\(\dfrac{-1}{3}< \dfrac{?}{36}< \dfrac{?}{18}< \dfrac{-1}{4}\)
Những câu hỏi liên quan
SGK Kết nối tri thức với cuộc sống - Trang 63
23 tháng 8 2023 lúc 23:34
Rút gọn rồi quy đồng mẫu số các phân số (theo mẫu).Mẫu: dfrac{5}{15} và dfrac{4}{18}- dfrac{5}{15}dfrac{1}{3}; dfrac{4}{18}dfrac{2}{9} - dfrac{1}{3}dfrac{1times3}{3times3}dfrac{3}{9}a) dfrac{2}{36} và dfrac{8}{12}b) dfrac{10}{25} và dfrac{14}{40}
Đọc tiếp
Rút gọn rồi quy đồng mẫu số các phân số (theo mẫu).
Mẫu: \(\dfrac{5}{15}\) và \(\dfrac{4}{18}\) - \(\dfrac{5}{15}=\dfrac{1}{3}\); \(\dfrac{4}{18}=\dfrac{2}{9}\) - \(\dfrac{1}{3}=\dfrac{1\times3}{3\times3}=\dfrac{3}{9}\) |
a) \(\dfrac{2}{36}\) và \(\dfrac{8}{12}\)
b) \(\dfrac{10}{25}\) và \(\dfrac{14}{40}\)
a) \(\dfrac{2}{36}=\dfrac{1}{18}\)
\(\dfrac{8}{12}=\dfrac{2}{3}\)
b) \(\dfrac{10}{25}=\dfrac{2}{5}\)
\(\dfrac{14}{40}=\dfrac{7}{20}\)
Đúng 1
Bình luận (0)
Câu 1 :dfrac{-5}{7}.dfrac{7}{-45};dfrac{-3}{10}.left(-30right);-12.dfrac{-2}{36}Câu 2: dfrac{3}{4}+dfrac{1}{8}.dfrac{-16}{5};dfrac{7}{15}-dfrac{18}{21}.dfrac{7}{9}Câu 3: left(dfrac{-5}{9}+dfrac{3}{5}right).dfrac{3}{10};left(dfrac{3}{9}-dfrac{2}{5}right).dfrac{-3}{10}Câu 4: left(dfrac{3}{7}+dfrac{1}{3}right).left(dfrac{1}{8}-dfrac{1}{2}right);left(dfrac{-9}{12}-dfrac{16}{30}right).left(dfrac{-18}{22}-dfrac{6}{11}right)Càn gấp
Đọc tiếp
Câu 1 :\(\dfrac{-5}{7}.\dfrac{7}{-45}\);\(\dfrac{-3}{10}.\left(-30\right)\);\(-12.\dfrac{-2}{36}\)
Câu 2: \(\dfrac{3}{4}+\dfrac{1}{8}.\dfrac{-16}{5};\dfrac{7}{15}-\dfrac{18}{21}.\dfrac{7}{9}\)
Câu 3: \(\left(\dfrac{-5}{9}+\dfrac{3}{5}\right).\dfrac{3}{10};\left(\dfrac{3}{9}-\dfrac{2}{5}\right).\dfrac{-3}{10}\)
Câu 4: \(\left(\dfrac{3}{7}+\dfrac{1}{3}\right).\left(\dfrac{1}{8}-\dfrac{1}{2}\right);\left(\dfrac{-9}{12}-\dfrac{16}{30}\right).\left(\dfrac{-18}{22}-\dfrac{6}{11}\right)\)
Càn gấp
Câu 1:
\(-\dfrac{5}{7}\cdot\dfrac{7}{-45}=\dfrac{1}{9}\) ; \(-\dfrac{3}{10}\cdot-30=9\) ; \(-12\cdot-\dfrac{2}{36}=\dfrac{2}{3}\)
Caau2;3;4;5,... tự bấm máy tính là ra
Đúng 0
Bình luận (0)
Tính :
a, dfrac{3cdot13-13cdot18}{15cdot40-80};
b, dfrac{18cdot34+left(-18right)cdot124}{-36cdot17+9cdotleft(-52right)};
c, dfrac{dfrac{3}{41}-dfrac{12}{47}+dfrac{27}{53}}{dfrac{4}{41}-dfrac{16}{47}+dfrac{36}{53}}+dfrac{-0,25cdotdfrac{-2}{3}-0,75:left(dfrac{-1}{2}+dfrac{2}{3}right)}{left|-1dfrac{1}{2}right|cdotleft(dfrac{-2}{3}-75%:dfrac{3}{-2}right)}.
Đọc tiếp
Tính :
a, \(\dfrac{3\cdot13-13\cdot18}{15\cdot40-80}\);
b, \(\dfrac{18\cdot34+\left(-18\right)\cdot124}{-36\cdot17+9\cdot\left(-52\right)}\);
c, \(\dfrac{\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}}{\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}}+\dfrac{-0,25\cdot\dfrac{-2}{3}-0,75:\left(\dfrac{-1}{2}+\dfrac{2}{3}\right)}{\left|-1\dfrac{1}{2}\right|\cdot\left(\dfrac{-2}{3}-75\%:\dfrac{3}{-2}\right)}\).
a: \(=\dfrac{13\left(3-18\right)}{40\left(15-2\right)}=\dfrac{13}{15-2}\cdot\dfrac{-15}{40}=\dfrac{-3}{8}\)
b: \(=\dfrac{18\left(34-124\right)}{36\left(-17-13\right)}=\dfrac{1}{2}\cdot\dfrac{-90}{-30}=\dfrac{3}{2}\)
c: \(=\dfrac{3\left(\dfrac{1}{41}-\dfrac{4}{47}+\dfrac{9}{53}\right)}{4\left(\dfrac{1}{41}-\dfrac{4}{47}+\dfrac{9}{53}\right)}+\dfrac{\dfrac{-1}{4}\cdot\dfrac{-2}{3}-\dfrac{3}{4}:\dfrac{1}{6}}{\dfrac{3}{2}\cdot\left(\dfrac{-2}{3}-\dfrac{3}{4}\cdot\dfrac{-2}{3}\right)}\)
\(=\dfrac{3}{4}+\dfrac{\dfrac{2}{12}-\dfrac{9}{2}}{\dfrac{3}{2}\cdot\dfrac{-1}{6}}=\dfrac{3}{4}+\dfrac{-13}{3}:\dfrac{-3}{12}=\dfrac{3}{4}+\dfrac{13}{3}\cdot\dfrac{12}{3}\)
\(=\dfrac{3}{4}+\dfrac{156}{9}=\dfrac{217}{12}\)
Đúng 1
Bình luận (0)
Tính nhanh :
\(C=\dfrac{1}{3}+\dfrac{-3}{4}+\dfrac{3}{5}+\dfrac{1}{57}+\dfrac{-1}{36}+\dfrac{1}{15}+\dfrac{-2}{9}\)
\(D=\dfrac{1}{2}+\dfrac{-1}{5}+\dfrac{-5}{7}+\dfrac{1}{6}+\dfrac{-3}{35}+\dfrac{1}{3}+\dfrac{1}{41}\)
\(E=\dfrac{-1}{2}+\dfrac{3}{5}+\dfrac{-1}{9}+\dfrac{1}{127}+\dfrac{-7}{18}+\dfrac{4}{35}+\dfrac{2}{7}\)
\(D=\dfrac{1}{2}+\dfrac{-1}{5}+\dfrac{-5}{7}+\dfrac{1}{6}+\dfrac{-3}{35}+\dfrac{1}{3}+\dfrac{1}{41}\)
\(D=\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{3}\right)+\left(\dfrac{-1}{5}+\dfrac{-5}{7}+\dfrac{-3}{35}\right)+\dfrac{1}{41}\)
\(D=1+-1+\dfrac{1}{41}\)
\(D=0+\dfrac{1}{41}\)
\(D=\dfrac{1}{41}\)
Đúng 0
Bình luận (0)
\(C=\left(\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}\right)+\left(\dfrac{-3}{4}+\dfrac{-1}{36}+\dfrac{-2}{9}\right)+\dfrac{1}{57}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-1-8}{36}+\dfrac{1}{57}\)
=1/57
\(E=\left(-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\left(\dfrac{3}{5}+\dfrac{4}{35}+\dfrac{2}{7}\right)+\dfrac{1}{127}=\dfrac{1}{127}\)
Đúng 0
Bình luận (0)
C1. Điền số thích hợp vào chỗ trống :
\(\dfrac{-1}{3}< \dfrac{...}{36}< \dfrac{...}{18}< \dfrac{-1}{4}\)
C2.Lớp 6A có \(\dfrac{4}{5}\) hs thích bóng bàn , \(\dfrac{7}{10}\) hs thích bóng chuyền , \(\dfrac{23}{25}\) hs thích bóng đá . Môn bóng nào được hs lớp 6A yêu thích nhất ?
thực hiện phép tínhdfrac{16}{103}+(38+dfrac{-16}{103})dfrac{100}{91}+310+dfrac{-9}{91}dfrac{-13}{49}+(dfrac{-36}{49}+41)dfrac{-10}{71}:1dfrac{4}{71}dfrac{4}{15}+dfrac{8}{15}:2 -dfrac{1}{18}.left(-3right)^2
Đọc tiếp
thực hiện phép tính
\(\dfrac{16}{103}\)+(38+\(\dfrac{-16}{103}\))
\(\dfrac{100}{91}\)+310+\(\dfrac{-9}{91}\)
\(\dfrac{-13}{49}\)+(\(\dfrac{-36}{49}\)+41)
\(\dfrac{-10}{71}\):1\(\dfrac{4}{71}\)
\(\dfrac{4}{15}\)+\(\dfrac{8}{15}\):2 -\(\dfrac{1}{18}\).\(\left(-3\right)^2\)
`16/803+38+(-16/803)`
`=16/803-16/803+38`
`=0+38=38`
Đúng 0
Bình luận (0)
`100/91+310-9/91`
`=100/91-9/91+310`
`=1+310=311`
Đúng 0
Bình luận (1)
\(\dfrac{16}{103}+\left(38+\dfrac{-16}{103}\right)\)
\(=\dfrac{16}{103}+38+\dfrac{-16}{103}\)
\(=\dfrac{16}{103}+\dfrac{-16}{103}+38\)
\(=0+38\)
\(=38\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
BT2: Tính nhanh
9) (\(\left(5+\dfrac{1}{5}-\dfrac{2}{9}\right)-\left(2-\dfrac{1}{23}-2\dfrac{3}{35}+\dfrac{5}{6}\right)-\left(8+\dfrac{2}{7}-\dfrac{1}{18}\right)\)
10)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
9:
\(=5+\dfrac{1}{5}-\dfrac{2}{9}-2+\dfrac{1}{23}+\dfrac{73}{35}-\dfrac{5}{6}-8-\dfrac{2}{7}+\dfrac{1}{18}\)
\(=\left(5-2-8\right)+\left(\dfrac{1}{5}+\dfrac{73}{35}-\dfrac{2}{7}\right)+\left(-\dfrac{2}{9}+\dfrac{1}{18}-\dfrac{5}{6}\right)+\dfrac{1}{23}\)
\(=\left(-5\right)+\dfrac{7+73-10}{35}+\dfrac{-4+1-15}{18}+\dfrac{1}{23}\)
\(=-5+2-1+\dfrac{1}{23}=-4+\dfrac{1}{23}=-\dfrac{91}{23}\)
10: \(=\left(\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}\right)+\left(\dfrac{-3}{4}-\dfrac{2}{9}-\dfrac{1}{36}\right)+\dfrac{1}{64}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-8-1}{36}+\dfrac{1}{64}\)
=1/64
Đúng 0
Bình luận (0)
26 tháng 2 2022 lúc 10:47
Bài 1.Tính
a)\(\dfrac{4}{28}\)+\(\dfrac{12}{36}\) b)\(\dfrac{-12}{18}\)+\(\dfrac{15}{-21}\) c)\(\dfrac{14}{28}\)-\(\dfrac{-16}{32}\)-\(\dfrac{17}{51}\)
\(a,\dfrac{1}{7}+\dfrac{1}{3}=\dfrac{3}{21}+\dfrac{7}{21}=\dfrac{10}{21}\\ b,\dfrac{-2}{3}+\dfrac{-5}{7}=\dfrac{-14+\left(-15\right)}{21}=\dfrac{-29}{21}\\ c,\dfrac{1}{2}-\dfrac{-1}{2}-\dfrac{1}{3}=\dfrac{3+3-2}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
Đúng 6
Bình luận (1)
\(a.\dfrac{4}{28}+\dfrac{12}{36}=\dfrac{1}{7}+\dfrac{1}{3}=\dfrac{3}{21}+\dfrac{7}{21}=\dfrac{10}{21}\\ b.\dfrac{-12}{18}+\dfrac{-15}{21}=\dfrac{-2}{3}+\dfrac{-5}{7}=\dfrac{-14}{21}+\dfrac{-15}{21}=\dfrac{-29}{21}\\ c.\dfrac{14}{28}+\dfrac{16}{32}-\dfrac{17}{51}=\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{17}{51}=1-\dfrac{17}{51}=\dfrac{2}{3}\)
Đúng 1
Bình luận (0)
\(\dfrac{4}{28}+\dfrac{12}{36}=\dfrac{144}{1008}+\dfrac{336}{1008}=\\ \dfrac{480}{1008}=\dfrac{10}{21}\)
Câu b và c em làm tương tự.
Đúng 1
Bình luận (4)
20 tháng 12 2021 lúc 22:10
a, 1dfrac{5}{18}+dfrac{7}{25}-dfrac{5}{18}+dfrac{18}{25}-0, 75b, dfrac{2}{5}.dfrac{1}{3}-dfrac{4}{3}.dfrac{2}{5}c, (dfrac{-1}{4}).( 6dfrac{2}{11}) + 3 dfrac{9}{11}.(dfrac{-1}{4})d, 4. (-dfrac{1}{2})^{3_{ }}-_{ }2. (dfrac{-1}{2})^2 + 3. (dfrac{-1}{2}) + 1e, dfrac{1}{6}-(dfrac{2}{3})^2 + dfrac{5}{18}f, (dfrac{4}{3}-dfrac{3}{2})^2- 2.|-dfrac{1}{9}| + (-dfrac{5}{18})
Đọc tiếp
a, 1\(\dfrac{5}{18}\)+\(\dfrac{7}{25}\)-\(\dfrac{5}{18}\)+\(\dfrac{18}{25}\)-0, 75
b, \(\dfrac{2}{5}\).\(\dfrac{1}{3}\)-\(\dfrac{4}{3}\).\(\dfrac{2}{5}\)
c, (\(\dfrac{-1}{4}\)).( 6\(\dfrac{2}{11}\)) + 3 \(\dfrac{9}{11}\).(\(\dfrac{-1}{4}\))
d, 4. (-\(\dfrac{1}{2}\))\(^{3_{ }}\)-\(_{ }\)2. (\(\dfrac{-1}{2}\))\(^2\) + 3. (\(\dfrac{-1}{2}\)) + 1
e, \(\dfrac{1}{6}\)-(\(\dfrac{2}{3}\))\(^2\) + \(\dfrac{5}{18}\)
f, (\(\dfrac{4}{3}\)-\(\dfrac{3}{2}\))\(^2\)- 2.|-\(\dfrac{1}{9}\)| + (-\(\dfrac{5}{18}\))
e: \(=\dfrac{1}{6}-\dfrac{4}{9}+\dfrac{5}{18}=\dfrac{3-8+5}{18}=0\)
Đúng 0
Bình luận (0)