A 4^2 . 4^3 phan 2^10
B 6^3+3.6^2+3^3 phan -1^3
C (-39)^4 : 13^4
tinh bang cach thuan tien
a, 12 phan 25 + 3 phan 5 + 13 phan 25
b, 3 phan 2 + 2 phan 3 + 4 phan 3
c, 3 phan 5 + 7 phan 5 + 3 phan 4
a, \(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=1+\frac{3}{5}\)
\(=\frac{8}{5}\)
b, \(\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)
\(=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)\)
\(=\frac{3}{2}+2\)
\(=\frac{7}{2}\)
c, \(\frac{3}{5}+\frac{7}{5}+\frac{3}{4}\)
\(=2+\frac{3}{4}\)
\(=\frac{11}{4}\)
nhớ ấn đúng giùm tớ nha
a) = 8 phần 5
b) = 7 phần 2
c) = 11 phần 4
nhớ ấn giùm tớ nha
6^3+3.6^2+3^3 phan -13
a, Viet cac phan so 1/2 ; 2/3 ; 3/4 ; 4/5 ; 5/6 theo thu tu tu be den lon
b, Viet cac phan so 13/12 ; 3/2 ; 15/22 ; 7/8 theo thu tu tu lon den be
a,1/2 2/3 3/4 4/5 theo thứ tự từ bé đến lớn
b,từ lớn đến bé là : 3/2 13/12 7/8 15/22
1/7=8/-x
3x/9=2/6
4/2/5:(-33/10)+x=-1/5/6
(x-2/1/4):(-5/6)=3
-8:(4/1/5x+3/10)=4/4/9
(5,5x-44):(-3/2)=30
(13/10x-15).(-5/14)=3
1/3.(x+5/2)=-2
chu y dau( //)la so tap phan con dau( /) la phan so
\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)
\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)
\(-\frac{100}{33}+x=-\frac{6}{5}\)
\(x=\frac{302}{165}\)
Chia so 420 thanh 4 phan sao cho phan 1 va phan 2 ti le voi 2 va 3,phan 2 va 3 ti le voi 4 va 5,phan 3 va phan 4 ti le voi 6 va 7
\(\text{Gọi 4 phần đó lần lượt là a,b,c,d}\)
\(\text{Ta có :}\)\(\frac{a}{b}=\frac{2}{3}=\frac{16}{24}\Rightarrow\frac{a}{16}=\frac{b}{24}\)
\(\frac{b}{c}=\frac{4}{5}=\frac{24}{30}\Rightarrow\frac{b}{24}=\frac{c}{30}\)
\(\frac{c}{d}=\frac{6}{7}=\frac{30}{35}\Rightarrow\frac{c}{30}=\frac{d}{35}\)
\(\text{Áp dụng t/chất dãy tỉ số bằng nhau:}\)\(\frac{a}{16}=\frac{b}{24}=\frac{c}{30}=\frac{d}{35}=\frac{a+b+c+d}{16+24+30+35}=\frac{420}{105}=4\)
\(\frac{a}{16}=4\Rightarrow a=64\)
\(\frac{b}{24}=4\Rightarrow b=96\)
\(\frac{c}{30}=4\Rightarrow c=120\)
\(\frac{d}{35}=4\Rightarrow d=140\)
Vậy :
tinh
2 - 5 phan 6
7 phan 8 + 3 phan 4
2 phan 5 + 3 phan 4
7 phan 12 - 2 phan 7 + 1 phan 12
12 phan 17 - 5 phan 17 - 4 phan 17
2 - 5/6= 7/6
7/8+3/4=`13/8
2/5+3/4=23/20
7/12 - 2/7 + 1/12=8/21
12/17 - 5/17 - 4/17=3/17
\(2-\frac{5}{6}=1\frac{1}{6}\)
\(\frac{7}{8}+\frac{3}{4}=1\frac{5}{8}\)
\(\frac{2}{5}+\frac{3}{4}=\frac{23}{20}\)
\(\frac{7}{12}-\frac{2}{7}+\frac{1}{12}=\frac{8}{7}\)
\(\frac{12}{17}-\frac{5}{17}-\frac{4}{17}=\frac{3}{17}\)
Tính tổng có quy luật sau
A 6 và 2 phần 7+ 7 va 3 Phan 5 8 va 1 Phan 4+ 5 phan 7 + 1 phan 3+ 3 phan 4+1967
Rút gọn biểu thức:
a) 2^7 . 9^3/ 6^5.8^2
b) 6^3 + 3.6^2 +3^3 / -13
c) 5^4 . 20^4/ 25^4 . 4^5
d) (5^4.5^3)^3/125^4
e) Căn ( 2,5 - 0,7)^2
f) Căn 3^2 + căn 39^2/ căn 7^2 + căn 91^2
a) \(\frac{2^7\cdot9^3}{6^5\cdot8^2}=\frac{2^7\cdot\left(3^2\right)^3}{\left(2\cdot3\right)^5\cdot\left(2^3\right)^2}=\frac{2^7\cdot3^6}{2^5\cdot3^5\cdot2^6}=\frac{3}{2^4}=\frac{3}{16}\)
c) \(\frac{5^4\cdot20^4}{25^4\cdot4^5}=\frac{5^4\cdot\left(2^2\cdot5\right)^4}{\left(5^2\right)^4\cdot\left(2^2\right)^5}=\frac{5^4\cdot2^8\cdot5^4}{5^8\cdot2^{10}}=\frac{1}{2^2}=\frac{1}{4}\)
d) \(\frac{\left(5^4\cdot20^4\right)^3}{125^4}=\frac{5^{12}\cdot20^{12}}{\left(5^3\right)^4}=\frac{5^{12}\cdot\left(2^2\cdot5\right)^{12}}{5^{12}}=2^{24}\cdot5^{12}\)
BÀI 2 TÍNH :
A = \(\dfrac{6^3+3.6^2+3^3}{13}\)
B = \(\dfrac{4^6.9^5+6^9.120}{8^4-3^{12}.6^{11}}\)
\(A=\dfrac{6^3+3\cdot6^2+3^3}{13}\)
\(=\dfrac{3^3\cdot8+3^3\cdot4+3^3}{13}\)
=27