tính nhanh :
( 3737 x 50 - 5050 x 36 ) : ( 1 + 2 + 3 + ............. + 100 )
(3737x 50- 5050 x 36): (1+2+3+........+99+100)
(3737x 50- 5050 x 36): (1+2+3+........+99+100)
= (37 . 101 . 50 - 50 . 101 . 36) : \(\frac{100.\left(100+1\right)}{2}\)
= 50 . (37 . 101 - 101 . 36) : 5050
= 50 x 101 - 5050
= 5050 - 5050
= 0
Từ dòng thứ 4 sửa lại :
= 50 x 101 : 5050
= 5050 : 5050
= 1
Tìm x :
\(\frac{1}{x}\)+\(\frac{2}{x}\)+\(\frac{3}{x}\)+....+\(\frac{99}{x}\)+\(\frac{100}{x}\)=5050
ai nhanh mình tik
\(\frac{1}{x}\)+\(\frac{2}{x}\)+\(\frac{3}{x}\)+....+\(\frac{99}{x}\)+\(\frac{100}{x}\)=5050
\(\frac{1+2+3+....+99+100}{x}\)=5050
\(\frac{5050}{x}\)=5050
\(\frac{5050}{x}\)=\(\frac{5050}{1}\)
\(\Rightarrow x=1\)
Vậy x = 1
Tính nhanh: a) ( 68 x 72 x 49) x ( 27 x 12 – 9 x 36 )
b) ( 25 x 50 – 125 x 10 ) x ( 1 + 2 + 3 + ……….. + 99 + 100
a: \(=68\cdot72\cdot49\cdot\left[324-324\right]=0\)
b: \(=\left(1250-1250\right)\cdot\left(1+...+100\right)=0\)
\(a,\left(68\times72\times49\right)\times\left(27\times12-9\times36\right)=\left(68\times72\times49\right)\times0=0\\ b,\left(25\times50-125\times10\right)\times\left(1+2+...+100\right)=0\times\left(1+2+...+100\right)=0\)
a, ( 68 × 72 × 49 ) × ( 27 × 12 − 9 × 36 ) = ( 68 × 72 × 49 ) × 0 =
b, ( 25 × 50 − 125 × 10 ) × ( 1 + 2 + ... + 100 ) = 0 × ( 1 + 2 + ... + 100 ) = 0
TÌM X
a)5*(x-1)+3=43
b)(1+2+3+4+...+50)+x=5050
c)(2*x+1)3=64
\(5\left(x-1\right)+3=43\)
\(5\left(x-1\right)=40\)
\(x-1=8\)
\(x=9\)
\(\left(1+2+3+...+50\right)+x=5050\)
\(\dfrac{50\left(50+1\right)}{2}+x=5050\)
\(1275+x=5050\)
\(x=3775\)
\(\left(2x+1\right)^3=64\)
\(\left(2x+1\right)^3=4^3\)
\(2x+1=4\)
\(2x=3\)
\(x=1,5\)
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
100x + 101.100 : 2 = 5050
100x + 5050 = 5050
100x = 0
x = 0
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5050
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5050
100 số x
100.x + (1 + 100).100:2 = 5050
100.x + 101.50 = 5050
100.x + 5050 = 5050
=> 100.x = 0
=> x = 0
Ủng hộ mk nha ^_-
\(\text{( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050 }\)
\(x+\left(100+1\right)\cdot100:2=5050\)
\(x+5050=5050\)
\(\Rightarrow x=0\)
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
100x + (1+2+3+4+...+100) = 5050
100x + { [ ( 100-1):1+1 ] . [ (100+1):2 ] } = 5050
100x + 5050 = 5050
100x = 0
=> x =0
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
=> ( x+x+.... +x)+(1+2+3+4+5+....+100)
tổng 1+2+3+4+....+100=5050
=> x=0
( x + 1 ) + ( x + 2 ) + ( x + 3 )+ .... + ( x + 100) = 5050.
(x+1) + (x+2) +....+(x+100) = 5050
100 x X + ((100+1) x 100 : 2) = 5050
100 x X + 5050 = 5050
100 x X = 0
=> x = 0
(X+1)+(X+2)+(X+3)+...+(X+100)=5050
=>(X+X+X+...+X)+(1+2+3+...+100)=5050
=>100X+[(1+100)x100:2)]=5050
=>100X+(101x100:2)=5050
=>100X+(10100:2)=5050
=>100X+5050=5050
=>100X=5050-5050
=>100X=0
=>X=0:100
=>X=0
a) Tìm x biết: (x + 1) + (x + 2) + (x + 3) + … + (x + 99) + (x +100) = 5050
(X + 1) + (X + 2) + (X + 3) + … + (X + 99) + (X +100) = 5050
(X+X+X+...+X+X) + (1+100) x 50 = 5050
100 x X + 101 x 50 = 5050
100 x X + 5050 = 5050
100 x X = 5050 - 5050
100 x X = 0
X= 0: 100
X= 0
`(x + 1) + (x + 2) + (x + 3) + … + (x + 99) + (x +100) = 5050`
`(x+x+x+...+x+x) + (1+2+3+...+99+100)=5050`
Số số hạng là : `(100-1)/1+1= 100` ( số hạng )
Tổng dãy là : `(100+1) xx 100 : 2=5050`
`100x+5050=5050`
` 100x=5050-5050`
` 100x=0`
`x=0`
Tìm x biết (x+1)+(x+2)+(x+3)+...+(x+100) = 5050
100x+(1+2+3+...+100)=5050
100x+5050=5050
100x=5050-5050
100x=0
x=0:100
x=0