\(-\dfrac{1}{3}< \dfrac{x}{36}< \dfrac{y}{18}< -\dfrac{1}{4}\)
\(\Leftrightarrow\dfrac{-12}{36}< \dfrac{x}{36}< \dfrac{2y}{35}< \dfrac{-9}{36}\)
\(\Leftrightarrow-12< x< y< -9\)
\(\left(x,y\right)=\left(-11,-10\right)\)
Ta có: \(\dfrac{-1}{3}< \dfrac{x}{36}< \dfrac{y}{18}< \dfrac{-1}{4}\)
\(\Leftrightarrow\dfrac{-12}{36}< \dfrac{x}{36}< \dfrac{2y}{36}< \dfrac{-9}{36}\)
Suy ra: -12<x<2y<-9
\(\Leftrightarrow\left(x,y\right)\in\left\{\left(-11;-5\right)\right\}\)
Giải:
\(-\dfrac{1}{3}< \dfrac{x}{36}< \dfrac{y}{18}< -\dfrac{1}{4}\)
\(\Rightarrow-\dfrac{12}{36}< \dfrac{x}{36}< \dfrac{2y}{36}< -\dfrac{9}{36}\)
\(\Rightarrow-12< x< 2y< -9\)
\(\Rightarrow\left(x;y\right)=\left\{\left(-11;-5\right)\right\}\)
Chúc bạn học tốt!