Hướng dẫn giải:

a.

17 x 543 + 83 x 543

= (17 + 83) x 543

= 100 x 543

= 54300

b.

318 x 963 + 682 x 963

= (318 + 682) x 963

= 1000 x 963

= 963000

a)17x543+83x543

=(17+83)x543

=100x543

=54300

b)318x963+682x963

=(318+682)x963

=1000x963

=963000

\(2\dfrac{1}{547}.\dfrac{3}{211}-\dfrac{546}{547}.\dfrac{1}{211}-\dfrac{4}{547.211}\)

\(=\left(2+\dfrac{1}{547}\right).3.\dfrac{1}{211}-\left(1-\dfrac{1}{547}\right).\dfrac{1}{211}-4.\dfrac{1}{547}.\dfrac{1}{211}\)

Đặt \(a=\dfrac{1}{547};b=\dfrac{1}{211}\)

Thay \(a=\dfrac{1}{547};b=\dfrac{1}{211}\) vào biểu thức trên , ta được :

\(\left(2+a\right).3b-\left(1-a\right)b-4ab\)

\(=6b+3ab-b+ab-4ab\)

\(=5b\)

\(=5.\dfrac{1}{211}\)

\(=\dfrac{5}{211}\)

Vậy g/t biểu thức trên là : \(\dfrac{5}{211}\)

a: \(M=\dfrac{631}{315}\cdot\dfrac{1}{651}-\dfrac{1}{105}\cdot\dfrac{2603}{651}-\dfrac{4}{315\cdot651}+\dfrac{4}{105}\)

\(=\dfrac{1}{315\cdot651}\cdot\left(631-4\right)-\dfrac{1}{105}\left(\dfrac{2603}{651}-4\right)\)

\(=\dfrac{1}{105}\cdot\dfrac{1}{1953}\cdot627+\dfrac{1}{105\cdot651}\)

\(=\dfrac{1}{105\cdot651}\left(\dfrac{1}{3}\cdot627+1\right)=\dfrac{1}{105\cdot651}\cdot210=\dfrac{2}{651}\)

b: \(N=\dfrac{1095}{547}\cdot\dfrac{3}{211}-\dfrac{546}{547\cdot211}-\dfrac{4}{547\cdot211}\)

\(=\dfrac{1}{547\cdot211}\left(1095\cdot3-546-4\right)\)

\(=\dfrac{1}{547\cdot211}\cdot2735=\dfrac{5}{211}\)

543 x ( 45 + 35 )

= 543 x 80

= 43440

43440 chắc luôn ihihih

  543x45+543x35

= 543x(45+35)

= 543x80

=43440

a.125-(27-75+73)

= 125 - (27 + 73 - 75)

= 125 - (100 - 75)

=125 - 25

=100

b.314-(21-86+79)

= 314 - (21 + 79 - 86)

= 314 - (100 - 86)

= 314 - 14

= 300

c.728-(211-72+89)

= 728 - (211 + 89 -72)

= 728 - (300 - 72)

= 728 - 28

= 700

d.(547-623)-(547-23)

= 547 - 623 - 547 + 23

= 547 - 547 + 23 - 623

= 0 + -600

= - 600

a)125-(27-75+73)=125-27+75-73=(125+75)-(27+73)=200-100=100.       b)314-(21-86+79)=314-21+86-79=(314+86)-(21+79)=400-100=300.               c) 728-(221-72+89)=(728+72)-(221+89)=800-300=500.             d) (547-623)-(547-23)=547-623-547+23=(547-547)+(23-623)=0+(-600)=-600

(  a x 1 - a x 1 ) : ( a x 1883 + 543 )

= ( a - a ) : ( a x 1883 + 543 )

= 0 : a x 1883 + 543

= 0 x 1883 +  543

= 0 + 543

= 543.

\(\left(a\times1-a:1\right):\left(a\times1883+543\right)\\ =\left(a-a\right):\left(a\times1883+543\right)\\ =0:\left(a\times1883+543\right)\\ =0\)

\(543x46+54x543-14300\)

\(=543x\left(46+54\right)-14300\)

\(=543x100-14300\)

\(=54300-14300\)

\(=40000\)

Học Tốt !

\(=543\cdot\left(46+54\right)-14300=543\cdot100-14300\)

\(=54300-14300=40000\)

(129-a).543=51042

129-a=51042:543

129-a=94

   a=129-94

   a=35

        học tốt nha bn

(129-a) x 543 = 51042

=> 129 - a      =  51042 :543

=> 129 - a      = 94

=> a                = 129 - 94

=> a                = 35

\(\left(129-a\right)\times543=51042\)

\(\Leftrightarrow129-a=94\)

\(\Leftrightarrow a=35\)