1) Cho mach dien nhu hinh 2.7:
R1 = R2 = 4Ω; R3 = 6Ω; R4 = 12Ω; R5 = 0,6Ω; UAB = 12V; RA ≈ 0
a) Tinh RAB
b) Tim I qua cac dien tro, va so chi cua Ampe ke
1) Cho mach dien nhu hinh 2.5
Cho biet UAB = 20V, R1 = 2Ω; R2 = 1Ω; R3 = 6Ω; R4 = 4Ω
a) Tinh cuong do dong dien qua cac dien tro khi K mo
b) Tinh cuong do dong dien qua cac dien tro khi K dong va I qua K
1) Cho mach dien nhu hinh 2.6: UAB= 18V. I2 = 2A
a) Tim R1: R2 = 6Ω; R3 = 3Ω
b) Tim R3: R1 = 3Ω; R2 = 1Ω
c) Tim R2: R1 = 5Ω; R3 = 3Ω
cho mach dien nhu hinh ve hdt hai dau doan mach U= 84V Biet R1 = 2 R2 va R3 = 10om so chi cua ampe ke A la 6 ampe . Tinh dong dien qua cac dien tro R1 r2 va gia tri R1 R2
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1) Cho mach dien nhu hinh 2.6: UAB = 18V, I2 = 2A
a) Tim R2: R1 = 5Ω, R3 = 3Ω
1) Cho mach nhu hinh ve, trong do bo nguon co n pin giong nhau mac noi tiep, moi pin co ξ = 1,5V r = 0,5Ω. R1 va R2 la 2 den lan luot co ghi (1,2V - 0,72W) va (1,2V - 0,48W); R3 = 9Ω, R4 = 4Ω, R5 la binh dien phan dung dung dich AgNO3 co cuc duong tan. Biet rang cac den sang binh thuong. Tinh:
a) So pin cua bo nguon
b) Khoi luong Ag giai phong o dien cuc am cua binh dien phan sau thoi gian 32 phut 10 giay
1) Cho mach dien nhu hinh ve:
Moi nguon co e = 6V, r = 1Ω, R1 = 2Ω, R2 = R3 = 6Ω . Tinh:
a) eb, rb
b) U, I qua moi R
Cho mach dien nhu hinh ve , biet R1=R2=R3=R4=R5=5 OM, R6=6 OM , U=6 OM . Tinh U4
Cho mach dien nhu hinh ve cho biet R1=1Ω R2=3Ω R3=2 hieu dien the toan mach U=12 V
a. Von ke chi so 0, tinh R4 ?
b. Tinh cuong do dong dien chay qua cac dien tro.?
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Cho mach dien co so do nhu hinh ve trong do cac dien tro R1 = 14Ω , R2 = 14Ω , R3 = 24Ω dong dien di qua R1 co cuong do la I1 = 0,4A
a) Tinh cac cuong do dong dien I2 , I3 tuong ung di qua cac dien tro R2 , R3
b) Tinh cac hieu dien the UAC ; UCB va UAB
a) \(R_1nt(R_2//R_3)\)
\(R_1=\dfrac{U_1}{I_1}\Rightarrow U_1=0,4.14=5,6\left(V\right)\)
\(I_1=I_{AB}=0,4A\)
Có \(R_{AB}=R_1+R_{23}=14+\dfrac{R_2.R_3}{R_2+R_3}=\dfrac{434}{19}\left(\Omega\right)\)
\(\Rightarrow U_1+U_{23}=U_{AB}=R_{AB}.I_{AB}=\dfrac{439}{19}.0,4=\dfrac{868}{95}\left(V\right)\)
\(\Rightarrow U_{23}=\dfrac{868}{95}-5,6=\dfrac{336}{95}\left(V\right)\)
\(\Rightarrow U_2=U_3=\dfrac{336}{95}\left(V\right)\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{24}{95}\left(A\right)\)
\(I_3=\dfrac{U_3}{R_3}=\dfrac{14}{95}\left(V\right)\)
b) \(U_{AB}=\dfrac{868}{95}\left(V\right)\)
\(U_{AC}=I_1.R_1=0,4.14=5,6\left(V\right)\)
\(U_{CB}=I_{23}.R_{23}=0,4.\dfrac{R_2.R_3}{R_2+R_3}=\dfrac{336}{95}\left(V\right)\)
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