\(n_{O2}=\frac{3,36}{22,4}=0,15\left(mol\right)\)
\(2KClO_3\underrightarrow{^{to}}2KCl+3O_2\left(1\right)\)
\(C+O_2\underrightarrow{^{to}}CO_2\left(2\right)\)
Theo PTHH (1):
\(n_{KCLO3}=\frac{2n_{O2}}{3}=\frac{2.0,15}{3}=0,1\left(mol\right)\)
\(\Rightarrow m_{KClO3}=0,1.122,5=12,25\left(g\right)\)
Theo PTHH (2):
\(n_{CO2}=n_{O2}=0,15\left(mol\right)\)
\(\Rightarrow m_{CO2}=0,15.44=6,6\left(g\right)\)