Câu 2: 

\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)

\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)

\(\dfrac{7}{12}-\dfrac{1}{6}:\dfrac{2}{5}=\dfrac{7}{12}-\dfrac{5}{12}=\dfrac{2}{12}=\dfrac{1}{6}\)

\(2\times\dfrac{2}{3}+1=\dfrac{4}{3}+1=\dfrac{4}{3}+\dfrac{3}{3}=\dfrac{7}{3}\)

7/12 - 1/6 : 2/5 = 7/12 - 5/12 = 2/12 = 1/6

2 x 2/3 + 1 = 4/3 + 1 = 7/3

1: \(\dfrac{-7}{4}\cdot\dfrac{2}{9}=\dfrac{-14}{36}=\dfrac{-7}{18}\)

2: \(=\dfrac{12}{13}\cdot\dfrac{26}{5}=\dfrac{24}{5}\)

3: \(=\dfrac{20}{11}\cdot\dfrac{55}{21}=\dfrac{100}{21}\)

4: \(=\dfrac{-40}{240}=\dfrac{-1}{6}\)

\(\dfrac{x}{15}\)+\(\dfrac{x}{12}\)=4/1+1/2=9/2

=>x(\(\dfrac{1}{15}\)+\(\dfrac{1}{12}\))=9/2

=>x\(\cdot\)\(\dfrac{3}{20}\)=9/2

=>x=9/2:3/20=30

Vậy x=30

\(\dfrac{x}{15}+\dfrac{x}{12}=\dfrac{9}{2}\Rightarrow\left(\dfrac{1}{15}+\dfrac{1}{12}\right)x=\dfrac{9}{2}\)

\(\Rightarrow\left(\dfrac{12+18}{180}\right)x=\dfrac{9}{2}\Rightarrow\dfrac{30}{180}x=\dfrac{9}{2}\Rightarrow\dfrac{1}{6}x=\dfrac{9}{2}\Rightarrow x=\dfrac{9}{2}.6=27\)

12 : {390 : [500 - (125 + 35 . 7)]}

= 12 : {390 : [500 - (125 + 245)]}

= 12 : [390 : (500 - 370)]

= 12 : (390 : 130)

= 12 : 3

= 4

12 : { 390 : [ 500 - ( 125 + 35. 7 ) ] }

   =  12 : { 390 : [ 500 - ( 125 + 245 ) ] }

   =   12 : { 390 : [ 500 - 370 ] }

   =   12 : { 390 : 130 }

    =   12 : 3

    =     4

\(\dfrac{4}{7}\times X=\dfrac{1}{2}\\ X=\dfrac{1}{2}:\dfrac{4}{7}=\dfrac{1}{2}\times\dfrac{7}{4}=\dfrac{7}{8}\)

\(\dfrac{7}{8}\)

x=1/2:4/7

x=7/8

a) 100 + (+430) + 2145+ (-530)

= 100+ 430  + 2145 - 530

= 530 - 530 +2145

= 0 + 2145 = 2145

 b) (-12).15 = -10.15 -2.15 = -150 - 30 = -180

c) (+12).13 + 13.(-22)

= 13.   (12 - 22)

= 13. (-10)

= -130

d) {[14 : (-2)] + 7} : 2020

=     { - 7 + 7} : 2020

= 0 : 2020

=0

Học tốt

a) 100+430+2145+(-530)

=(100+2145)+[430+(-530)]

=2245+(-100)=2145

b) (-12).15=-180 (nếu muốn tính nhanh : (-12).15=(-3).4.15=(-3).60=-180)

c) 12.13+13.(-22)=13[12+(-22)]

                           =13.(-10)=-130

d) {[14:(-2)]+7}:2020

={(-7)+7}:2020

=0:2020=0

(+430) hay (-430)?

a) 100 + (+430) + 2145 + (-530) =530+2145+(-530)=2675+(-530)=2145

b) (-12).15=180

c) 12.13+13.(-22)=[12.(-22)] + 13 = -246+13=-251

d) {[14/(-2)]+7}/2020={[(-7)+7]}/2020=0/2020=0
Ko biết đúng hay sai :V

1) = \(\frac{3}{5}\)

2) =\(\frac{6}{7}\)

3)\(\frac{9}{13}\)

4)\(\frac{4}{13}\)

Bài 1:

\(f\left(x\right)=-x^{15}+8x^{14}-8x^{13}+...-8x-5\)

Ta xét \(x=7\Leftrightarrow x+1=8\)

Khi đó :

\(f\left(7\right)=-x^{15}+x^{14}\left(x+1\right)-x^{13}\left(x+1\right)+...-x\left(x+1\right)-5\)

\(f\left(7\right)=-x^{15}+x^{15}+x^{14}-x^{14}-x^{13}+...-x^2-x-5\)

\(f\left(7\right)=-x-5\)

\(f\left(7\right)=-7-5\)

\(f\left(7\right)=-12\)

Vậy...