Phương pháp giải:

- Đặt tính: Viết phép tính sao cho các chữ số cùng hàng thẳng cột với nhau.

- Tính: Trừ các số rồi điền kết quả vào chỗ trống.

Lời giải chi tiết:

a)

b)

c)

Phương pháp giải:

Trừ nhẩm các số rồi điền kết quả vào chỗ trống.

Lời giải chi tiết:

a)

15 − 6 = 9         15 − 7 = 8

15 − 8 = 7         15 − 9 = 6

16 − 7 = 9         16 − 8 = 8

16 − 9 = 7         17 − 8 = 9

17 − 9 = 8         18 − 9 = 9

b)

18 − 8 − 1 = 9       18 − 9 = 9

15 − 5 − 2 = 8       15 − 7 = 8

16 − 6 − 3 = 7       16 − 9 = 7

15 - 6 = 9, 

15 - 8 =7, 

15 - 7 = 8, 

15 - 9 = 6

bạn hỏi j z

`@` `\text {Ans}`

`\downarrow`

`x^3 = 125`

`=> x^3 = 5^3`

`=> x = 5`

Vậy, `x = 5`

_____

`4^5 \div 4^3`

`=`\(4^{5-3}\)

`= 4^2`

______

\(8^{12}\cdot8^3\div8^{15}\)

`=`\(8^{12+3-15}\)

`=`\(8^0=1\)

______

\(7^{15}\div7^{13}\)

`=`\(7^{15-13}\)

`=`\(7^2\)

_______

\(17^{15}\cdot17^{10}\div17^{22}\)

`=`\(17^{15+10-22}\)

`= 17^3`

_______

\(5^{10}\cdot25\div5^{11}\)

`=`\(5^{10}\cdot5^2\div5^{11}\)

`=`\(5^{10+2-11}\)

`= 5`

_______

\(15^{10}\cdot225\div15^{11}\)

`=`\(15^{10}\cdot15^2\div15^{11}\)

`=`\(15^{12}\div15^{11}\)

`= 15`

`@` `\text {Kaizuu lv uuu}`

\(x^3=125\)

\(\Rightarrow x^3=5^3\)

\(\Rightarrow x=3\)

___________________

\(4^5:4^3\)

\(=4^{5-3}\)

\(=4^2=16\)

___________________

\(8^{12}.8^3:8^{15}\)

\(=8^{15}:8^{15}\)

\(=1\)

___________________

\(7^{15}:7^{13}\)

\(=7^{15-13}\)

\(=7^2=49\)

___________________

\(17^{15}.17^{10}:17^{22}\)

\(=17^{25}:17^{22}\)

\(=17^3=4913\)

___________________

\(5^{10}.25:5^{11}\)

\(=5^{10}.5^2:5^{11}\)

\(=5^{12}:5^{11}\)

\(=5^1=5\)

___________________

\(15^{10}.225:15^{11}\)

\(=15^{10}.15^2:15^{11}\)

\(=15^{12}:15^{11}\)

\(=15^1=15\)

__________________

* aⁿ . a^m = a^n+m

 aⁿ : a^m = a^n-m

Chúc bạn học tốt

câu a : 

\(\dfrac{-8}{24}+\dfrac{-4}{12}=\dfrac{-1}{3}+\dfrac{-1}{3}=\dfrac{-2}{3}\)

câu b : 

\(\dfrac{-20}{35}+\dfrac{16}{24}=\dfrac{-4}{7}+\dfrac{2}{3}=\dfrac{2}{21}\)

câu c : 

\(\dfrac{-3}{9}+\dfrac{-6}{15}=\dfrac{-1}{3}+\dfrac{-2}{5}=\dfrac{-11}{15}\)

câu d : 

\(\dfrac{3}{13}-\dfrac{4}{10}=\dfrac{3}{13}-\dfrac{2}{5}=\dfrac{-11}{65}\)

câu e : 

\(\dfrac{5}{17}-\dfrac{9}{15}=\dfrac{5}{17}-\dfrac{3}{5}=\dfrac{-26}{85}\)

câu g : 

\(\dfrac{9}{18}-\dfrac{6}{15}+\dfrac{3}{-9}=\dfrac{9}{18}-\dfrac{6}{15}+\dfrac{-3}{9}\\ =\dfrac{1}{2}-\dfrac{2}{5}+\dfrac{-1}{3}=\dfrac{-7}{30}\)

câu h : 

\(\dfrac{5}{4}-\dfrac{1}{2}+\dfrac{-7}{8}=\dfrac{10}{8}-\dfrac{4}{8}+\dfrac{-7}{8}=\dfrac{-1}{8}\)

\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)

\(=1+\frac{8}{11}=\frac{19}{11}\)

\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)

\(=2+1=3\)

\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}\)

\(=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)

\(=1+\frac{8}{11}\)

\(=\frac{19}{11}\)

\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)\)

\(=\frac{26}{17}+\frac{15}{34}+\frac{8}{17}+\frac{19}{34}\)

\(=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)

\(=2+1\)

\(=3\)

\(\Leftrightarrow-\dfrac{16}{279}< \dfrac{x}{9}< =\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{x}{9}=0\)

hay x=0