a: \(\dfrac{7}{4}-\dfrac{11}{8}+\dfrac{1}{2}\)

\(=\dfrac{14-11+4}{8}\)

\(=\dfrac{7}{8}\)

b: \(\dfrac{3}{16}+\dfrac{7}{30}\cdot\dfrac{40}{36}\)

\(=\dfrac{3}{16}+\dfrac{7}{36}\cdot\dfrac{40}{30}\)

\(=\dfrac{3}{16}+\dfrac{7}{36}\cdot\dfrac{4}{3}\)

\(=\dfrac{3}{16}+\dfrac{7}{27}=\dfrac{81+112}{432}=\dfrac{193}{432}\)

c: \(\left(\dfrac{9}{2}-\dfrac{15}{4}\right):\dfrac{21}{12}\)

\(=\left(\dfrac{18}{4}-\dfrac{15}{4}\right):\dfrac{7}{4}\)

\(=\dfrac{3}{4}\cdot\dfrac{4}{7}=\dfrac{3}{7}\)

a, = 3.25 + 15.4 - 16 : 2 = 75 + 60 - 8 = 135 - 8 = 127

a: =75+60-8=127

\(a,=x^3+3x^2+3x+1-x^3+4x^2-4x-1\\ =7x^2-x\\ b,=\left[\left(x+1\right)\left(x^2-x+1\right)\right]\left[\left(x-1\right)\left(x^2+x+1\right)\right]\\ =\left(x^3+1\right)\left(x^3-1\right)=x^6-1\\ c,=8a^2+12a^2+6a+1\\ d,=27a^3-54a^2b+36ab^2-8b^3\)

giúp mình nha mình cần gấp, cảm ơn mọi người trước

a) (2x+3)²

=4x^2+12x+9

b) (x-2/5)³

=x^3-1.2x^2+0.48x-0.064

c) (4x²+1)³

=(4x^2)^3+12x^4+12x^2+1

\(\left(5x\right)^2=\left(\dfrac{6}{7}\right)^2\)

⇒5x=6/7 =>x=6/35

5x=-6/7   =>x=-6/36

\(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{4}{9}\right)^3\)

=>x-2/9=4/9

=>x=6/9

a \(\dfrac{53}{84}\)

b \(\dfrac{20}{63}\)

c \(\dfrac{1}{60}\)

a: \(\dfrac{2}{3}+\dfrac{5}{7}-\dfrac{3}{4}=\dfrac{56}{84}+\dfrac{60}{84}-\dfrac{63}{84}=\dfrac{53}{84}\)

b: \(=\dfrac{3}{7}-\dfrac{1}{9}=\dfrac{27}{63}-\dfrac{7}{63}=\dfrac{20}{63}\)

c: \(=\dfrac{2}{5}\cdot\dfrac{1}{8}\cdot\dfrac{1}{3}=\dfrac{2}{8}\cdot\dfrac{1}{15}=\dfrac{1}{60}\)

a) 2/3 + 5/2 - 3/4

= 19/6 - 3/4

= 29/12

b) 2/5 x 1/2 : 1/3

= 1/5 x 3

= 3/5 

2/9 : 2/9 x 1/2

= 1 x 1/2 

= 1/2