=>5x^3+4x^2+3x+3-4+x+4x^2-5x^3=5

=>8x^2+4x-1-5=0

=>8x^2+4x-6=0

=>4x^2+2x-3=0

=>\(x=\dfrac{-1\pm\sqrt{13}}{4}\)

\(\left(x.7-7\right)\left(x.12+24\right)=0\)

=> \(\orbr{\begin{cases}x.7-7=0\\x.12+24=0\end{cases}}\)

=> \(\orbr{\begin{cases}7x=7\\12x=-24\end{cases}}\)

=> \(\orbr{\begin{cases}x=1\\x=-2\end{cases}}\)

\(170-\left(4+5x\right)=101\)

=> \(4+5x=170-101\)

=> \(4+5x=69\)

=> \(5x=69-4\)

=> \(5x=65\)

=> \(x=65:5=13\)

(x.7-7).(x.12+24)=0

* x.7-7=0                                  * x.12+24=0

x.7=7                                           x.12=24

   x=7:7                                            x=24:12

   x=1                                                x=2

vạy x=1 hoặc x=2

170-(4+5x)=101

4+5x=170-101

4+5x=69

5x=69-4

5x=65

  x=65:5

  x=13

vậy x=13

250:(2x-4)=145-120

250:(2x+4)=25

2x+4=250:25

2x+4=10

2x=10+4

2x=14

  x=14:2

  x=7

vậy x=7

6.x+3.x-4.x=105

x.(6+3-4)=105

x.(9-4)=105

x.5=105

   x=105:5

   x=21

vậy x=21

1) (x.7 - 7)(x.12 + 24) = 0

(7x - 7)(12x + 24) = 0

7x - 7 = 0 hoặc 12x + 24 = 0

7x = 0 + 7          12x = 0 - 24

7x = 7                 12x = -24

x = 1                    x = -2

Vậy: x = 1 hoặc x = -2

2) 170 - (4 + 5x) = 101

170 - 4 - 5x = 101

-5x + 166 = 101

-5x = -65

x = 13

3) 250 : (2x - 4) = 145 - 120

250 : (2x - 4) = 25

125 = 25(x - 2)

125 : 25 = x - 2

5 = x - 2

5 + 2 = x

7 = x

x = 7

4) 6.x + 3.x - 4.x = 105

5.x = 105

x = 105 : 5

x = 21

\(2016\times105-2016\times4-2016\)

\(=2016\times\left(105-4-1\right)\)

\(=2016\times100\)

\(=201600\)

\(x\times24+x\times6=240\)

   \(x\times\left(24+6\right)=240\)

                 \(x\times30=240\)

                            \(x=240:30\)

                            \(x=8\)

\(x-167\times15=167\times185\)

        \(x-2505=30895\)

                        \(x=30895+2505\)

                        \(x=33400\)

\(173\times105+173\times96-173\)

\(=173\times\left(105+96-1\right)\)

\(=173\times200\)

\(=34600\)

1. 2016 x 105 - 2016 x 4 - 2016

= 211680 - 8064 - 2016

= 203616 - 2016

= 201600

2. X x 24 + X x 6 = 240

    X x (24 + 6) = 240

    X x 30 = 240

    X        = 240 : 30

    X        = 8

3. X - 167 x 15 = 167 x 185

    X - 2505 = 30895

    X           = 30895 - 2505

    X           = 28390

4. 173 x 105 + 173 x 96 - 173

= 18165 + 16608 - 173

= 34773 - 173

= 34600

f ) \(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24\)

\(=\left[\left(x+1\right)\left(x+4\right)\right]\left[\left(x+2\right)\left(x+3\right)\right]-24\)

\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)-24\)

Đặt \(x^2+5x+5=t\), ta có :

\(\left(t-1\right)\left(t+1\right)-24\)

\(=t^2-1-24=t^2-25\)

\(=\left(t-5\right)\left(t+5\right)\)

Thay và ta có :

\(\left(x^2+5x+5-5\right)\left(x^2+5x+5+5\right)\)

\(=\left(x^2+5x\right)\left(x^2+5x+10\right)\)

\(=x\left(x+5\right)\left(x^2+5x+10\right)\)

a) \(58+7x=100\)

\(=>7x=100-58\)

\(=>7x=42\)

\(=>x=42:7\)

\(=>x=6\)

b) \(3x-7=28\)

\(=>3x=28+7\)

\(=>3x=35\)

\(=>x=35:3\)

\(=>x=\dfrac{35}{3}\)

c) \(x-56:4=16\)

\(=>x-14=16\)

\(=>x=16+14\)

\(=>x=30\)

d) \(101+\left(36-4x\right)=105\)

\(=>36-4x=105-101\)

\(=>36-4x=4\)

\(=>4x=36-4\)

\(=>4x=32\)

\(=>x=32:4\)

\(=>x=8\)

e) \(\left(x-12\right):12=12\)

\(=>x-12=12.12\)

\(=>x-12=144\)

\(=>x=144-12\)

\(=>x=132\)

f) \(\left(3x-2^4\right).7^3=2.7^4\)

\(=>3x-2^4=2.7^4:7^3\)

\(=>3x-16=2.7=14\)

\(=>3x=14+16\)

\(=>3x=30\)

\(=>x=30:3\)

\(=>x=10\)

i) \(\left(10+2x\right).4^{2011}=4^{2013}\)

\(=>10+2x=4^{2013}:4^{2011}\)

\(=>10+2x=4^2=16\)

\(=>2x=16-10\)

\(=>2x=6\)

\(=>x=6:2\)

\(=>x=3\)

\(#WendyDang\)

1) Ta có: \(5\left(x-3\right)\left(x-7\right)-\left(5x+1\right)\left(x-2\right)=-8\)

\(\Leftrightarrow5\left(x^2-10x+21\right)-\left(5x^2-10x+x-2\right)=-8\)

\(\Leftrightarrow5x^2-50x+105-5x^2+9x+2+8=0\)

\(\Leftrightarrow-41x=-115\)

hay \(x=\dfrac{115}{41}\)

2) Ta có: \(x\left(x+1\right)\left(x+2\right)-\left(x+4\right)\left(3x-5\right)=84-5x\)

\(\Leftrightarrow x\left(x^2+3x+2\right)-\left(3x^2+7x-20\right)=84-5x\)

\(\Leftrightarrow x^3+3x^2+2x-3x^2-7x+20-84+5x=0\)

\(\Leftrightarrow x^3=64\)

hay x=4

3) Ta có: \(\left(9x^2-5\right)\left(x+3\right)-3x^2\left(3x+9\right)=\left(x-5\right)\left(x+4\right)-x\left(x-11\right)\)

\(\Leftrightarrow9x^3+27x^2-5x-15-9x^3-27x^2=x^2-x-20-x^2+11x\)

\(\Leftrightarrow-5x-15=10x-20\)

\(\Leftrightarrow-5x-10x=-20+15\)

\(\Leftrightarrow x=\dfrac{-5}{-15}=\dfrac{1}{3}\)

a, 100 - 7 x ( x - 5 ) = 58

7 x ( x - 5 ) = 100 - 58

7 x ( x - 5 ) = 42

( x - 5 ) = 42 : 7

x - 5 = 6

x = 6 + 5

x = 11

b, 24 + 5 * x = 49

5 * x = 49 - 24

5 * x = 25

x = 25 : 5

x = 5

c, x - 105 : 21 = 15

x - 5 = 15

x = 15 + 5

x = 20

d, ( x - 105 ) : 21 = 15

( x - 105 ) = 15 x 21

x - 105 = 315

x = 315 + 105

x = 420

3. tìm số tự nhiên x biết 

a 100 - 7x [ x - 5] = 58

b 24+5 nhân x = 49

c x- 105 : 21 = 15

d { x- 105] : 21 =15

a, 100 - 7 x ( x - 5 ) = 58

7 x ( x - 5 ) = 100 - 58

7 x ( x - 5 ) = 42

( x - 5 ) = 42 : 7

x - 5 = 6

x = 6 + 5

x = 11

b, 24 + 5 * x = 49

5 * x = 49 - 24

5 * x = 25

x = 25 : 5

x = 5