a ) (2,8x - 32 ) : 2/3 = -90 

<=> 2,8x -32 = -60

<=> 2,8x = -28

<=> x = -10 

b ) 4/5 + 5/7 :x =1/6

<=> 5/7:x = -19/30

<=> x = -150/133

a)\(\left(2,8x-32\right):\frac{2}{3}=-90\)

\(2,8x-32=-90\cdot\frac{2}{3}\)

\(2,8x-32=-60\)

\(2,8x=-60+32\)

\(2,8x=-28\)

\(x=-28:2,8\)

\(x=-10\)

Vậy x = -10

b) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{6}\)

\(\frac{5}{7}:x=\frac{1}{6}-\frac{4}{5}\)

\(\frac{5}{7}:x=\frac{-19}{30}\)

\(x=\frac{5}{7}:\frac{-19}{30}\)

\(x=\frac{-150}{133}\)

Vậy x = -150/133

=))

a) x=-10

b)x=2

a,    x=10

b,   x= 2

A/\(\left(2,8x-32\right):\frac{2}{3}=-90\)

\(\left(\frac{28}{10}x-32\right)=\frac{-90}{1}.\frac{2}{3}\)

\(\left(\frac{14}{5}x-32\right)=\frac{-30}{1}.\frac{2}{1}\)

\(\left(\frac{14}{5}x-32\right)=-60\)

\(\frac{14}{5}x=-60+32\)

\(\frac{14}{5}x=-28\)

\(x=\frac{-28}{1}:\frac{14}{5}\)

\(x=\frac{-28}{1}.\frac{5}{14}\)

\(x=\frac{-2}{1}.\frac{5}{1}=-10\)

B/\(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)

\(\left(\frac{45}{10}-2x\right).\frac{11}{7}=\frac{11}{14}\)

\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}:\frac{11}{7}\)

\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}.\frac{7}{11}\)

\(\left(\frac{9}{2}-2x\right)=\frac{1}{2}.\frac{1}{1}=\frac{1}{2}\)

\(2x=\frac{9}{2}-\frac{1}{2}\)

\(2x=\frac{8}{2}\)

\(x=\frac{8}{2}:\frac{2}{1}=\frac{8}{2}.\frac{1}{2}\)

\(x=\frac{4}{2}.\frac{1}{1}=\frac{4}{2}=2\)

\(\left(2,8x-32\right):\frac{2}{3}=-90\)

\(2,8x-32=-90.\frac{2}{3}=\frac{-90.2}{3}=\frac{-30.2}{1}=-60\)

\(\frac{14}{5}x=-60+32=-28\)

\(x=-28:\frac{14}{5}=-28.\frac{5}{14}=\frac{-28.5}{14}=\frac{-2.5}{1}=-10\)

(2,8X-32):2/3=-90

2,8X -32=-90*2/3

2,8X-32=-60

2,8X=-60+32

2,8X=-28

X=-28/2,8

X=-10

28/10.x-32=-90÷2/3

28/10.x-32=135

28/10.x=135+32

28/10.x=167

x=167÷28/10

x=835/14

Bạn tu rút gọn nha ok 

Học tot

\(a.\left(2,8x-32\right):\frac{2}{3}=-90\)

\(2,8x-32=-90\cdot\frac{2}{3}=-30\cdot\frac{2}{1}\)

\(2,8x-32=-60\)

\(2,8x=-60+32\)

\(2,8x=28\)

\(x=\frac{28}{2,8}=10\). Vậy x=10

\(b.\left(4,5-2x\right)\cdot1\frac{4}{7}=\frac{11}{14}\)

\(4,5-2x=\frac{11}{14}:\frac{11}{7}=\frac{11}{14}\cdot\frac{7}{11}\)

\(4,5-2x=\frac{1}{2}\)

\(2x=\frac{45}{10}-\frac{1}{2}=\frac{9}{2}-\frac{1}{2}=\frac{8}{2}\)

\(2x=4\)

\(x=\frac{4}{2}=2\) . Vậy x=2

Chúc bạn học tốt!^_^

a)(2,8x-32):\(\frac{2}{3}\)=-90

          (2,8x-32)  =(-90).\(\frac{2}{3}\)

          (2,8x-32)  =(-60)

                 2,8x   =(-60)+32

                 2,8x   =(-28)

                     x    =(-28):2,8

                     x    =(-10)

b)(4,5-2x).1\(\frac{4}{7}\)=\(\frac{11}{14}\)

   (4,5-2x).\(\frac{11}{7}\)=\(\frac{11}{14}\)

           (4,5-2x)    =\(\frac{11}{14}\):\(\frac{11}{7}\)

           (4,5-2x)    =\(\frac{1}{2}\)

                  2x    =4,5-\(\frac{1}{2}\)

                  2x    =4

                    x    =4:2

                    x    =2

tính trên máy tính casio được đấy

\(\left(2,8x-32\right)\div\frac{2}{3}=-90\)

\(\Rightarrow2,8x-32=-60\)

\(\Rightarrow2,8x=-28\)

\(\Rightarrow x=-10\)

\(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)

\(\Rightarrow4,5-2x=\frac{1}{2}\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

a: \(=\dfrac{7}{5}\cdot\dfrac{15}{49}-\dfrac{12+10}{15}:\dfrac{11}{5}\)

\(=\dfrac{3}{7}-\dfrac{22}{15}\cdot\dfrac{5}{11}=\dfrac{3}{7}-\dfrac{2}{3}=\dfrac{9-14}{21}=\dfrac{-5}{21}\)

b: =>2,8x-32=-60

=>2,8x=-28

hay x=-10

\(\left(2,8x-32\right):\frac{2}{3}=-90\)

\(\Rightarrow\left(2,8x-32\right)=-90\cdot\frac{2}{3}\)

\(\Rightarrow\left(2,8x-32\right)=-60\)

\(\Rightarrow2,8x=-60+32\)

\(\Rightarrow2,8x=-28\)

\(\Rightarrow x=-10\)