(2x - 1/3)= 2

2x= 2+1/3

2x= 7/3

x= 7/3 : 2

x= 1,66666

a: =>2x-1/3=2

=>2x=7/3

=>x=7/6

b: Sửa đề: 1/11-5/22

\(\dfrac{8}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)

\(=\dfrac{8}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:\dfrac{-9}{15}\)

\(=\dfrac{8}{9}\cdot\dfrac{-22}{3}+\dfrac{5}{9}\cdot\dfrac{-5}{3}\)

\(=\dfrac{-66-25}{27}=\dfrac{-91}{27}\)

1 / 9 + 2 / 9 + 4 / 9 = 7 / 9

5 / 5 + 6 / 5 + 1 = 15 / 5 = 3

12 / 2 + 4 / 2 + 1 + 3 / 2 = 21 / 2

7 / 3 + 6 / 3 + 1 + 1 = 19  / 3

2/3 = 2 x 4/ 3 x 4 =8/12

8/14 = 8 : 2/ 14 : 2 =4/7

5/9 = 5 x3/ 9 x 3 =15/37

35/ 40 = 35 : 5/ 40 : 5=7/8

11/9 + 18/5 -2/9 -3/5

= 11/9  - 2/ 9  + 18/5 - 3/5

= 9/9 + 15/5

= 1+ 3

= 4

=11/9-2/9+18/5-3/5=9/9+15/5

                               =1+3=4

11/9 + 18/5 -2/9 -3/5

= 11/9  - 2/ 9  + 18/5 - 3/5

= 9/9 + 15/5

= 1+ 3

= 4

c: Ta có: \(\dfrac{5}{3}+\dfrac{5}{3\cdot5}+\dfrac{5}{5\cdot7}+...+\dfrac{5}{101\cdot103}\)

\(=\dfrac{5}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{101\cdot103}\right)\)

\(=\dfrac{5}{2}\left(1-\dfrac{1}{103}\right)\)

\(=\dfrac{5}{2}\cdot\dfrac{102}{103}\)

\(=\dfrac{255}{103}\)

Kết quả bằng -5 nha!

1+1-2-2-3-4-5-6-7-8-9+1+3+5+7+9+10

=-44+1+3+5+7+9+10

=-44+35

=-9

-5 nha bạn

5/9 : 3/x+2 = 5/3 ( Câu này mình để x + 2 dưới mẫu nhé còn nếu tách chuyển vế âm lớp 4 chưa học ! )

<=> 3/x+2 = 5/9 : 5/3

<=> 3/x+2 = 1/3

<=> x + 2 = 9 <=> x = 7

3/7 + x/35 = 4/5

<=> x/35 = 4/5 - 3/7 = 13/35

<=> x = 13

<=>15/35 + x/35=28/35
<=>28/35-15/35=x/35
<=>8/35=x/35
<=>8

(3/5+2/5)+(4/9+5/9)=1+1=2

(5/4+3/4)+(3/8+5/8)=8/4+1=8/4