\(\dfrac{x^9+x^8+x^7+x^6+....+x+1}{x^2-1}\)
\(=\dfrac{x^8\left(x+1\right)+x^6\left(x+1\right)+....+\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{\left(x+1\right)\left(x^8+x^6+x^4+x^2+1\right)}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^8+x^6+x^4+x^2+1}{x-1}\)