\(-36+24x-x^2\)

\(=-x^2+24x-36\)

\(=-x^2+24x-144+108\)

\(=-\left(x^2-24x+144\right)+108\)

\(=-\left(x-12\right)^2+108\le108\)

Đẳng thức xảy ra khi \(x=12\)

\(\left(x-3\right)\left(x-10\right)\left(x-5\right)\left(x-6\right)-24x^2\)

\(=\left(x^2+30-13x\right)\left(x^2+30-11x\right)-24x^2\)

\(=\left(x^2+30x-12x-x\right)\left(x^2+30x-12x+x\right)-24x^2\)

\(=\left(x^2+30-12x\right)^2-x^2-24x^2\)

\(=\left(x^2-12x+30\right)^2-\left(5x\right)^2\)

\(=\left(x^2-12x+30+5x\right)\left(x^2-12x+30-5x\right)\)

\(=\left(x^2-7x+30\right)\left(x^2-17x+30\right)\)

\(x\left(y-1\right)-y\left(y-1\right)\)

\(=\left(y-1\right)\left(x-y\right)\)

_________________

\(5x\left(x-2\right)-x+2\)

\(=5x\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(5x-1\right)\)

_________________

\(5x\left(x+1\right)-8x-8\)

\(=5x\left(x+1\right)-\left(8x+8\right)\)

\(=5x\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(5x-8\right)\)

\(x^2-24x-8\)

\(x^2-2.12x+144-152\)

\(\Leftrightarrow\left(x-12\right)^2-152\)

\(\Leftrightarrow\left(x-12-\sqrt{152}\right)\left(x-12+\sqrt{152}\right)\)

P/s tham khảo nha

tên của mày nói lên tất cả , ko cần bít đề đúng hay sai , tao cứ đăng thôi :)) 

=8x^2+12x=4x(2x+3)

\(x^2+7x^2+12x=8x^2+12x=4x\left(2x+3\right)\)

\(9x^2-24x+15=\left(3x\right)^2-2.3.4x+4^2-1\)

\(=\left(3x-4\right)^2-1=\left(3x-4+1\right)\left(3x-4-1\right)=\left(3x-3\right)\left(3x-5\right)\)

x¹⁰+x⁸+16x²+24x+16=x²(x⁸+x⁶+16+24/x+16/x²)

1, =x^2 + 2.x.7 + 7^2 = (x+7)^2

2,  =(3x^2)^2 + 2 .3 x^2.4 +4^2 = ( 3x^2 + 4 )^2

3, =(5x)^2 - 2 .5x.2y + (2y)^2 = (5x + 2y) ^2

1)x^2+14x+49=x^2+2.7x+7^2=(x+7)^2

2)9x^4+24x^2+16=(3x^2)^2+2.12x^2+4^2=(3x^2+4)^2

3)25x^2-20xy+4y^2=(5x)^2-2.10xy+(2y)^2=(5x-2y)^2

1 bài tập mình cho bn đây;16-a^2=?

chỗ nào ko hiểu thì hòi mình