Khi giải phương trình sau: \(\dfrac{2\left(x-4\right)}{3}+\dfrac{4\left(x+3\right)-x+1}{8}=\dfrac{3\left(2x-3\right)}{5}-7\), ta nhận được nghiệm là
\(x=49\).\(x=-49\).\(x=-\dfrac{931}{50}\).\(x=-50\).Hướng dẫn giải:\(\dfrac{2\left(x-4\right)}{3}+\dfrac{4\left(x+3\right)-x+1}{8}=\dfrac{3\left(2x-3\right)}{5}-7\)
\(\Leftrightarrow40.2\left(x-4\right)+15.\left[4\left(x+3\right)-x+1\right]=24.3\left(2x-3\right)-7.120\)
\(\Leftrightarrow80\left(x-4\right)+15.\left(3x+13\right)=72\left(2x-3\right)-840\)
\(\Leftrightarrow80x-320+45x+195=144x-1056\)
\(\Leftrightarrow x\left(80+45-144\right)=-931\)
\(\Leftrightarrow-19x=-931\)
\(\Leftrightarrow x=49\)