2x^2-4xy+5y^2-4x-2y+5=0
Những câu hỏi liên quan
Tìm x,y biết:
a, 2x2 + 3y2 + 4xy - 8x - 2y + 17 = 0
b, 4x2 + 5y2 - 18x + 4x - 4xy + 35 = 0
c, x2 + 2xy + 5y2 - 4x - 8y + 2019 = 0
Chứng minh rằng:
a)x^2+5y^2+2x-4xy-10y+14>0
b)5x^2+10y^2-6xy-4x-2y+3>0
Chứng minh rằng:
B = x^2-4xy+5y^2+2x-10y+14 > 0
C = 5x^2-10y^2-6xy-4x-2y+3 > 0
a) x^2+!x-3!=4xy-4y^2
b)x^2+5y^2+2xy+4x+5
c)x^2-2x+y^2+4yz+4z^2+6=0
d)y^2+2y+4-2^x+2+2=0
Phân tích mỗi đa thức sau thành nhân tử
a)x^3-2x^2y+xy^2+xy
b)x^3+4x^2y+4xy^2-9x
c)x^3-y^3+x-y
d)4x^2-4xy+2x-y+y^2
e)9x^2-3x+2y-4y^2
f)3x^2-6xy+3y^2-5x+5y
a) Xem lại đề
b) x³ - 4x²y + 4xy² - 9x
= x(x² - 4xy + 4y² - 9)
= x[(x² - 4xy + 4y² - 3²]
= x[(x - 2y)² - 3²]
= x(x - 2y - 3)(x - 2y + 3)
c) x³ - y³ + x - y
= (x³ - y³) + (x - y)
= (x - y)(x² + xy + y²) + (x - y)
= (x - y)(x² + xy + y² + 1)
d) 4x² - 4xy + 2x - y + y²
= (4x² - 4xy + y²) + (2x - y)
= (2x - y)² + (2x - y)
= (2x - y)(2x - y + 1)
e) 9x² - 3x + 2y - 4y²
= (9x² - 4y²) - (3x - 2y)
= (3x - 2y)(3x + 2y) - (3x - 2y)
= (3x - 2y)(3x + 2y - 1)
f) 3x² - 6xy + 3y² - 5x + 5y
= (3x² - 6xy + 3y²) - (5x - 5y)
= 3(x² - 2xy + y²) - 5(x - y)
= 3(x - y)² - 5(x - y)
= (x - y)[(3(x - y) - 5]
= (x - y)(3x - 3y - 5)
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tìm gtln.gtnn d=3x-2x^2-4
e=2x^2+5y^2-4xy-4x+2y+3
Tìm x, y biết:a, 2x2 - 8x + y2 + 2y + 9 0b, x2 + y2 + x - xy + 1/2 0c, x2 - 4xy + 92 + 9 2xy + 6x - x2d, 5x2 + 5y2 + 8xy + 2y - 2x + 2 0e, 4x2 + 13y2 +12xy + 4x - 2y + 5 0f, x2 + 2y2 - 2xy + 2x + 2 - 4y 0g, 8x3 + (x + 8)2 8(x + 2)(x2 - 2x + 4)h, (3x +1)(9x2 + 1 - 3x) - (3 - x)2 (3x - 2)3i, 2x2 + 5y2 - 4xy - 4x - 14y + 29 0j, 4x2 + 9y2 - 12x - 32y - 2xy + 44 0
Đọc tiếp
Tìm x, y biết:
a, 2x2 - 8x + y2 + 2y + 9 = 0
b, x2 + y2 + x - xy + 1/2 = 0
c, x2 - 4xy + 92 + 9 = 2xy + 6x - x2
d, 5x2 + 5y2 + 8xy + 2y - 2x + 2 = 0
e, 4x2 + 13y2 +12xy + 4x - 2y + 5 =0
f, x2 + 2y2 - 2xy + 2x + 2 - 4y = 0
g, 8x3 + (x + 8)2 = 8(x + 2)(x2 - 2x + 4)
h, (3x +1)(9x2 + 1 - 3x) - (3 - x)2 = (3x - 2)3
i, 2x2 + 5y2 - 4xy - 4x - 14y + 29 = 0
j, 4x2 + 9y2 - 12x - 32y - 2xy + 44 = 0
1, Tìm x, y biết:a, 2x2 - 8x + y2 + 2y + 9 0b, x2 + y2 + x - xy + 1/2 0c, x2 - 4xy + 92 + 9 2xy + 6x - x2d, 5x2 + 5y2 + 8xy + 2y - 2x + 2 0e, 4x2 + 13y2 +12xy + 4x - 2y + 5 0f, x2 + 2y2 - 2xy + 2x + 2 - 4y 0g, 8x3 + (x + 8)2 8(x + 2)(x2 - 2x + 4)h, (3x +1)(9x2 + 1 - 3x) - (3 - x)2 (3x - 2)3i, 2x2 + 5y2 - 4xy - 4x - 14y + 29 0j, 4x2 + 9y2 - 12x - 32y - 2xy + 44 0v
Đọc tiếp
1, Tìm x, y biết:
a, 2x2 - 8x + y2 + 2y + 9 = 0
b, x2 + y2 + x - xy + 1/2 = 0
c, x2 - 4xy + 92 + 9 = 2xy + 6x - x2
d, 5x2 + 5y2 + 8xy + 2y - 2x + 2 = 0
e, 4x2 + 13y2 +12xy + 4x - 2y + 5 =0
f, x2 + 2y2 - 2xy + 2x + 2 - 4y = 0
g, 8x3 + (x + 8)2 = 8(x + 2)(x2 - 2x + 4)
h, (3x +1)(9x2 + 1 - 3x) - (3 - x)2 = (3x - 2)3
i, 2x2 + 5y2 - 4xy - 4x - 14y + 29 = 0
j, 4x2 + 9y2 - 12x - 32y - 2xy + 44 = 0v
a,\(2x^2-8x+y^2+2y+9=0\)
\(\Rightarrow2\left(x^2-4x+4\right)+\left(y^2+2y+1\right)=0\)
\(\Rightarrow2\left(x-2\right)^2+\left(y+1\right)^2=0\)
Mà \(2\left(x-2\right)^2\ge0\forall x\); \(\left(y+1\right)^2\ge0\forall y\)
\(\Rightarrow2\left(x-2\right)^2+\left(y+1\right)^2\ge0\forall x;y\)
Dấu "=" xảy ra<=> \(\hept{\begin{cases}2\left(x-2\right)^2=0\\\left(y+1\right)^2=0\end{cases}\Rightarrow\hept{\begin{cases}x=2\\y=-1\end{cases}}}\)
Vậy x=2;y=-1
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a) x^2+4x+4-y^2
b) x^2-16-4xy+4y^2
c) x^3+2x^2y +xy^2
d) 5x+5y-x^2-2xy-y^2
e) x^5-x^4+x^3-x^2
a) \(x^2+4x+4-y^2\)
\(=\left(x^2+2.x.2+2^2\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
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\(a,=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\\ b=\left(x-2y\right)^2-16=\left(x-2y-4\right)\left(x-2y+4\right)\\ c,=x\left(x^2+2xy+y^2\right)=x\left(x+y\right)^2\\ d,=5\left(x+y\right)-\left(x+y\right)^2=\left(5-x-y\right)\left(x+y\right)\\ e,=x^4\left(x-1\right)+x^2\left(x-1\right)\\ =x^2\left(x^2+1\right)\left(x-1\right)\)
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a: \(x^2+4x+4-y^2=\left(x+2-y\right)\left(x+2+y\right)\)
b: \(x^2-4xy+4y^2-16=\left(x-2y-4\right)\left(x-2y+4\right)\)
c: \(x^3+2x^2y+xy^2=x\left(x^2+2xy+y^2\right)=x\left(x+y\right)^2\)
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