A= 5.4.(-3)-3(4+(-3))

A= -60-3.1

A=-63

A=5ab-3(a+b) với a=4; b=-3

A=5.4.(-3)-3.[4+(-3)]

A=5.4.(-3)-3.1

A=20.(-3)-3

A=-60-3

A=-63

a)     A = 500 + x = 500 + 8075 = 8575

        B = x - 500 = 8075 - 500 = 7575

b)     A + B = 8575 + 7575 = 16150

a) theo đề ta có : A= 500+ 8075  ; B = 8075 - 500

=> A = 500 + 8075 = 8575 ; B = 8075-500 = 7575

b) Ta đã có : A = 8587 và B= 7575 

=> A + B = 8587 + 7575 = 16 162 

Đáp số = 16 162

a, thay x= -28

-> (-12)-(-28)=16

b, thay a=12, b=-48 

->12- (-48)= 60

a) (- 12) – x = (- 12) – -  28 = 16

b) a – b = 12 – (-48) = 12 + 48 = 60

a) (-12)-x=-12-(-28)=12+28=40

b) a-b=12-(-48)=12+48=60

Với a = 6 thì A = 2874 + 178 x 6 = 2874 + 1068

\(a,A=\left(\cos^220^0+\cos^270^0\right)+\left(\cos^240^0+\cos^250^0\right)\\ A=\left(\cos^220^0+\sin^220^0\right)+\left(\cos^240^0+\sin^240^0\right)=1+1=2\\ b,B=\left(\cos^2\alpha\right)^3+\left(\sin^2\alpha\right)^3+3\sin^2\alpha\cdot\cos^2\alpha\cdot\left(\sin^2\alpha+\cos^2\alpha\right)\\ B=\left(\sin^2\alpha+\cos^2\alpha\right)^3=1^3=1\)

Ta có:

\(4a^2+b^2=5ab\Leftrightarrow4a^2+b^2-4ab-ab=0\)

\(\Leftrightarrow4a\left(a-b\right)-b\left(a-b\right)=0\)

\(\Leftrightarrow\left(a-b\right)\left(4a-b\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}a-b=0\\4a-b=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}a=b\left(ktm\right)\\4a=b\left(tm\right)\end{matrix}\right.\)

\(\Rightarrow4a=b\)

\(\Rightarrow\dfrac{5ab}{3a^2+2b^2}=\dfrac{5a.4a}{3a^2+2.\left(4a\right)^2}=\dfrac{20a^2}{3a^2+32a^2}\)

\(=\dfrac{20a^2}{35a^2}=\dfrac{4}{7}\)

\(4a^2+b^2=5ab\)

\(\Rightarrow4a\left(a-b\right)-b\left(a-b\right)=0\)

\(\Rightarrow\left(a-b\right)\left(4a-b\right)=0\)

\(\Rightarrow b=4a\left(do.a\ne b\right)\)

\(\dfrac{5ab}{3a^2+2b^2}=\dfrac{20a^2}{3a^2+32a^2}=\dfrac{4}{7}\)