a )
\(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{\left(2^2\right)^5}=\frac{4^5}{4^5}=1\)
b )
\(\frac{6^3+3.6^2+3^3}{\left(-1\right)^3}=\frac{6^2.\left(6+3\right)+27}{-1}=\frac{36.9+27}{-1}=\frac{351}{-1}=-351\)
c )
\(\frac{\left(-39\right)^4}{13^4}=\frac{39^4}{13^4}=\frac{\left(13.3\right)^4}{13^4}=\frac{13^4.3^4}{13^4}=3^4\)
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A \(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{2^{2.5}}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
B \(\frac{6^3+3.6^2+3^3}{-1^3}=\frac{3^3.2^3+3.3^2.2^2+3^3}{-1}=\frac{3^3.2^3+3^3.2^2+3^3}{-1}\)
\(=\frac{3^3\left(2^3+2^2+1\right)}{-1}=\frac{3^3.13}{-1}=\frac{351}{-1}=-351\)
C \(\frac{\left(-39\right)^4}{13^4}=\frac{-3^4.13^4}{13^4}=\left(-3\right)^4=81\)
Ta có : \(a,4^2.\frac{4^3}{2^{10}}=\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{\left(2^2\right)^5}{2^{10}}=\frac{2^{10}}{2^{10}}\)\(=1\)
\(b,6^3+3.6^2+\frac{3^3}{-1^3}=6^2.6+3.6^2+\left(-27\right)\)\(=6^2.\left(6+3\right)+\left(-27\right)=6^2.9+\left(-3\right).9\)
\(=9.\left(6^2+\left(-3\right)\right)=9.\left(36-3\right)=9.33\)
\(=297\)
\(c,\left(-39\right)^4:13^4=\left(-39:13\right)^4=\left(-3\right)^4=81\)
