Ta có:\(\frac{2-x}{2011}-1=\frac{1-x}{2012}-\frac{x}{2013}\)
<=> \(\frac{2013-x}{2011}-1=\frac{2013-x}{2012}-\frac{x}{2013}\)
<=>\(\frac{2013-x}{2011}-\frac{x-2013}{2013}-\frac{2013-x}{2012}=0\)
<=>\(\left(2013-x\right)\left(\frac{1}{2011}+\frac{1}{2013}-\frac{1}{2012}\right)=0\)
<=>\(2013-x=\frac{0}{\frac{1}{2011}+\frac{1}{2013}-\frac{1}{2012}}=0\)
<=>\(x=0+2013=2013\)
Vậy \(x=2013\)