d: =>6x^2+2x-3x-1+9x-6x^2+12-8x=5

=>13=5(loại)

e: =>0,6x^2-0,3x-0,6x^2-0,39x=0,38

=>-0,69x=0,38

=>x=-38/69

a: =>3x=-9

hay x=-3

b: =>3x=2

hay x=2/3

c: =>2x=4

hay x=2

d: =>-2x=-6

hay x=3

e: =>0,5x=1

hay x=2

f: =>0,6x=3,6

hay x=6

g: =>2/3x=4/3

hay x=2

h: =>-3x+3=6x+2

=>-9x=-1

hay x=1/9

i: =>4x-2x=1+3

=>2x=4

hay x=2

\(A.3x+9=0\)

\(\Leftrightarrow3x=-9\)

\(\Leftrightarrow x=-2\)

\(B.3x-2=0\)

\(\Leftrightarrow3x=2\)

\(\Leftrightarrow x=\dfrac{2}{3}\)

\(C.4-2x=0\)

\(\Leftrightarrow4=2x\)

\(\Leftrightarrow x=2\)

\(D.-2x+6=0\)

\(\Leftrightarrow6=2x\)

\(\Leftrightarrow x=3\)

\(E.0,5x-1=0\)

\(\Leftrightarrow0,5x=1\)

\(\Leftrightarrow x=2\)

\(F.3,6-0,6x=0\)

\(\Leftrightarrow3,6=0,6x\)

\(\Leftrightarrow x=6\)

\(G.\dfrac{2}{3}x-1=\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{4}{3}\)

\(\Leftrightarrow x=2\)

\(H.-\dfrac{1}{3}x+1=\dfrac{2}{3}x-3\)

\(\Leftrightarrow4=x\)

\(\Leftrightarrow x=4\)

\(I.4x-3=2x+1\)

\(\Leftrightarrow2x=4\)

\(\Leftrightarrow x=2\)

mình cần khá gấp nhe

\(\left(5x-1\right)\left(\frac{2x-1}{3}\right)=0\)

\(\Leftrightarrow\left(\frac{\left(5x-1\right)\left(2x-1\right)}{3}\right)=0\)

\(\Leftrightarrow\left(5x-1\right)\left(2x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5x-1=0\\2x-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{2}\end{cases}}\)

Vậy \(x=\frac{1}{5}\)hoặc\(x=\frac{1}{2}\)

b) \(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)

\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}=\frac{-2}{3}\)

\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right)=\frac{-8}{9}\)

\(\Leftrightarrow-0,6x=\frac{-7}{18}\)

\(\Rightarrow x=\frac{35}{54}\)

a) 6x(5x + 3) + 3x(1 – 10x) = 7  

⇒ 30x²+18x+3x-30x²=7

⇒21x=7

⇒x=\(\dfrac{7}{21}\)

⇒x= \(\dfrac{1}{3}\)

b) (3x – 3)(5 – 21x) + (7x + 4)(9x – 5) = 44

⇒15x-63x²-15+63x + 63x²-35x+36x-20=44

⇒79x-35=44

⇒79x=44+35

⇒79x=79

⇒x=1

d) 5x(12x + 7) – 3x(20x – 5) = - 100

⇒60x²+35x-60x²+15=-100

⇒35x+15=-100

⇒35x=-100-15

⇒35x=-115

⇒x=\(\dfrac{-115}{35}\)

⇒x=\(\dfrac{-23}{7}\)

j) (x + 2).(3 - x) = 0

TH1:  x + 2 = 0

          x = 0 - 2

          x = (-2)

TH2: 3 - x = 0

              x = 3 - 0

              x = 3

⇒ Vậy x = (-2) hoặc x = 3.

m) (x + 5).(x.2 - 4) = 0

TH1: x + 5 = 0

         x = 0 - 5

         x = (-5)

TH2: x.2 - 4 = 0

         x.2 = 0 + 4

         x.2 = 4

         x = 4 : 2

         x = 2

⇒ Vậy x = (-5) hoặc x = 2.

g) 0,3x + 0,6x = 9

x.(0,3 + 0,6) = 9

x. 0,9 = 9

x = 9 : 0,9

x = 10

j) (x + 2)(3 - x) = 0

x + 2 = 0 hoặc 3 - x = 0

*) x + 2 = 0

x = 0 - 2

x = -2

*) 3 - x = 0

x = 3

Vậy x = -2; x = 3

m) (x + 5)(x.2 - 4) = 0

x + 5 = 0 hoặc x.2 - 4 = 0

*) x + 5 = 0

x = 0 - 5

x = -5

*) x.2 - 4 = 0

2x = 0 + 4

2x = 4

x = 4 : 2

x = 2

Vậy x = -5; x = 2

g) 0,3x + 0,6x = 9

0,9x = 9

x = 9 : 0,9

x = 10

Làm giống chị Kiều Vũ Linh nhé

j) (x + 2)(3 - x) = 0

x + 2 = 0 hoặc 3 - x = 0

*) x + 2 = 0

x = 0 - 2

x = -2

*) 3 - x = 0

x = 3

Vậy x = -2; x = 3

m) (x + 5)(x.2 - 4) = 0

x + 5 = 0 hoặc x.2 - 4 = 0

*) x + 5 = 0

x = 0 - 5

x = -5

*) x.2 - 4 = 0

2x = 0 + 4

2x = 4

x = 4 : 2

x = 2

Vậy x = -5; x = 2

g) 0,3x + 0,6x = 9

0,9x = 9

x = 9 : 0,9

x = 10.

a) 5x(12x + 7) - 3x(20x - 5) = -100

<=> 60x² + 35x - 60x² + 15x = -100

<=> 50x = -100

<=> x = -2

b) 0,6x(x - 0,5) - 0,3x(2x + 1,3) = 0,138

<=> 0,6x² - 0,3x - 0,6x² - 0,39x = 0,138

<=> -0,69x = 0,138

<=> x = -0,2

c) 4x(3x - 7) - 6(2x² - 5x + 1) = 12

<=> 12x² - 28x - 12x² + 30x - 6 = 12

<=> 2x - 6 = 12

<=> 2x = 18

<=> x = 9