1.

(x + 1/5)² = 26/25 - 17/25 

(x + 1/5)² = 9/25 

Rút căn hai vế : 

|(x + 1/5)| = 3/5 

x = -4/5 
hoặc
x = 2/5

2.

(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0 
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4 = 0 
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0 
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0 
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) >0 nên x+ 329 =0 => x= -329 

Câu 1 chưa chắc đã đúng ( quên hết kiến thức lớp 6 rùi ) hihi

aaaaaaaa . chết rồi . cho mình sủa câu thứ nhất :

(x+1/5)² + 17/25=26/25

( x + 1/5 ) ² = 26/25 - 17/25

( x + 1/5 ) ² = 3/5²

x + 1/5 = 3/5

x = 2/5.

1/\(-2020+23+x=-2020\\ \Leftrightarrow23+x=-2020+2020\\ \Leftrightarrow23+x=0\\ \Leftrightarrow x=0-23\\ \Leftrightarrow x=-23\)

Vậy...

2/\(2x-35=25\\ \Leftrightarrow2x=60\\ \Leftrightarrow x=30\)

Vậy...

3/\(3x+17=26\\ \Leftrightarrow3x=9\\ \Leftrightarrow x=3\)

Vây...

4/\(\left|\text{x}-1\right|=0\\ \Leftrightarrow x-1=0\\ \Leftrightarrow x=1\)

Vậy...

5/ \(-17.\left|x\right|=-34\\ \Leftrightarrow\left|x\right|=2\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)

VẬy...

a, 568 + 568 x 135 - 568 x 36

= 568 x ( 1 + 135 - 36)

= 568 x 100

56 800

b, 17 x 49 + 49 x 37 + 54 x 26 + 54 x 25

=  49 x ( 17 + 37) + 54 x ( 26 + 25 )

= 49 x 54 + 54 x 51

= 54 x ( 49 + 51)

= 54 x 100

= 5 400

c,   14 x 35 x 5 + 10 x 25 x 7 + 20 x 70

 =    ( 2 x 35) x ( 7 x 5)  + ( 10 x 7) x 25 + 20 x 70

= 70 x 35 + 70 x 25 + 20 x 70

= 70 x ( 35 + 25 + 20)

= 70 x 80

= 5 600 

a) 568 + 568 x 135 - 568 x 36

= 568 x ( 1+1+135-1-36 )

=568 x 100

=5680

b) 17 x 49 + 49 x 37 + 54 x 26 + 54 x 25

= 49 x ( 17 + 37 ) + 54 x ( 26 + 25 )

= 49 x 54 + 54 x 51

= 54 x ( 49 + 51 )

= 54 x 100

= 5400

c) 14 x 35 x 5 + 10 x 25 x 7 + 20 x 70

= 70 x 35 + 10 x 25 x 7+ 20 x 70

= 70 x 35 + 250 x 7 + 20 x 70

= 70 x 35 + 70 x 25 + 20 x 70

= 70 x (35+25+20)

= 70 x 80

= 5600

2 . tìm x :

a ) 5^2x = 625

 5^2x = 5⁴

=> 2 . x = 4

x = 4 : 2

x = 2

b ) 9^x-1 = 9

9^x-1 = 9¹

=> x - 1 = 1

x = 1 + 1

x = 2

c ) 2^x : 2⁵ = 1

2^x-5 = 1

=> x = 5 , vì 2^5-5 = 2⁰ = 1

1: =>x=8-35=-27

2: =>15-4+x=6

=>x+11=6

hay x=-5

3: =>-30+25-x=-1

=>x+5=1

hay x=-4

4: =>x-(-13)=-8

=>x+13=-8

hay x=-21

5: =>x-29-17+38=-9

=>x-8=-9

hay x=-1

`Answer:`

a. \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)

\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)

\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{41}{4}+\frac{3}{4}\\2x=-\frac{41}{4}+\frac{3}{4}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=11\\2x=-\frac{19}{2}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=11:2\\x=-\frac{19}{2}:2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=-\frac{19}{4}\end{cases}}\)

b. \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\Leftrightarrow\left(x+\frac{1}{5}\right)=\left(\frac{3}{5}\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}-\frac{1}{5}\\x=-\frac{3}{5}-\frac{1}{5}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}\)

c. \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)

\(\Leftrightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)

\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}-\left(-\frac{24}{27}\right)\)

\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)

\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)

\(\Leftrightarrow3x-\frac{7}{9}=-\frac{2}{3}\)

\(\Leftrightarrow3x=-\frac{2}{3}+\frac{7}{9}\)

\(\Leftrightarrow3x=\frac{1}{9}\)

\(\Leftrightarrow x=\frac{1}{9}:3\)

\(\Leftrightarrow x=\frac{1}{27}\)