a/317+(600-x)=517
b/325-(x+16)=425:17
c/25*(x-1)=0
d/713:(2x+17)=23
e/(x+a/3)*7/4=5-7/6
bài tìm x
a) 435 - ( x + 16 ) = 425 : 17
b) ( x + 4/3 ) * 7/4 = 5 - 7/6
a) \(435-\left(x+16\right)=425:17\)
\(435-\left(x+16\right)=25\)
\(\Rightarrow x+16=435-25=410\)
\(\Rightarrow x=410-16=394\)
b) \(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=\frac{23}{6}\)
\(\Rightarrow x+\frac{4}{3}=\frac{23}{6}:\frac{7}{4}=\frac{46}{21}\)
\(\Rightarrow x=\frac{46}{21}-\frac{4}{3}=\frac{6}{7}\)
Ủng hộ mk nka!!!^_^^_^^_^
a) 435 - ( x + 16 ) = 25
x+ 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
b) (x+4/3 ) * 7/4 = 23/6
x+4/3= 23/6 : 7/4
x+4/3 = 46/21
x = 46/21 - 4/3
x = 6/7
435-(x+16)=425:17
435-(x+16)=25
x+16 =435-25
x+16 =410
x =394
b) \(\left(x+\frac{4}{3}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{4}{3}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(\left(x+\frac{4}{3}\right)=\frac{23}{6}:\frac{7}{4}\)
\(\left(x+\frac{4}{3}\right)=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{4}{3}\)
\(x=\frac{6}{7}\)
T mk nha bạn ^...^ !!!
a/713:(2x+17)=23
b/(x+4/3)*7/4=5-7/6
tìm X
435 - ( x +16 ) = 425 : 17
(x + 3/4 ) * 7/4 +7 /6 =5
a) \(435-\left(x+16\right)=425:17\)
\(435-\left(x+16\right)=25\)
\(x+16=435-25\)
\(x+16=410\)
\(x=410-16\)
\(x=394\)
b) \(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(x+\frac{3}{4}=\frac{23}{6}:\frac{7}{4}\)
\(x+\frac{3}{4}=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{3}{4}\)
\(x=\frac{121}{84}\)
435 - ( x + 16 ) = 425 : 17
435 - ( x + 16 ) = 25
x + 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
\(435-\left(x+16\right)=425\div17\)
\(435-\left(x+16\right)=25\)
\(x+16=435-25\)
\(x+16=410\)
\(x=410-16\)
\(x=394\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x\times\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(x+\frac{3}{4}=\frac{23}{6}\div\frac{7}{4}\)
\(x\times\frac{3}{4}=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{3}{4}\)
\(x=\frac{121}{84}\)
\(\)
Bài 1.
a, thực hiện phép tính
2và 3/4 × 1/2 - 1/2 × 3/7 + 1/3
b, Tìm x biết
a, 435 - ( X + 16 ) = 425 : 17
b, ( X + 3/4 ) × 7/4 = 5 - 7/6
Giải giúp mình nhé mình cầu xin các bạn 🙏🙏🙏
\(2\frac{3}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{8}-\frac{3}{14}+\frac{1}{3}\)
\(=\frac{251}{168}\)
Bài 1 : a, thực hiện phép tính :
\(2\frac{3}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)
\(=\frac{1}{2}×\left(\frac{11}{4}-\frac{3}{7}\right)+\frac{1}{3}\)
\(=\frac{1}{2}×\frac{65}{28}+\frac{1}{3}\)
\(=\frac{65}{56}+\frac{1}{3}\)
\(=\frac{251}{168}\)
b , Tìm x biết :
a, 435- ( x + 16 ) = 425 : 17
435 - ( x + 16 ) = 25
x + 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
Vậy x = 394
b, ( x + 3/4 ) × 7/4 = 5 - 7/6
( x + 3/4 ) × 7/4 = 23/6
x + 3/4 = 23/6 : 7/4
x + 3/4 = 23/6 × 4/7
x + 3/4 = 46/21
x = 46/21 - 3/4
x = 121/84
Vậy x = 121/84
a/ 4^(x-3)+4^(x-5)=68
b/ 1/3-1/3:|2x-1|=-2/3
c/ 2|x-1|-3|x+5|=0
d/( √x +7)^10 =1024*125^2*25^2
a: \(\Leftrightarrow4^{x-5}\cdot17=68\)
=>4^x-5=4
=>x-5=1
=>x=6
b: \(\Leftrightarrow\dfrac{1}{3}:\left|2x-1\right|=\dfrac{1}{3}+\dfrac{2}{3}=1\)
=>|2x-1|=1/3
=>2x-1=1/3 hoặc 2x-1=-1/3
=>x=2/3 hoặc x=1/3
c: =>|2x-2|=|3x+15|
=>3x+15=2x-2 hoặc 3x+15=-2x+2
=>x=-17 hoặc x=-13/5
a. 2/3x-1/2=1/10
b. 39/7:x=13
c. (14/5x-50):2/3=51
d. (x+1/2)(2/3-2x)=0
e. 2/3x-1/2x=5/12
g. (x.44/7+3/7)11/5-3/7=-2
h. x.13/4+(-7/6)x-5/3=5/12
i.93/17:x+(-4/17):x+22/7:52/3=4/11
j. 17/2-|2x-3/4|=-7/4
k. (x+1/5)^2+17/25=26/25
l. -32/27-(3x-7/9)^3=-24/27
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
1: Tính nhanh :
a) 437 + 541 + 463 - 341
b) 562 + 389 - 462 + 611
c) ( 417 + 536 ) + ( 583 - 436 )
d) 325 x 6 + 6 x 560 + 115 x 6
e)133 : 7 + 154 : 7 + 413 : 7
f) 2 x 13 x 5 x 4 x 17 x 25
g) 125 x 36 x 8
h) 28 x 14 x 25
i) 125 x 31 x 72
k) 417 x 28 - 28 x 317 + 5200
l) 3 x 78 x 8 + 6 x 22 x 4 - 24 x 10
m) 3 x 128 x 12 - 4 x 28 x 9 + 18 x 100 x 2
n) 50 x 76 + 25 x 18 - 14 x 125
a)437+541+463-341
=(437+463)+(541-341)
=900+200
=1100
bài 19: tìm x
c) ( 34 - 2x ) . ( 2x - 6 ) = 0
d) ( 2019 - x ) . ( 3x - 12 ) 0
e) 57 . ( 9x - 27 ) = 0
f) 25 + ( 15 - x ) = 30
g) 43 - ( 24 - x ) = 20
h) 2 . ( x - 5 ) - 17 = 25
i) 3 . ( x + 7 ) - 15 = 27
j) 15 + 4 . ( x - 2 ) = 95
k) 20 - ( x + 14 ) = 5
l) 14 + 3 . ( 5 - x ) = 27
nhanh nha, mik tick cho, ccau trình bày dễ hiểu, ko cần ''hoặc''
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6-0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
f) \(25+\left(15-x\right)=30\)
\(\Rightarrow25+15-x=30\)
\(\Rightarrow40-x=30\)
\(\Rightarrow x=40-30\)
\(\Rightarrow x=10\)
g) \(43-\left(24-x\right)=20\)
\(\Rightarrow43-24+x=20\)
\(\Rightarrow19+x=20\)
\(\Rightarrow x=20-19\)
\(\Rightarrow x=1\)
h) \(2\left(x-5\right)-17=25\)
\(\Rightarrow2\left(x-5\right)=17+25\)
\(\Rightarrow x-5=21\)
\(\Rightarrow x=21+5\)
\(\Rightarrow x=26\)
i) \(3\left(x+7\right)-15=27\)
\(\Rightarrow3\left(x+7\right)=27+15\)
\(\Rightarrow x+7=14\)
\(\Rightarrow x=14-7\)
\(\Rightarrow x=7\)
j) \(15+4\left(x-2\right)=95\)
\(\Rightarrow4\left(x-2\right)=95-15\)
\(\Rightarrow4\left(x-2\right)=80\)
\(\Rightarrow x-2=20\)
\(\Rightarrow x=20+2\)
\(\Rightarrow x=22\)
k) \(20-\left(x+14\right)=5\)
\(\Rightarrow x+14=20-5\)
\(\Rightarrow x+14=15\)
\(\Rightarrow x=15-14\)
\(\Rightarrow x=1\)
l) \(14+3\left(5-x\right)=27\)
\(\Rightarrow3\left(5-x\right)=27-14\)
\(\Rightarrow3\left(5-x\right)=13\)
\(\Rightarrow5-x=\dfrac{13}{3}\)
\(\Rightarrow x=5-\dfrac{13}{3}\)
\(\Rightarrow x=\dfrac{2}{3}\)
a) 5(x-2)(x+3)=1
b) 7(x-2024)2 = 23- y2
c) |x2+ 2x| + |y2- 9|= 0
d) 2x+ 2x+1+2x+2+2x+3=120
e) ( x- 7 )x+1- (x - 7)x+11=0
f) 25 - y2= 8(x 2012)2
a: \(5^{\left(x-2\right)\left(x+3\right)}=1\)
=>\(\left(x-2\right)\left(x+3\right)=0\)
=>\(\left[{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
c: \(\left|x^2+2x\right|+\left|y^2-9\right|=0\)
mà \(\left\{{}\begin{matrix}\left|x^2+2x\right|>=0\forall x\\\left|y^2-9\right|>=0\forall y\end{matrix}\right.\)
nên \(\left\{{}\begin{matrix}x^2+2x=0\\y^2-9=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\left(x+2\right)=0\\\left(y-3\right)\left(y+3\right)=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x\in\left\{0;-2\right\}\\y\in\left\{3;-3\right\}\end{matrix}\right.\)
d: \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=120\)
=>\(2^x\left(1+2+2^2+2^3\right)=120\)
=>\(2^x\cdot15=120\)
=>\(2^x=8\)
=>x=3
e: \(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
=>\(\left(x-7\right)^{x+11}-\left(x-7\right)^{x+1}=0\)
=>\(\left(x-7\right)^{x+1}\left[\left(x-7\right)^{10}-1\right]=0\)
=>\(\left[{}\begin{matrix}x-7=0\\x-7=1\\x-7=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\\x=6\end{matrix}\right.\)