a) 232 - (3x + 2).5 = 2³.5²

232 - (3x + 2).5 = 8.25

232 - 5.(3x + 2) = 200

-5.(3x + 2) = 200 - 232

-5.(3x + 2) = -32

3x + 2 = (-32) : (-5)

3x + 2 = 32/5

3x = 32/5 - 2

3x = 22/5

x = 22/5 : 3

x = 22/15

\(a)232-\left(3x+2\right).5=2^3.5^2\)

\(\Leftrightarrow232-\left(3x+2\right).5=200\)

\(\Leftrightarrow\left(3x+2\right).5=32\)

\(\Leftrightarrow3x+2=6.4\)

\(\Leftrightarrow3x=4.4\)

\(\Leftrightarrow\frac{22}{15}\)

\(b)3.5^x-10^0=74\)

\(\Leftrightarrow3.5^x=75\)

\(\Leftrightarrow5^x=25\)

\(\Leftrightarrow5^x=5^2\)

\(\Leftrightarrow x=2\)

\(c)4^{2x+4}=64\)

\(\Leftrightarrow4^{2x+4}=4^3\)

\(\Leftrightarrow2x+4=3\)

\(\Leftrightarrow x=-\frac{1}{2}\)

\(d)5^{x-1}+5^x=100\)

\(\Leftrightarrow5^x.\frac{1}{5}+5^x=100\)

\(\Leftrightarrow5^x\left(\frac{1}{5}+1\right)=100\)

\(\Leftrightarrow5^x=\frac{250}{3}\)

Chưa nghĩ ra. Các câu khác tương tự như các câu trên.

`@` `\text {Ans}`

`\downarrow`

Gửi c!

Bài 1: 

a) \(3x^2\left(2x^3-x+5\right)-6x^5-3x^3+10x^2\)

\(=6x^5-3x^3+10x^2-6x^5-3x^3+10x^2\)

\(=10x^2+10x^2\)

\(=20x^2\)

b) \(-2x\left(x^3-3x^2-x+11\right)-2x^4+3x^3+2x^2-22x\)

\(=-2x^4+6x^3+2x^2-22x-2x^4+3x^3+2x^2-22x\)

\(=-4x^4+9x^3+4x^2-44x\)

4:

a: =>1/4x^2-1/4x^2+2x=-14

=>2x=-14

=>x=-7

b: =>2x^2-8x+3x-12+x^2-2x-5x+10=3x^2-12x-5x+20

=>3x^2-12x-2=3x^2-17x+20

=>5x=22

=>x=22/5

Câu hỏi đâu ạ ? 

câu hỏi điu

dở hơi:D

\(\left(x-2\right)\left(x^2+2x+4\right)+3x-4=\left(x+2\right)\left(x^2-2x+4\right)-x+1\)

\(\Rightarrow\left(x^3-8\right)+3x-4=\left(x^3+8\right)-x+1\)

\(\Rightarrow x^3-8+3x-4=x^3+8-x+1\)

\(\Rightarrow x^3-x^3+3x+x=8+8+4+1\)

\(\Rightarrow4x=21\)

\(\Rightarrow x=\dfrac{21}{5}\)

Bài 2: 

Sửa đề:  \(x^3-3x^2-10x=0\)

\(\Leftrightarrow x\left(x^2-3x-10\right)=0\)

\(\Leftrightarrow x\left(x-5\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\\x=-2\end{matrix}\right.\)

a) (x-2)³+6(x+1)²-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6(x²+2x+1)-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6x²+12x+6-x³+12=0

\(\Rightarrow\)24x+10=0

\(\Rightarrow\)24x=-10

\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)

b)(x-5)(x+5)-(x+3)²+3(x-2)²=(x+1)²-(x-4)(x+4)+3x²

\(\Rightarrow\)x²-25-(x²+6x+9)+3(x²-4x+4)=x²+2x+1-(x²-16)+3x²

\(\Rightarrow\)x²​-25-x²-6x-9+3x²-12x+12=x²+2x+1-x²+16+3x²

\(\Rightarrow\)3x²-18x-22=3x²+2x+17

\(\Rightarrow\)3x²-18x-22-3x²-2x-17=0

\(\Rightarrow\)-20x-39=0

\(\Rightarrow\)-20x=39

\(\Rightarrow\)x=\(-\dfrac{39}{20}\)

c) (2x+3)² +(x-1)(x+1)=5(x+2)²-(x-5)(x+1)+(x+4)

⇒4x²+12x+9+x²-1=5(x²+4x+4)-(x²+x-5x-5)+x+4

⇒5x²+12x+8=5x²+20x+20-x²-x+5x+5+x+4

⇒5x²+12x+8-5x²-20x-20+x²+x-5x-5-x-4=0

⇒x²-13x-21=0

a, x+15=20-4x

=> x + 4x = 20 - 15

=> 5x = 5

=> x = 5 : 5

=> x = 1

b, 17-x=7-6x

=> -x + 6x = 7 - 17

=> 5x = - 10

=> x = -10 : 5

=> x = -2

c, 4.(x-5)-3.(x+7)= -19

=> 4x - 4.5 - 3.x + 3.7 = -19

=> 4x - 20 - 3x + 21 = -19

=> (4x-3x) + (21-20) = -19

=> 1x + 1 = -19

=> x = -19 - 1

=> x = -18

d, -7.(5-x)-2.(x-10)=15

=> -7x - (-7).5 - 2x - 2.10 = 15

=> -7x - (-35) - 2x - 20 = 15

=> -7x + 35 - 2x - 20 = 15

=> -7x+2x + (35-20) = 15

=> -5x + 15 = 15

=> -5x = 15 - 15

=> -5x = 0

=> x = 0 : (-5)

=> x = 0

e, -5.(2-x)+4.(x-3) = 10.x-15

=> -5x - (-5).2 + 4x - 4.3 = 10x - 15

=> -5x - (-10) + 4x - 12 = 10x - 15

=> -5x + 10 + 4x - 12 = 10x - 15

=> (-5x+4x) - (12-10) = 10x - 15

=> -1x - 2 = 10x - 15

=> -1x - 10x = -15 + 2

=> -11x = -13

=> x = \(\frac{-13}{-11}\)