33+2=
99/3=
95+5=
99+1=
4+3/5+3/7+...+3/95+3/97+3/99
1/99+1/3*97+1/5*95+..+1/95*5+1/97*3+1/99*1
tính A= (1+1/3+1/5+...+1/95+1/97+1/99) /(1/1*99+1/3*97+1/5*95+...+1/95*5+1/97*3+1/99*1)
tinh tong gia tri bieu thuc :
a)A=1+1/3+1/5+...+1/97+1/99/1/1*99+1/3*97+1/5*95+...+1/97*3+1/99*1
b)B=1/2+1/3+1/4+...+1/100/99/1+98/2+97/3+...+1/99
E=(1+1/3+1/5+........+1/97+1/99)/(1/1*99+1/3*97+1/5*95+.....+1/97*3+1/99*1)
Giải pt : ( x-1/99 +x-99 )+( x-3/97 + x-97/3 )+ (x-5/95 + x-95/5 )=6
\(\Leftrightarrow\left(\dfrac{x-1}{99}-1\right)+\left(\dfrac{x-99}{1}-1\right)+\left(\dfrac{x-3}{97}-1\right)+\left(\dfrac{x-97}{3}-1\right)+\left(\dfrac{x-5}{95}-1\right)+\left(\dfrac{x-95}{5}-1\right)=0\)
=>x-100=0
=>x=100
(x-1/99+x-99)+(x-3/97+x-7/93)+(x-5/95+x-95/5)=6
1.So sánh
a)3/5 và 4/9
b)13/14 và 131313/141414
c) 91 nhân 99/95 nhân 95 và 1
d)35 nhân 35/33 nhân 37 và 1
\(\frac{3}{5}>\frac{4}{9}\)
\(\frac{13}{14}=\frac{131313}{141414}\)
\(91.\frac{99}{95}.95>1\)
\(35.\frac{35}{33}.37>1\)
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)\(\frac{1}{95}\)
\(\frac{1}{95}\frac{1}{95}\)
là sao ???
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=\frac{2765070}{921690}+\frac{9310}{921690}+\frac{9405}{921690}+\frac{9702}{921690}\)
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=\frac{2793487}{921690}\)
\(BCNN\left(99,98,95\right)=921690\Rightarrow x=101\)
(x-1)/99+(X-2)/98+(X-5)/95=3+1/99+1/98+1/95
Giải từng bước dùm mình nhé
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