giải pt :

a, (x+5)(2-x)=3\(\sqrt{x^2+3x}\)

b, \(\sqrt[3]{\dfrac{2x}{x+1}}+\sqrt[3]{\dfrac{1}{2}+\dfrac{1}{2x}}=2\)

c,\(\sqrt[5]{\dfrac{16x}{x-1}}+\sqrt[5]{\dfrac{x-1}{16x}}=\dfrac{5}{2}\)

d, \(\sqrt{5x^2+10x+1}=7-2x-x^2\)

e, \(\sqrt{2x^2+4x+1}=1-2x-x^2\)

giải pt :

a,\(\sqrt[3]{\dfrac{2x}{x+1}}\sqrt[3]{\dfrac{1}{2}+\dfrac{1}{2x}}=2\)

b,\(\sqrt[5]{\dfrac{16x}{x-1}}\sqrt[5]{\dfrac{x-1}{16xx}}=\dfrac{5}{2}\)

giải pt :

a, \(\dfrac{\sqrt{x-3}}{\sqrt{2x-1}-1}=\dfrac{1}{\sqrt{x+3}-\sqrt{x-3}}\)

b, \(\left(\sqrt{x^2+x+1}+\sqrt{4x^2+x+1}\right)\left(\sqrt{5x^2+1}-\sqrt{2x^2+1}\right)=3x^2\)

giải pt :

a,\(2x^2-11x+21=3\sqrt[3]{4x-4}\)

b,\(\dfrac{\sqrt{x-3}}{\sqrt{2x-1}-1}=\dfrac{1}{\sqrt{x+3}-\sqrt{x-3}}\)

c,\(\left(\sqrt{x^2+x+1}+\sqrt{4x^2+x+1}\right)\left(\sqrt{5x^2+1}-\sqrt{2x^2+1}\right)=3x^2\)

giải pt

a)\(\dfrac{1}{x+1}+\dfrac{3}{2x+1}=\dfrac{8}{x-2}\)

b)\(\sqrt{2x+1}+\sqrt{3-x}=\sqrt{3x+5}\)

Giải phương trình:
1. \(5x^2+2x+10=7\sqrt{x^4+4}\)
2. \(\dfrac{4}{x}+\sqrt{x-\dfrac{1}{x}}=x+\sqrt{2x-\dfrac{5}{x}}\)
3. \(\sqrt{x^2+2x}=\sqrt{3x^2+4x+1}-\sqrt{3x^2+4x+1}\)

gptr:

1, \(\dfrac{x}{\sqrt{2x-1}}+\dfrac{1}{\sqrt[4]{4x-3}}=\dfrac{2}{x}\)

2, \(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{2x-1}}=\sqrt{3}\left(\dfrac{1}{\sqrt{4x-1}}+\dfrac{1}{\sqrt{5x-2}}\right)\)

3,\(\sqrt{-x^2+4x+21}-\sqrt{-x^2+3x+10}=\sqrt{2}\)

Éttttt ooooo éttttt. mời các thiên tài toán học ạ

giải pt sau :

\(2\sqrt{x^2-\dfrac{1}{4}+\sqrt{x^2-\dfrac{1}{4}+\sqrt{...+\sqrt{x^2-\dfrac{1}{4}+\sqrt{x^2+x+\dfrac{1}{4}}}}}}=2x^3+3x^2+3x+1\)

trong đó biểu thức ở vế trái có 2010 dấu căn thức bậc 2