\(1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}\)

=\(\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\)

=3-3\4-4x\(\frac{5}{2}\)

=\(\frac{5}{2}\)

5 phan 2

\(1\frac{1}{2}.1\frac{1}{3}.1\frac{1}{4}=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}=2.\frac{5}{4}=\frac{5}{2}\)

=3/2*4/3*5/4...*11/10

=5,5

\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)

\(=1+1+1=3\)

Ta có\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)

\(=\left(\frac{2+4}{6}\right)+\left(\frac{3+9}{12}\right)+\left(\frac{4+16}{20}\right)\)

\(=\frac{6}{6}+\frac{12}{12}+\frac{20}{20}\)

\(=1+1+1\)

\(=3\)

\(a,\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)

\(=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\)

\(b,\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\)

\(=\frac{1\times2\times3}{2\times3\times4}=\frac{1}{4}\)

\(\frac{4}{5}+\frac{2}{35}\times\frac{7}{2}=\frac{4}{5}+\frac{1}{5}=1\)

\(\frac{4}{5}+\left(\frac{1}{5}-\frac{1}{7}\right):\frac{2}{7}\)

\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\frac{1}{7}:\frac{2}{7}\)

\(=\frac{5}{5}-\frac{1}{2}\)

\(=1-\frac{1}{2}=\frac{1}{2}\)

cái này khó quá nâng cao à

khó quá vậy giống nâng cao

\(=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{1}{55}=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+....+\frac{2}{110}=2\times\left(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+...+\frac{1}{10\times11}\right)\)

\(=2\times\left(\frac{1}{2}-\frac{1}{11}\right)=1-\frac{2}{11}=\frac{9}{11}\)

\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)

\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)

\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)

\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)

\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)

\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)

c,d tương tự 

A) \(\frac{2}{3}\). \(\frac{4}{5}\)+ \(\frac{1}{3}\). \(\frac{4}{5}\)    B) \(\frac{1}{2}\). \(\frac{4}{5}\)+ \(\frac{1}{6}\): \(\frac{3}{4}\)      C) \(\frac{2}{3}\). \(\frac{4}{5}\)- \(\frac{1}{3}\). \(\frac{4}{5}\)         

= \(\left(\frac{2+1}{3}\right)\). \(\frac{4}{5}\)                =  \(\frac{2}{5}\)+ \(\frac{2}{9}\)                         = \(\frac{2}{3}\)- \(\frac{1}{3}\). \(\left(\frac{4-4}{5}\right)\)

= 1 . \(\frac{4}{5}\)                                   = \(\frac{28}{45}\)                                   = \(\frac{1}{3}\). 0

= \(\frac{4}{5}\)                                                                                         = 0

1/2 + 1/3 + 1/4 + 1/5 + 4/5 + 3/4 + 2/3 + 1/2

= (1/2 + 1/2) + (1/3 + 2/3) + (1/4 + 3/4) + (1/5 + 4/5)

= 1 + 1 + 1 + 1

= 4