a)\(=\dfrac{3}{3}+\dfrac{4}{3}=\dfrac{7}{3}\)

b)\(=\dfrac{5}{9}\times\dfrac{3}{2}=\dfrac{15}{18}=\dfrac{5}{6}\)

d)\(=\left(\dfrac{12}{8}-\dfrac{3}{8}\right)\times2=\dfrac{9}{8}\times2=\dfrac{18}{8}=\dfrac{9}{4}\)

c)\(=\dfrac{4}{3}-\dfrac{5}{6}=\dfrac{8}{6}-\dfrac{5}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)

a) 1 + 4/3 = 7/3

b) 5/9 : 2/3 = 5/6

c ) 4/3 -1/3 x 5/2

= 1 x 5/2

= 5/2

d) ( 3/2 - 3/8) : 1/2

= 9/8 : 1/2

= 9/4

e) 15/16 : 3/8 x 3/4 

= 5/2 x 3/4

= 15/8

f) 7/19 x 1/3 x 7/19 x 2/3

= 7/19 x (1/3 x 2/3)

= 7/19 x 2/9

= 14/171

g) 3/5 x 8/27 x 25/3

= 3/5 x 25/3 x 8/27 

= 5 x 8/27

= 40/27

h) 1/5 + 4/11 + 4/5 + 7/11

= (1/5 + 4/5) + (4/11 + 7/11)

= 1 + 1

= 2

e)\(\dfrac{15}{16}\times\dfrac{8}{3}\times\dfrac{3}{4}=\dfrac{360}{192}=\dfrac{15}{8}\)

f) \(=\dfrac{7}{19}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{7}{19}\times\dfrac{3}{3}=\dfrac{7}{19}\)

g)\(=\dfrac{600}{120}=\dfrac{600:120}{120:120}=\dfrac{5}{1}=5\)

h)\(=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)

a,C1 
 (5/6 + 5/8) x 2/3
= 35/24 x 2/3
=35/36
C2
 (5/6 + 5/8) x 2/3
= 5/6x2/3 + 5/8x2/3
= 10/18 + 10/24
= 35/36

b,C1
7/5 x 3/4 - 1/2 x 3/4
= 21/20 - 3/8
= 27/40
C2
7/5 x 3/4 - 1/2 x 3/4
=3/4 x (7/5-1/2)
=3/4x9/10
=27/40

a, 5/6 x (1/8x2/3) 

=5/6 x 1/12

=5/72

b,(7/5 - 1/2) x 3/4 

=0,9 x 3/4

=3,06

c,(5/6+5/8) x 2/3

=70/48 x 2/3

=35/36

a, 5/6 x (1/8x2/3) 

=5/6 x 1/12

=5/72

b,(7/5 - 1/2) x 3/4 

=0,9 x 3/4

=3,06

c,(5/6+5/8) x 2/3

=70/48 x 2/3

=35/36

A

\(\frac{3}{5}\div\frac{4}{5}+\frac{1}{2}\times\frac{2}{3}\)

\(=\frac{3}{4}+\frac{1}{3}\)

\(=\frac{13}{12}\)

B

\(\frac{5}{4}\times x=\frac{3}{8}+\frac{1}{4}\)

 \(\frac{5}{4}\times x =\frac{5}{8}\)

\(x=\frac{5}{8}\div\frac{5}{4}\)

\(x=\frac{4}{8}=\frac{1}{2}\)

AI TRA LOI GIUP MINK DI

a: \(\dfrac{x}{6}=\dfrac{8}{3}\)

=>\(x=6\cdot\dfrac{8}{3}=\dfrac{6}{3}\cdot8=8\cdot2=16\)

b: \(\dfrac{5}{x}=\dfrac{4}{9}\)

=>\(x=\dfrac{5\cdot9}{4}=\dfrac{45}{4}\)

c: \(\dfrac{x+3}{-4}=\dfrac{5}{20}\)

=>\(x+3=\dfrac{-4\cdot5}{20}=-1\)

=>x=-1-3=-4

d: \(\dfrac{7}{3+4x}=\dfrac{-2}{9}\)

=>\(4x+3=\dfrac{9\cdot7}{-2}=-\dfrac{63}{2}\)

=>\(4x=-\dfrac{63}{2}-3=-\dfrac{69}{2}\)

=>\(x=-\dfrac{69}{8}\)

f: ĐKXĐ: x<>1

\(\dfrac{3}{x-1}=\dfrac{x-1}{27}\)

=>\(\left(x-1\right)^2=3\cdot27=81\)

=>\(\left[{}\begin{matrix}x-1=9\\x-1=-9\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=10\left(nhận\right)\\x=-8\left(nhận\right)\end{matrix}\right.\)

a) \(\dfrac{3}{5}+x=\dfrac{4}{3}\) 

\(\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}\)

\(\Leftrightarrow x=\dfrac{20}{15}-\dfrac{9}{15}\) 

\(\Leftrightarrow x=\dfrac{11}{15}\)

b) \(x+\dfrac{5}{6}=\dfrac{1}{7}\)

\(\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}\)

\(\Leftrightarrow x=\dfrac{6}{42}-\dfrac{35}{42}\)

\(\Leftrightarrow x=-\dfrac{29}{42}\)

c) \(x\times\dfrac{3}{8}=\dfrac{3}{4}\)

\(\Leftrightarrow x=\dfrac{3}{4}:\dfrac{3}{8}\)

\(\Leftrightarrow x=\dfrac{3}{4}\times\dfrac{8}{3}\)

\(\Leftrightarrow x=2\)

d) \(\dfrac{4}{5}\times x=\dfrac{3}{7}\)

\(\Leftrightarrow x=\dfrac{3}{7}:\dfrac{4}{5}\)

\(\Leftrightarrow x=\dfrac{3}{7}\times\dfrac{5}{4}\)

\(\Leftrightarrow x=\dfrac{15}{28}\)

a, \(\dfrac{3}{5}+x=\dfrac{4}{3}\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}=\dfrac{20-9}{15}=\dfrac{11}{15}\)

b, \(x+\dfrac{5}{6}=\dfrac{1}{7}\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}=\dfrac{6-35}{42}=\dfrac{-29}{42}\)

c, \(\dfrac{3x}{8}=\dfrac{3}{4}\Leftrightarrow\dfrac{3x}{8}=\dfrac{6}{8}\Rightarrow3x=6\Leftrightarrow x=2\)

d, \(\dfrac{4x}{5}=\dfrac{3}{7}\Leftrightarrow\dfrac{28x}{35}=\dfrac{15}{35}\Rightarrow x=\dfrac{15}{28}\)

a, \(\dfrac{3}{5}\) + \(X\) = \(\dfrac{4}{3}\)

           \(X\) = \(\dfrac{4}{3}\) - \(\dfrac{3}{5}\)

           \(X\) = \(\dfrac{11}{15}\)

b, \(X\) + \(\dfrac{5}{6}\) = \(\dfrac{1}{7}\)

    \(X\)        = \(\dfrac{1}{7}\) - \(\dfrac{5}{6}\)

    \(X\)        = -\(\dfrac{29}{42}\)

c, \(X\) x \(\dfrac{3}{8}\) = \(\dfrac{3}{4}\)

    \(X\)       = \(\dfrac{3}{4}\) : \(\dfrac{3}{8}\)

    \(X\)       = 2

d, \(\dfrac{4}{5}\) x \(X\) = \(\dfrac{3}{7}\)

          \(X\) = \(\dfrac{3}{7}\) : \(\dfrac{4}{5}\)

          \(X\) = \(\dfrac{15}{28}\)

#Yu

 3/10 x x=2/5 

x = 2/5:3/10

x = 4/3

1/8 : x  = 1/2 

x = 1/8:1/2

x= 1/4

5/6 : 3/4  = 5/6x4/2= 10/9

1: 2/3= 1/1 x 3/2= 3/2

5/6 + 3/4  = 19/12

1 + 2/3= 1/1+2/3= 5/3

 5/6 - 3/4 = 1/12

1 - 2/3= 1/1-2/3= 1/3

5/6 x 3/4= 5/8

1/1x2/3= 2/3

\(a\dfrac{3\times8\times7}{7\times11\times3}=\dfrac{8}{11}\)

\(b\dfrac{4}{15}\times\left(\dfrac{3}{8}+\dfrac{5}{8}\right)=\dfrac{4}{15}\times1=\dfrac{4}{15}\)

a)8/11

b) (3/8+5/8) x 4/15= 1 x 4/15= 4/15

Bài 1: 

c) ĐKXĐ: \(x\notin\left\{\dfrac{1}{4};-\dfrac{1}{4}\right\}\)

Ta có: \(\dfrac{3}{1-4x}=\dfrac{2}{4x+1}-\dfrac{8+6x}{16x^2-1}\)

\(\Leftrightarrow\dfrac{-3\left(4x+1\right)}{\left(4x-1\right)\left(4x+1\right)}=\dfrac{2\left(4x-1\right)}{\left(4x+1\right)\left(4x-1\right)}-\dfrac{6x+8}{\left(4x-1\right)\left(4x+1\right)}\)

Suy ra: \(-12x-3=8x-2-6x-8\)

\(\Leftrightarrow-12x-3-2x+10=0\)

\(\Leftrightarrow-14x+7=0\)

\(\Leftrightarrow-14x=-7\)

\(\Leftrightarrow x=\dfrac{1}{2}\)(nhận)

Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)

a: \(=\dfrac{3}{5}\cdot\dfrac{5}{4}+\dfrac{1}{2}\cdot\dfrac{2}{3}=\dfrac{3}{4}+\dfrac{1}{3}=\dfrac{9+4}{12}=\dfrac{13}{12}\)

b: \(\Leftrightarrow x\cdot\dfrac{5}{4}=\dfrac{5}{8}\)

hay x=1/2