Tìm x :
a)\(\dfrac{49}{81}\)=\(\dfrac{7^x}{9}\) b)\(\dfrac{-64}{343}\)=(\(\dfrac{-4^x}{7}\))
c)\(\dfrac{9}{144}\)=\(\dfrac{3^x}{12}\) d)\(\dfrac{-1}{32}\)=(\(\dfrac{-1^x}{2}\))
Giúp với ạ bài khó quá . Em cảm ơn ạ !
Tìm x, biết:
a) \(\left(5x+1\right)^2=\dfrac{36}{49}\)
b) \(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
c) \(2020^{\left(x-2\right).\left(2x+3\right)}=1\)
d) \(\left(x+1\right)^{x+10}=\left(x+1\right)^{x+4}\) với \(x\in Z\)
e) \(\dfrac{3}{4}\sqrt{x}-\dfrac{1}{2}=\dfrac{1}{3}\)
giúp mk vs :(( ( tìm x )
\(\dfrac{-4}{x}=\dfrac{x}{-49}\); \(\dfrac{3.5}{x-3}=\dfrac{5}{3}\)
(2x + 1) : 2 = 12 : 3 ; ( 2x - 14 ): 3= 12 :9
giúp mk nhaa vội lém á :((
Bài 1 tính .
a) \(\dfrac{\left(-3\right)^{10}.15^5}{25^3.\left(-9\right)^7}\)
b) 2\(^3\) +3 . (\(\dfrac{1}{9}\))\(^0\) -2\(^{-2}\) . 4 +[ (-2)\(^2\) : \(\dfrac{1}{2}\) ] . 8
Giúp mình với mình cảm ơn
Bài 1:
a)\(\left|x-2\right|\)+\(\left|1-\dfrac{x}{2}\right|\)=0 b)\(\left(x-\dfrac{1}{3}\right)^3\)=\(\dfrac{-8}{27}\)
c)\(\dfrac{x^2}{6}\)=\(\dfrac{24}{25}\) c)\(\dfrac{x-1}{x+5}\)=\(\dfrac{6}{7}\)
Giúp mik làm bài này với ạ mik đang cần gấp tối nay mik phải nộp rồi mong mn giúp đỡ mik. Mik cảm ơn mn
Tìm x biết
1, \(\dfrac{-1}{4}-\dfrac{3}{4}:x=-\dfrac{11}{36}\)
2,\(\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{3}{7}\)
1/Rút gọn biểu thức
a/ B=\(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
b/C= \(\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
c/D=\(\dfrac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
2/tìm x biết
a/9x+1-5.32x= 324
b/\(\dfrac{1}{3}\).3x=7.32.92-2.3x
c/\(\dfrac{1}{5}\).2x+\(\dfrac{1}{3}\).2x+1=\(\dfrac{1}{5}\).27+\(\dfrac{1}{3}\).28
d/ 3x+1+2x.3x- 18x - 27=0
Giups mik nhanh với, mai mik đi hc rùi , bạn nào làm đc mik tick cho
Tìm x biết:
\(7^{2+x}+2\times7^{x-1}=345\)
\(81^{-2\times x}\times27^x=9^5\)
\(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-1}=\dfrac{1}{36}\)
\(\dfrac{25}{5^x}=\dfrac{1}{125}\)
\(\dfrac{\left(-7\right)^{2\times x-1}}{49}=-343\)
\(\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}=\dfrac{x+1}{13}+\dfrac{x+1}{14}\)
\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
Mn giúp mk làm bài này nhoa !!!