\(=\left[\dfrac{9-3}{162}\cdot\dfrac{81}{17}+\dfrac{35}{34}\right]:\left(\dfrac{3}{5}+\dfrac{7}{102}\right)\cdot\dfrac{102}{5}+2017\)

\(=\left[\dfrac{6}{2}\cdot\dfrac{1}{17}+\dfrac{35}{34}\right]:\dfrac{341}{510}\cdot\dfrac{102}{5}+2017\)

\(=\dfrac{41}{34}\cdot\dfrac{510}{341}\cdot\dfrac{102}{5}+2017=\dfrac{12546}{341}+2017=\dfrac{700343}{341}\)

\(7^6+7^5-7^4\)

\(=7^4\left(7^2+7-1\right)\)

\(=7^4\cdot55⋮55\)

\(16^5+2^5\)

\(=\left(2^4\right)^5+2^5\)

\(=2^{20}+2^5\)

\(=2^5\left(2^{15}+1\right)\)

\(=2^5\cdot32769⋮33\)

\(81^7-27^9-9^{13}\)

\(=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\)

\(=3^{28}-3^{27}-3^{26}\)

\(=3^{26}\left(3^2-3-1\right)\)

\(=3^{26}\cdot5\)

\(=3^{22}\cdot405⋮405\)

\(a,-81.46-81.55+81\)

\(=81.\left(-46\right)-81.55+81\)

\(=81.\left(-46-55+1\right)\)

\(=81.\left(-100\right)\)

\(=-8100\)

\(b,35.\left(17-5\right)-17.\left(35-5\right)\)

\(=35.17-35.5-17.35+17.5\)

\(=\left(35.17-17.35\right)-\left(35.5-17.5\right)\)

\(=35.\left(17-17\right)-5.\left(35-17\right)\)

\(=35.0-5.18\)

\(=0-90\)

\(=-90\)

Cách 2 : \(35.\left(17-5\right)-17.\left(35-5\right)\)

\(=35.12-17.30\)

\(=420-510\)

\(=-90\)

\(c,-125.6.\left(-8\right).\left(-50\right)\)

\(=\left(-125\right).\left(-8\right).6.\left(-50\right)\)

\(=1000.\left(-300\right)\)

\(=-300000\)

a,=16.(64+17)+81.84
   =16.81+81.84
   =81(16+84)
   =81.100=8100
b,=32.19+32
   =32.(19+1)
   =32.20=640
c,=12.19+12.37+44.12
   =12.(19+37+44)
   =12.100=1200
d, Khoảng cách là:
        5-1=4;9-5=4
    Số số hạng là:
        (81-1):4+1=21(số)
    Tổng dãy số là:
        (81+1).21:2=861

a

\(\text{=16.(64+17)+81.84}\)
\(\text{=16.81+81.84}\)
\(\text{ =81.(16+84)}\)
 \(\text{=81.100=8100}\)

b

\(\text{=32.19+32}\)
\(\text{ =32.(19+1)}\)
\(\text{ =32.20=640}\)
c

\(\text{=12.19+12.37+44.12}\)
\(\text{ =12.(19+37+44)}\)
\(\text{ =12.100}\)

\(=1200\)

d
Có tất cả số hạng là

\(\text{( 81 - 1 ) : 4 + 1 = 21 (số )}\)

Tổng là

\(\text{( 81 + 1 ) x 21 : 2 = 861}\)

tu hoc moi gioi

a)= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x 0

=0 ( vì 0 nhân với số nào cũng bằng 0)

b)= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 9-9)

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x 0

= 0 ( vì 0 nhân với số nào cũng bằng 0)

c)=( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x 0

=0 ( vì 0 nhân với số nào cũng bằng 0 )

a ) ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x ( 32 x 11 - 3200 x 0 , 1 - 32 )

= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x ( 352 - 320 - 32 )

= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x 0

= 0.

b ) ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 1 , 8 x 5 – 0 , 9 x 10 )

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 9 - 9 )

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x 0

= 0

c ) ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x ( 11 x 9 – 900 x 0 , 1 – 9 )

= ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x ( 99 - 90 - 9 )

= ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x 0

= 0.

Hok tốt !

a)32 x 11 -3200x 0,1 -32

=32x11-32x100x0,1-32

=32x(11-10-1)=32x0=0

nên(81,6x27,3-17,3x81,6)x(32x11-3200x0,1-32)

=(81,6x27,3-17,3x81,6)x0

=0

b)1,8x5 -0,9x10=1,8x5-0,9x2x5

=1,8x5-1,8x5

=0

nên (13,75-0,48 x 5)x(42,75:3+2,9)x(1,8x5-0,9x10)=0

c)(792,81x0,25+792,81x0,75)x(11x9-900x0,1-9)

=792,81x(0,25+0,75)x(99-90-9)

=792,81x1x0

=0