bạn j ơi câu hỏi dễ thế này mà cũng hỏi là sao

nếu bạn cấp 1 thì thôi mà bạn học cấp 2 thì bạn nên cố gắng nhiều hơn nhé 

mình sẽ giải chi tiết để bạn bt cách làm:

(136/15-28/5+62/10).21/24

=(272/30-168/30+186/30).21/24

=290/30.21/24

=chắc đến đây bạn làm đc rồi pp

203/24

Thôi cậu ấy ko bít làm mà ,để tớ giải cho .​​

(136/15-28/5+62/10).21/24

=(272/30-168/30+186/30).21/24

=(104/30+186/30).21/24

=290/30.21/24

=29/3.7/8

=203/24

= 203/24

\(\left(\frac{136}{15}-\frac{28}{5}+\frac{62}{10}\right)\cdot\frac{21}{24}\)

=

\(=\left(\frac{272}{30}+-\frac{168}{30}+\frac{186}{30}\right).\frac{7}{8}\)\(=\frac{29}{3}.\frac{7}{8}=\frac{203}{24}\)

\(\left(\frac{136}{15}-\frac{28}{5}+\frac{62}{10}\right).\frac{21}{24}\)

\(=\left(\frac{136}{15}-\frac{28}{5}+\frac{31}{5}\right).\frac{21}{24}\)

\(=\left[\frac{136}{15}-\left(\frac{28}{5}-\frac{31}{5}\right)\right].\frac{21}{24}\)

\(=\left(\frac{136}{15}+\frac{3}{5}\right).\frac{21}{24}\)

\(=\frac{29}{3}.\frac{21}{24}\)

\(=\frac{203}{24}\)

Study well ! >_<

\(\frac{203}{24}\)

\(F=\dfrac{5}{6}+6\dfrac{5}{6}\left(11\dfrac{5}{20}-9\dfrac{1}{4}\right):8\dfrac{1}{3}\)

\(F=\dfrac{5}{6}+\dfrac{41}{6}\left(\dfrac{225}{20}-\dfrac{37}{4}\right):\dfrac{25}{3}\)

\(F=\dfrac{5}{6}+\dfrac{41}{6}.2.\dfrac{3}{25}\)

\(F=\dfrac{5}{6}+\dfrac{41}{25}.\dfrac{3}{25}\)

\(F=\dfrac{5}{6}+\dfrac{41}{25}\)

\(F=\dfrac{371}{150}\)

\(D=\left(\dfrac{136}{15}-\dfrac{28}{5}+\dfrac{62}{10}\right)\times\dfrac{21}{24}\)

\(D=\left(\dfrac{272}{30}-\dfrac{168}{30}+\dfrac{186}{30}\right)\times\dfrac{21}{24}\)

\(D=\dfrac{290}{30}\times\dfrac{21}{24}\)

\(D=\dfrac{29}{3}\times\dfrac{7}{8}\)

\(D=\dfrac{203}{24}\)

b)B=(136/15 - 28/5 +31/5)^.21/24

    B=(136/15-(28/5 - 31/5)^.21/24

     B=(136/15 + 3/5)^.21/24

      B=29/3^.21/24

      B=203/24

\(A=1.2.3...100-1.2.3...99-1.2.3...98.99^2\)

\(=1.2.3...99\left(100-1-99\right)\)

\(=1.2.3...99.0=0\)