Bn thấy cái nào cùng mẫu hoặc dễ quy đồng thì nhóm vào 1 nhóm nha!

Xin đừng ném đá, mk chỉ nói đúng

Hội con 🐄 chúc bạn học tốt!!!

Trả lời

Bò Vinamilk 3 không (Hội con bò ) ơi

Mk thấy cách làm của bạn có j đó không đúng.

Vì mấy bài này có cả phép cộng và phép nhân nên đâu có nhóm lại được.

a) 

45/23 . 7/25 + 1/5 . 7/23

= 45 . 7/23 . 25 + 1/5 . 7/23

= 45/25 . 7/23 + 1/5 . 7/23

= 7/23 . ( 45/25 + 1/5)

= 7/23 . ( 9/5 + 1/5 )

= 7/23 . 10/5

= 7/23 . 2

= 14/23

 [ Những câu khác làm tương tự ]

    \(\dfrac{7}{19}\).\(\dfrac{5}{19}\) + \(\dfrac{7}{19}\).\(\dfrac{8}{13}\) + \(\dfrac{12}{19}\)

=   \(\dfrac{7}{19}\).( \(\dfrac{5}{13}+\dfrac{8}{13}\)) + \(\dfrac{12}{19}\)

= \(\dfrac{7}{19}\) . \(\dfrac{13}{13}\) + \(\dfrac{12}{19}\)

= \(\dfrac{7}{19}\) + \(\dfrac{12}{19}\)

= \(\dfrac{19}{19}\)

= 1 

   719197​.519195​ + 719197​.813138​ + 12191912​

=   719197​.( 513+813135​+138​) + 12191912​

= 719197​ . 13131313​ + 12191912​

= 719197​ + 12191912​

= 19191919​

= 1 

= 35/13.19 + 56/13.19 + 12.13/13.19

= 35/13.19 + 56/13.19 + 156/13.19

= 35/a + 56/a + 156/a

a = 13.19

a = 13(20 - 1)

a = 13.20 - 13.1

a = 260 - 13

a = 247

=> 35/a + 56/a + 156/a = 35/247 + 56/247 + 156/247 = 247/247 = 1

Đây nhé bạn :D

3 * 7 /9-7 /13 * 5 /19-7 /19 * 8 /13  =    112/57

\(\dfrac{7}{13}\cdot\dfrac{5}{19}+\dfrac{7}{19}\cdot\dfrac{8}{13}-3\cdot\dfrac{7}{19}\\ =\dfrac{7}{19}\cdot\dfrac{5}{13}+\dfrac{7}{19}\cdot\dfrac{8}{13}-3\cdot\dfrac{7}{19}\\ =\dfrac{7}{19}\cdot\left(\dfrac{5}{13}+\dfrac{8}{13}-3\right)=\dfrac{7}{19}\cdot\left(-2\right)=-\dfrac{14}{19}\)

Ta có: \(\dfrac{7}{13}\cdot\dfrac{5}{19}+\dfrac{7}{19}\cdot\dfrac{8}{13}-3\cdot\dfrac{7}{19}\)

\(=\dfrac{7}{19}\cdot\dfrac{5}{13}+\dfrac{7}{19}\cdot\dfrac{8}{13}-3\cdot\dfrac{7}{19}\)

\(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-3\right)\)

\(=\dfrac{7}{19}\cdot\left(-2\right)\)

\(=\dfrac{-14}{19}\)

\(\dfrac{7}{13}.\dfrac{5}{19}+\dfrac{7}{19}.\dfrac{8}{13}-3.\dfrac{7}{19}=\dfrac{35}{247}+\dfrac{56}{247}-\dfrac{21}{19}=\dfrac{91}{247}-\dfrac{21}{19}=\dfrac{14}{-19}\)

Ta có: \(\dfrac{7}{13}\cdot\dfrac{5}{9}+\dfrac{7}{19}\cdot\dfrac{8}{13}-3\cdot\dfrac{7}{19}\)

\(=\dfrac{7}{13}\cdot\dfrac{5}{9}+\dfrac{7}{13}\cdot\dfrac{8}{19}-3\cdot\dfrac{7}{19}\)

\(=\dfrac{7}{13}\left(\dfrac{5}{9}+\dfrac{8}{19}\right)-3\cdot\dfrac{7}{19}\)

\(=\dfrac{7}{13}\cdot\dfrac{167}{171}-\dfrac{51}{19}\)

\(=\dfrac{-4798}{2223}\)

a: \(\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)

\(=\left(-\dfrac{5}{6}+\dfrac{2}{5}\right)\cdot\dfrac{8}{3}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right)\cdot\dfrac{8}{3}\)

\(=\dfrac{8}{3}\left(-\dfrac{5}{6}+\dfrac{2}{5}+\dfrac{4}{5}-\dfrac{11}{30}\right)\)

\(=\dfrac{8}{3}\cdot\dfrac{-25+36-11}{30}\)

=0

b: \(\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)

\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\cdot\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right)\cdot\dfrac{7}{3}\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)

\(=\dfrac{7}{3}\cdot0=0\)

c: \(\dfrac{-13}{18}\cdot\dfrac{5}{8}+\dfrac{-5}{18}\cdot\dfrac{2}{9}+\dfrac{-13}{18}\cdot\dfrac{3}{8}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\)

\(=\left(-\dfrac{13}{18}\cdot\dfrac{5}{8}+\dfrac{-13}{18}\cdot\dfrac{3}{8}\right)+\left(-\dfrac{5}{18}\cdot\dfrac{2}{9}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\right)\)

\(=-\dfrac{13}{18}\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{-5}{18}\left(\dfrac{2}{9}+\dfrac{7}{9}\right)\)

\(=-\dfrac{13}{18}-\dfrac{5}{18}=-\dfrac{18}{18}=-1\)

d: Sửa đề: \(\dfrac{-11}{19}\cdot\dfrac{4}{9}+\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-11}{19}\cdot\dfrac{5}{9}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\)

\(=\left(-\dfrac{11}{19}\cdot\dfrac{4}{9}+\dfrac{-11}{19}\cdot\dfrac{5}{9}\right)+\left(\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\right)\)

\(=-\dfrac{11}{19}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\dfrac{-8}{19}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)

\(=-\dfrac{11}{19}-\dfrac{8}{19}=-\dfrac{19}{19}=-1\)

\(a.\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)

\(=\left(-\dfrac{13}{30}\right):\dfrac{3}{8}+\dfrac{13}{30}:\dfrac{3}{8}\)

\(=\left[\left(-\dfrac{13}{30}+\dfrac{13}{30}\right)\right]:\dfrac{3}{8}\)

\(=0:\dfrac{3}{8}=0\)

\(b.\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+-\dfrac{1}{4}\right):\dfrac{3}{7}\)

\(=\left(-\dfrac{7}{20}\right):\dfrac{3}{7}+\dfrac{7}{20}:\dfrac{3}{7}\)

\(=\left[\left(-\dfrac{7}{20}+\dfrac{7}{20}\right)\right]:\dfrac{3}{7}=0:\dfrac{3}{7}=0\)

\(c.-\dfrac{13}{18}.\dfrac{5}{8}+-\dfrac{5}{18}.\dfrac{2}{9}+-\dfrac{13}{18}.\dfrac{3}{8}+-\dfrac{5}{18}.\dfrac{7}{9}\)

\(=\left(\dfrac{5}{8}+\dfrac{3}{8}\right).-\dfrac{13}{18}+\left(\dfrac{2}{9}+\dfrac{7}{9}\right).-\dfrac{5}{18}\)

\(=1.-\dfrac{13}{18}+1.-\dfrac{5}{18}=-\dfrac{13}{18}+-\dfrac{5}{18}=-1\)

\(d.-\dfrac{11}{19}.\dfrac{4}{9}+\dfrac{-8}{19}.\dfrac{3}{7}+-\dfrac{11}{19}.\dfrac{5}{9}+-\dfrac{9}{19}.\dfrac{4}{7}\)

\(=\left(\dfrac{4}{9}+\dfrac{5}{9}\right).-\dfrac{11}{19}+-\dfrac{24}{133}+-\dfrac{36}{133}\)

\(=-\dfrac{11}{19}+-\dfrac{60}{133}=-\dfrac{137}{133}\)

2

3

8/27+4/15+19/27+11/15

=(8/27+19/27)+(4/15+11/5)

=27/27+15/15

=1+1

=2

12/13 + 2/7 + 8/13 + 6/13 + 5/7

= ( 2/7 + 5/7 ) + ( 12/13 + 8/13 + 6/13 )

= 1 + 2

= 3

2

3

\(\frac{7}{13}.\frac{5}{19}+\frac{7}{19}.\frac{8}{13}-3\frac{7}{19}\)

\(=\frac{7}{19}.\frac{5}{13}+\frac{7}{19}.\frac{8}{13}-3-\frac{7}{19}\)

\(=\frac{7}{19}\left(\frac{5}{13}+\frac{8}{13}\right)-3-\frac{7}{19}\)

\(=\frac{7}{19}-3-\frac{7}{19}\)

\(=-3\)

\(\frac{7}{13}.\frac{5}{19}+\frac{7}{19}.\frac{8}{13}-3\frac{7}{19}\)  

=\(\frac{7}{19}.\frac{5}{13}+\frac{7}{19}.\frac{8}{13}-3-\frac{7}{19}\)

= \(\frac{7}{19}.\left(\frac{5}{13}+\frac{8}{13}\right)-3-\frac{7}{19}\)

= \(\frac{7}{19}-3-\frac{7}{19}\) =  \(-3\)