[41-(2x-5)]=23.5
b)[(4x+28).3+55]:5 =35 e)123-5.(x+4)=38
c)(12x-43).83=4.84 g)(3x-24).73=2.74
nhớ giúp nhaaaaa
a)128-3(x+4)=23
125.(x+4)=23
( x +4)=23 : 125
x+4 = 0,184
x = 0,184 -4
x = -3 .816
theo mềnh nhóe ( làm từng câu )
c: =>12x-64=32
=>12x=96
hay x=8
g: =>3x-16=14
hay x=10
e: =>5(x+4)=85
=>x+4=17
hay x=13
Tìm x , biết
a.128 - 3 ×( x +2 ) =23
b. ( 12 × x -64 ) × 8 = 4,64
c. [( 4 × x +28) × 3 + 55 ] : 5 = 35
d. 720 : [ 41 - ( 2 × x - 5 )] = 8 × 5
a. 128 - 3 x (X + 2) = 23
3 x (X + 2) = 128 - 23
X + 2 = 105 : 3
X = 35 - 2
X = 33
b. (12 x X - 64) x 8 = 4,64
12 x X - 64 = 4,64 : 8
12 x X = 0,58 + 64
X = 64,58 : 12
X = \(\frac{3229}{600}\)
c. [(4 x X + 28) x 3 + 55] : 5 = 35
[(4 x X + 28) x 3 + 55] = 35 x 5
(4 x X + 28) x 3 = 175 - 55
4 x X + 28 = 120 : 3
4 x X = 40 - 28
X = 12 : 4
X = 3
d. 720 : [41 - (2 x X - 5)] = 8 x 5
41 - (2 x X - 5) = 720 : (8 x 5)
2 x X - 5 = 41 - 18
2 x X = 23 + 5
X = 28 : 2
X = 14
x nhỏ : dấu nhân
X lớn : X
Tìm số tự nhiên x biết:
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
Tìm x biết:
a, (x+1)+(x+2)+...+(x+199)=0
b, (x=30)+(x-29)+(x-28)=11
c, x+(x-1)+(x-2)+...+(x-100)=0
d, 123-3.(x+4)=23
e, [(14x+26).3+55] : 5 =35
f, 720:[41-(2x-5)]= 23.5
g, (2x-4).(48-12x)2=0
h, (3-x).(4-2x).(x+10)=0
i, |x-7|+13=25
k, |x-3|-16=-4
l, 26-|x+9|=-13
Giúp mk nha!
a, ( x + 1 ) + ( x + 2 ) + ... + ( x + 199 ) = 0
x + 1 + x + 2 + ... + x + 199 = 0
( x + x + ... + x ) + ( 1 + 2 + ... + 199 ) = 0
199x + 19900 = 0
199x = 0 - 19900
199x = -19900
x = -19900 : 199
x = -100
Vậy ...
b, ( x - 30 ) + ( x - 29 ) + ( x - 28 ) = 11
x - 30 + x - 29 + x - 28 = 11
( x + x + x ) - ( 30 + 29 + 28 ) = 11
3x - 87 = 11
3x = 11 + 87
3x = 98
x = \(\frac{98}{3}\)
Vậy ...
123 - 3 ( x + 4 ) = 23
3 ( x + 4 ) = 123 - 23
3 ( x + 4 ) = 100
x + 4 = \(\frac{100}{3}\)
x = \(\frac{100}{3}-4\)
x = \(\frac{88}{3}\)
Vậy ...
bài1:
a)128-3(x+4)=23
b)[(4x+28).3+55]:5=35
c)(12-4^3).8^3=4.8^4
d)720:[41-(2x-5)]=2^3.5
e)2^x+2^x+1=48
f)(x-2)^2=(x-2)^4
128-3(x+4)=23
3(x+4)=128-23
3(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
Vậy x=31
Học tốt
tìm x
128 - 3 . ( x + 4 ) = 23
[ ( 4x +28 ) . 3 + 55 ] : 5 = 35
( 12x - 4^3 ) . 8^3 = 4.8^4
720 : [ 41 - ( 2x - 5 )] = 2^3 . 5
128-3.(x+4) =23
3.(x+4) =128-23
3.(x+4) = 105
x+4 =105:3
x+4 =35
x = 35-4
x=31